1.1.7Electricity & Charge Basics

Calculate electrical power (P = VI, P = I²R)

1,686 words8 min readdifficulty · medium

WHAT is electrical power?

WHY do we care (Hardware angle): Every component has a power rating. A resistor rated at 0.25 W will literally burn if you push more power through it. Power = heat = the thing that melts your PSU, throttles your CPU, and drains your battery. Knowing PP tells you heat and energy use.


HOW to derive P=VIP = VI from first principles

Start from the definitions — don't memorize, build it.

  1. Voltage = energy per unit charge: V=EQ    E=VQV = \dfrac{E}{Q}\;\Rightarrow\; E = VQ. Why this step? Voltage literally means "joules given to each coulomb," so total energy is voltage times how much charge you moved.

  2. Current = charge per unit time: I=Qt    Q=ItI = \dfrac{Q}{t}\;\Rightarrow\; Q = It. Why this step? Current tells us how fast charge flows, so charge = current × time.

  3. Substitute into power P=EtP = \dfrac{E}{t}: P=Et=VQt=V(It)t=VIP = \frac{E}{t} = \frac{VQ}{t} = \frac{V(It)}{t} = VI Why this step? The tt cancels — energy per second becomes voltage × current directly.


HOW to get P=I2RP = I^2R and P=V2/RP = V^2/R

We already have P=VIP = VI. Now bring in Ohm's law: V=IRV = IR.

Replace VV: P=VI=(IR)I=I2RP = VI = (IR)\,I = I^2R

Replace II (since I=V/RI = V/R): P=VI=VVR=V2RP = VI = V\cdot\frac{V}{R} = \frac{V^2}{R}

Figure — Calculate electrical power (P = VI, P = I²R)

Worked examples


Common mistakes (Steel-man + fix)


Recall Feynman: explain to a 12-year-old

Imagine a water slide. Voltage is how tall the slide is (how much of a drop). Current is how many kids slide down each second. Power is how much total whee! energy happens per second — a tall slide with lots of kids gives loads of power. If the slide is rough (resistance), the kids rub against it and it gets hot — that heat is I2RI^2R, and it grows really fast if more kids pile on, because they slow each other and press harder.


Flashcards

What is the SI unit of power and what does it equal?
The watt (W); 1 W=1 J/s1\ \text{W} = 1\ \text{J/s}.
Derive P=VIP=VI from definitions.
V=E/QV=E/Q and I=Q/tI=Q/t; P=E/t=VQ/t=V(It)/t=VIP=E/t = VQ/t = V(It)/t = VI.
How do you get P=I2RP=I^2R from P=VIP=VI?
Substitute Ohm's law V=IRV=IR: P=(IR)I=I2RP=(IR)I=I^2R.
How do you get P=V2/RP=V^2/R?
Substitute I=V/RI=V/R into P=VIP=VI: P=V(V/R)=V2/RP=V(V/R)=V^2/R.
Which formula if you know current and resistance but not voltage?
P=I2RP=I^2R.
Which formula if you know voltage and resistance but not current?
P=V2/RP=V^2/R.
If current in a fixed resistor doubles, how does power change?
It quadruples (×4), because PI2P\propto I^2.
A 5 V, 2 A charger delivers how much power?
P=VI=10 WP=VI=10\ \text{W}.
Energy from a 60 W device in 2 hours (joules)?
E=Pt=60×7200=432,000 JE=Pt=60\times7200=432{,}000\ \text{J}.
Why does thick, low-resistance wire reduce heat loss?
Lower RR means lower I2RI^2R heat for the same current.

Connections

Concept Map

defined as

gives

gives

substitute into

substitute into

t cancels to

replace V

replace I

combined with Ohm

combined with Ohm

square term means

drives design of

Power = rate of energy transfer

P = E over t

Voltage = E over Q

E = VQ

Current = Q over t

Q = It

P = VI

Ohm's law V = IR

P = I squared R

P = V squared over R

Heat loss ×4 if current doubles

Hardware ratings and thick wires

Hinglish (regional understanding)

Intuition Hinglish mein samjho

Dekho, power ka matlab hai energy kitni tezi se transfer ho rahi hai — units mein watts, matlab joules per second. Circuit mein charge jab ek voltage difference ke through move karta hai, toh woh kaam karta hai (energy deta hai). Isiliye base formula hai P=VIP = VI: voltage batata hai har coulomb ko kitni energy mili (V=E/QV=E/Q), aur current batata hai per second kitna charge beh raha hai (I=Q/tI=Q/t). Dono multiply karo, time cancel ho jaata hai, aur mil jaata hai power.

Ab Ohm's law V=IRV=IR ka use karke hum wahi formula do aur tarike se likh sakte hai: P=I2RP=I^2R aur P=V2/RP=V^2/R. Yeh teeno same cheez hai, bas alag quantities ke liye convenient. Jo pata ho use karo: V aur I pata hai toh VIVI; I aur R pata hai toh I2RI^2R; V aur R pata hai toh V2/RV^2/R.

Sabse important insight: I2RI^2R mein current ka square hai. Matlab current double karo toh heat char guna ho jaati hai, do guna nahi! Isiliye hardware mein thick (low resistance) wires use karte hai aur high voltage se power bhejte hai — taaki current kam rahe aur I2RI^2R heat loss kam ho. Yeh reason hai ki CPU, PSU, aur battery sab power (heat) ke around design hote hai. Ek aur common galti: time ko seconds mein convert karna mat bhoolna jab energy joules mein chahiye (2 hours = 7200 s).

Go deeper — visual, from zero

Test yourself — Electricity & Charge Basics

Connections