Intuition The ONE core idea
A rocket moves by throwing stuff backward ; an electric rocket uses electricity to throw that stuff very fast . But a fixed-size battery can only throw a fixed amount of "oomph" per second, so you must choose between throwing a little mass very fast (great fuel economy, tiny push) or throwing a lot of mass slowly (poor economy, bigger push) — you can never have both.
This page assumes you have seen nothing . Before you can read the parent topic , you must own every letter it writes. We build them one at a time, each on top of the last.
Definition Sign convention (fix the arrows once, for the whole page)
Every quantity here has a direction , not just a size. We fix forward = the way the ship travels = positive ( + ) , and backward = the way the balls are thrown = negative ( − ) .
The balls leave at − v e (backward), so their momentum is negative .
The ship therefore gains positive momentum, and its thrust F points forward ( + ) .
On this page we usually quote the size (magnitude) of v e , m ˙ , F as positive numbers, but keep the picture in mind: the two directions are always opposite. When the parent topic writes a minus sign in a vector formula, it is just bookkeeping for "backward." A magnitude is never negative; a direction can be.
Everything below lives inside one mental picture: a person on a frictionless skateboard throwing balls.
Intuition What this figure shows
A person on a frictionless skateboard throws orange balls to the left (backward, the − direction) at speed v e ; the green arrow shows the skateboard rolling right (forward, the + direction). The ground line is drawn only so you can see the motion — a real rocket has no ground, and this frictionless board copies that. Watch this picture in your head every time a new symbol appears; each symbol is just a number describing the balls being thrown , and the two arrows always point opposite ways.
m
The amount of "stuff" in an object, measured in kilograms (kg) . Picture it as how many tennis balls you are holding — more balls, more mass. Mass has no direction, so it is always a positive number.
Why the topic needs it: the propellant (the balls) is mass. Every equation counts how much mass leaves the ship.
t and a tiny slice d t
t is ordinary clock time in seconds (s) . The symbol d t (read "dee-tee") means a super-short flash of time — imagine a single film frame, so short that during it you throw exactly one ball.
Picture d t as one frame of a slow-motion video. We will ask "how much happened in one frame ?" and that is how every rate below is born.
d t is a weird new operation."
Why it feels right: the letter d looks like it multiplies.
The fix: d t is not "d times t ." It is a single symbol meaning "a tiny bit of time." Read it as one word: "a-tiny-bit-of-time."
Definition Speed / velocity
v
How fast something moves: metres travelled per second (m/s) . Picture a ball flying: if it covers 5 metres every second, its speed is v = 5 m/s .
Velocity adds a direction to speed. Using our convention, a forward velocity is + v and a backward one is − v . The balls fly backward, so their velocity carries a minus sign; the ship moves forward, so its velocity is positive. In this topic those opposite directions are the whole point.
v e
The speed (size only, always positive) of the balls (propellant) as they leave the thruster , relative to the ship. The little e is just a label meaning "exhaust." Units: m/s . The balls travel backward, so as a velocity it is − v e ; as a speed we write the positive number v e .
Intuition What this figure shows
Two bars compare exhaust speed. The red bar (chemical rocket) reaches only ≈ 4.5 km/s ; the blue bar (electric ion thruster) reaches ≈ 30 km/s — about seven times faster . The picture makes the single headline of the whole subject visible at a glance: electric propulsion throws its balls far faster.
Why the topic needs it: v e is the single most important number in electric propulsion. Chemical rockets are stuck near v e ≈ 4500 m/s ; electric ones reach v e ≈ 30 , 000 m/s . The whole subject is "what do you get for a bigger v e ?"
Definition Mass flow rate
m ˙
How much mass leaves the ship each second . The dot on top means "per second" (rate). Read "m ˙ " as m-dot . Units: kg/s. It is a positive number — mass really does leave.
Picture it as how many balls per second you throw. Throw one 0.5 kg ball every second → m ˙ = 0.5 kg/s .
