Before you can read the parent note, you must own every symbol it throws at you. This page builds each one from nothing — plain words, a picture, and why the topic needs it — in an order where each idea leans on the one before. Start at line one; assume you have seen none of the notation.
Look at the figure: the red box is our gate. Three black arrows enter (fan-in = 3). Four black arrows leave, each going to a different downstream box (fan-out = 4). That is the entire vocabulary — the rest of this page explains why each of those arrows costs time.
Digital logic only cares about two heights: full and empty.
Why the topic needs it: the parent note writes V(t)=VDD(1−e−t/RC) — the output climbing from empty toward the full rail. You cannot read that line without knowing VDD is the ceiling.
Every gate input behaves like a small bucket, because it is a transistor gate terminal — a tiny insulated plate that stores charge.
In the figure, the red output wire fills four black buckets (4Cg) plus its own small parasitic bucket Cpar. That is exactly the parent's Step 1:
CL=hCg+Cpar
where h is just the count of buckets (the fan-out).
The link between all three is Ohm's law, the one rule you must trust:
A switched-on transistor is not a perfect wire — it behaves like a fixed resistor R. That single fact is why filling a bucket takes time instead of happening instantly.
This is the parent's mnemonic made concrete: IN series, OUT parallel. Fan-in stacks resistors (series), fan-out stacks capacitors (parallel). Build these two pictures now and the rest of the topic is bookkeeping. See RC Delay Model and Transistor Sizing.
Now combine a resistor R (the transistor) feeding a capacitor C (the load). Open the tap and the bucket does not fill instantly: the fuller it gets, the smaller the pressure difference driving more water in, so it slows as it approaches full. This gives the classic charging curve.
The exact climb is the parent's equation:
V(t)=VDD(1−e−t/RC)
Here e is a fixed number (≈2.718) that shows up whenever something grows or decays proportional to how far it still has to go — exactly our "fills slower as it gets fuller" situation. You do not need to derive e; you need to know it is the fingerprint of this smooth-slowing fill.
Real numbers like "R=8 kΩ, C=3 fF" are clumsy. Engineers strip out the messy units by measuring delay in multiples of a reference — the delay of one plain inverter. This is the logical-effort language (see Logical Effort).
Recall Check you can read the master equation
In d=gf+p, which letter is fan-out? ::: f (electrical effort =Cout/Cin).
Which letter carries the fan-in penalty? ::: g (logical effort — bigger for more series transistors).
What is p physically? ::: Delay from charging the gate's own parasitic capacitance, present even with no load.
Read top to bottom: voltage/current/resistance give Ohm's law; Ohm's law plus capacitance gives the RC clock; the RC clock gives real delay; normalizing gives d=gf+p; series stacking (fan-in) and parallel loading (fan-out) both feed that equation — and that is the topic.