Electricity & Charge Basics
Chapter: 1.1 Electricity & Charge Basics Level: 1 — Recognition Time Limit: 20 minutes Total Marks: 30
Section A — Multiple Choice (1 mark each)
Choose the single best answer.
Q1. The SI unit of electric charge is the: (a) volt (b) ampere (c) coulomb (d) ohm
Q2. Which particle carries a negative charge? (a) proton (b) neutron (c) electron (d) photon
Q3. Ohm's Law is correctly stated as: (a) (b) (c) (d)
Q4. The unit of current, the ampere, is equivalent to: (a) one joule per second (b) one coulomb per second (c) one volt per ohm-second (d) one watt per volt
Q5. Which of the following is the best electrical insulator? (a) copper (b) silicon (c) rubber (d) aluminium
Q6. A resistor of carries a current of . The voltage across it is: (a) (b) (c) (d)
Q7. Electrical power is given by all of the following EXCEPT: (a) (b) (c) (d)
Q8. Conventional current is defined as the direction of flow of: (a) positive charge (b) electrons (c) neutrons (d) magnetic flux
Q9. The unit of capacitance is the: (a) henry (b) farad (c) tesla (d) weber
Q10. Which quantity is measured in joules? (a) power (b) energy (c) charge (d) potential difference
Section B — Matching (1 mark each, 8 marks)
Q11. Match each quantity in Column X to its unit in Column Y. Write the letter.
| Column X | Column Y |
|---|---|
| (i) Voltage | A. henry |
| (ii) Resistance | B. ampere |
| (iii) Inductance | C. volt |
| (iv) Current | D. ohm |
Q12. Match each schematic symbol/component to its role. Write the letter.
| Component | Role |
|---|---|
| (i) Battery | A. stores energy in an electric field |
| (ii) Resistor | B. provides a steady DC source |
| (iii) Capacitor | C. stores energy in a magnetic field |
| (iv) Inductor | D. opposes/limits current flow |
Section C — True/False WITH Justification (2 marks each, 12 marks)
State True or False (1 mark) and give a one-line justification (1 mark).
Q13. A DC signal reverses its direction periodically, whereas an AC signal is constant.
Q14. In a metallic conductor, electrons physically flow in the direction opposite to conventional current.
Q15. One volt equals one joule of energy transferred per coulomb of charge.
Q16. A semiconductor's conductivity lies between that of a conductor and an insulator.
Q17. Doubling the current through a fixed resistor doubles the power it dissipates.
Q18. Electric field strength points from regions of low potential to high potential.
Answer keyMark scheme & solutions
Section A (10 marks)
Q1. (c) coulomb — the coulomb (C) is the SI unit of charge. (1)
Q2. (c) electron — charge . (1)
Q3. (b) — voltage equals current times resistance. (1)
Q4. (b) one coulomb per second — , current is rate of charge flow. (1)
Q5. (c) rubber — non-metal with no free charge carriers; copper/aluminium are conductors, silicon a semiconductor. (1)
Q6. (c) — . (1)
Q7. (d) — incorrect; the valid forms are , , . (1)
Q8. (a) positive charge — conventional current flows from + to −. (1)
Q9. (b) farad — capacitance unit, . (1)
Q10. (b) energy — joule is the unit of energy; power is watts. (1)
Section B (8 marks)
Q11. (i)→C, (ii)→D, (iii)→A, (iv)→B. (1 each = 4)
Q12. (i)→B, (ii)→D, (iii)→A, (iv)→C. (1 each = 4)
Section C (12 marks)
Q13. False. (1) AC (not DC) periodically reverses direction; DC flows in one constant direction. (1)
Q14. True. (1) Electrons are negative, so they drift opposite to the defined positive (conventional) current direction. (1)
Q15. True. (1) By definition — energy per unit charge. (1)
Q16. True. (1) Semiconductors (e.g. silicon) have conductivity between conductors and insulators and can be doped. (1)
Q17. False. (1) , so doubling gives — power quadruples, not doubles. (1)
Q18. False. (1) The electric field points from high potential to low potential (direction a positive charge is pushed). (1)
[
{"claim":"Q6: V=IR gives 20V for I=2A,R=10ohm","code":"I=2; R=10; V=I*R; result = (V==20)"},
{"claim":"Q17: doubling current quadruples power in fixed resistor","code":"I,R=symbols('I R',positive=True); P1=I**2*R; P2=(2*I)**2*R; result = (simplify(P2/P1)==4)"},
{"claim":"Q15: 1V = 1J/C dimensionally consistent (1J over 1C = 1V)","code":"J=1; C=1; V=J/C; result = (V==1)"},
{"claim":"Q4: 1A equals 1C per 1s","code":"Q=1; t=1; I=Q/t; result = (I==1)"}
]