Mnemonic The dot = a clock
Any letter with a dot on top means "how fast is this thing changing / leaving, per second." m ˙ = mass leaving per second.
p
"Amount of motion" = mass times velocity: p = m v . Units: kg·m/s. Picture it as how hard a moving object would shove you if it hit you — a fast heavy ball has lots of momentum, a slow light one has little. Because it contains velocity, momentum has a direction : a backward ball carries negative momentum ( − ) , and the ship gains equal positive momentum ( + ) .
Intuition What this figure shows
The top orange ball is small but fast; the bottom blue ball is big but slow. Their arrows (velocities) have very different lengths, yet the caption shows both can carry the same momentum p = m v — a lot of mass times a little speed equals a little mass times a lot of speed. That is exactly why the thrust formula F = m ˙ v e has to count both the mass rate and the speed.
Why the topic needs it: the deepest law in the subject is that momentum is conserved — the backward momentum of the balls ( − ) must be exactly cancelled by the forward momentum the ship gains ( + ) . That is exactly Newton's Third Law in number form.
F and thrust
A push , measured in newtons (N) . One newton is roughly the weight of a small apple in your hand. Thrust is the specific name for the forward push a rocket gets from throwing mass backward. Because the ship is pushed forward, thrust points in the + direction.
The key idea, built from the pictures above:
Why "per second"? A force is a continuous push. Throwing one ball gives a single shove; throwing balls every second gives a steady push — and steady push per second is exactly force.
Definition Kinetic energy
E
The energy an object has because it is moving : E = 2 1 m v 2 . Units: joules (J) . The v 2 (v-squared, v times v ) is crucial: doubling the speed quadruples the energy. Because v is squared, direction disappears — energy is always positive.
P
Energy delivered per second : watts (W) , where 1 watt = 1 joule per second. In symbols, power is "energy change per tiny bit of time," written P = d t d E (read: how much E changes in one film-frame d t ). Picture it as how hard your arm works to throw the balls. A bigger solar panel = more watts = a stronger "arm."
Intuition What this figure shows
Two curves versus exhaust speed v e . The green line (push per ball , ∝ v e ) rises as a straight line . The red curve (energy per ball , ∝ v e 2 ) bends upward and quickly leaves the green line far behind. This is the crux: making balls faster raises the energy bill much quicker than it raises the push — the single fact that forces the whole trade-off below.
Common mistake Confusing energy and power.
Why it feels right: both sound like "how strong."
The fix: Energy (J) is the total thrown; power (W) is per second (P = d E / d t ). A weak arm (low power) can still throw huge total energy — it just takes longer.
First, name the specific power we care about.
P j e t
P j e t is just the power P of the beam of balls — the kinetic energy the balls carry away per second. It is the same "energy-per-second" idea as P in §2.8; the subscript "jet" only says which stream of energy we mean (the exhaust jet). So P j e t is a special case of P , measured in watts.
Now build its formula, one honest step at a time.
Step A — energy of the mass thrown in one second. In one second we throw a mass m ˙ (that is what m ˙ means). Each kilogram of it moves at speed v e , so by E = 2 1 m v 2 its kinetic energy is 2 1 m ˙ v e 2 .
Step B — turn energy-per-second into power. That energy leaves every second, so by P = d E / d t (energy per second) the jet power is simply that same number:
P j e t = d t d E = 2 1 m ˙ v e 2 .
Why this is allowed: we multiplied the per-mass energy 2 1 v e 2 by the mass flow m ˙ (mass per second), and "energy per mass × mass per second = energy per second = power." Nothing was assumed.
Step C — replace m ˙ v e with F . Look back at §2.7: thrust is F = m ˙ v e . So inside the formula we can group one v e with m ˙ :
P j e t = 2 1 m ˙ v e 2 = 2 1 = F ( m ˙ v e ) v e = 2 1 F v e .
Where the 2 1 comes from: it is the same 2 1 that sits in E = 2 1 m v 2 — energy, not momentum, carries that factor. Thrust (from momentum) has no 2 1 ; power (from energy) does. The substitution just carries that original 2 1 through untouched.
η
The Greek letter "eta" (say "AY-ta"). A number between 0 and 1 saying what fraction of your electrical power actually ends up in the beam of balls, i.e. η = P j e t / P in where P in is the electrical power fed in. η = 0.65 means 65% useful, 35% lost as heat.
Why the topic needs it: real thrusters waste power, and the wasted part becomes heat the spacecraft must dump via Thermal Control (radiators) .
Definition Standard gravity
g 0
A fixed number, g 0 = 9.81 m/s 2 — the pull of Earth's gravity at the surface. Here it is used only as a conversion constant , not as real gravity acting on the ship.
Definition Specific impulse
I s p
A fuel-economy score , like "miles per gallon" for rockets. It is exhaust speed rescaled by g 0 :
I s p = g 0 v e , measured in == seconds == .
High I s p = uses very little propellant per unit of push. See Specific Impulse .
I s p as a speed.
Why it feels right: I s p and v e are proportional.
The fix: I s p is in seconds , not m/s. To get a real speed, multiply by g 0 : v e = g 0 I s p .
Δ v , m 0 , m f , ln
Δ v ("delta-vee") = the total speed change a rocket can achieve. Δ means "change in." Units: m/s.
m 0 = the ship's mass at the start (full of propellant); m f = mass at the finish (tanks emptier).
ln = the natural logarithm , a math function that answers "how many times must I multiply by a fixed factor to reach this mass ratio?" It grows slowly — see the picture below.
Intuition What this figure shows (why
ln grows slowly)
The green curve is ln ( x ) . Notice it climbs fast at first, then flattens: to go from ln = 1 to ln = 2 you must jump the mass ratio from about 2.7 all the way to 7.4 , and to reach ln = 3 you need a ratio of 20 . So doubling your Δ v by carrying more fuel demands wildly bigger tanks , while doubling v e doubles Δ v outright. That is precisely why electric propulsion — which buys a big v e — beats simply adding fuel. This is the Tsiolkovsky Rocket Equation ; you only need to recognise the letters here.
Mass flow m-dot per second
Thrust F = m-dot times v_e
Kinetic energy E = half m v squared
Jet power P_jet = half m-dot v_e squared
Trade-off P_jet = half F v_e
Specific impulse I_sp = v_e over g0
Delta-v = v_e times ln mass ratio
Electric propulsion topic
What does the dot in m ˙ mean? "per second" — it is a rate; m ˙ = mass leaving per second (kg/s).
What is our sign convention for directions? Forward (ship's motion) is + ; backward (balls thrown) is − ; magnitudes stay positive.
What is momentum, in symbols and words? p = m v ; the "amount of motion," and it carries a direction (backward ball = negative).
Why is thrust F = m ˙ v e a "per second" quantity? Force is a steady push = momentum thrown backward every second.
Write power as a rate of energy. P = d E / d t — energy delivered per second (1 W = 1 J/s).
How do you get P j e t = 2 1 m ˙ v e 2 from E = 2 1 m v 2 ? Multiply the per-mass energy 2 1 v e 2 by the mass flow m ˙ (mass per second) = energy per second = power.
Where does the 2 1 in P j e t = 2 1 F v e come from? From E = 2 1 m v 2 ; energy carries the 2 1 , momentum (hence thrust) does not — the substitution just carries it through.
Is P j e t the same kind of thing as P ? Yes — P j e t is the power P of the exhaust jet specifically; the subscript names which energy stream.
What does efficiency η measure? η = P j e t / P in : fraction of electrical power reaching the beam; the rest becomes heat.
Convert I s p (seconds) to exhaust speed? v e = g 0 I s p with g 0 = 9.81 m/s 2 .
State the trade-off seed relating P j e t , F , v e . P j e t = 2 1 F v e — at fixed jet power, more v e means less F .
Why does ln make extra fuel a losing game? ln grows slowly, so doubling Δ v by fuel needs a huge tank; doubling v e doubles Δ v directly.
What do m 0 and m f stand for? Ship mass at start (full) and finish (emptier).