3.3.40 · D1 · Physics › Rocket Propulsion › Electric propulsion — thrust, power, Isp trade-off
Ek rocket cheezein peeche phenkkar move karta hai; ek electric rocket electricity use karta hai un cheezoon ko bahut tezi se phenkne ke liye. Lekin ek fixed-size battery sirf ek fixed amount "oomph" har second throw kar sakti hai, isliye tumhe choose karna hoga — thodi mass bahut tezi se phenko (mast fuel economy, chhoti push) ya zyada mass dheere phenko (kharab economy, badi push) — dono ek saath kabhi nahi milenge.
Is page pe assume kiya gaya hai ki tumne kuch nahi dekha . Pehle tum parent topic padh sako, uske liye tumhare paas har ek letter hona chahiye. Hum ek ek karke build karenge, har ek pichle ke upar.
Definition Sign convention (arrows ek baar fix karo, poore page ke liye)
Yahan har quantity ka ek direction hai, sirf size nahi. Hum fix karte hain forward = jis taraf ship travel karti hai = positive ( + ) , aur backward = jis taraf balls throw hoti hain = negative ( − ) .
Balls − v e (backward) pe jaati hain, isliye unka momentum negative hai.
Ship isliye positive momentum gain karti hai, aur uska thrust F forward point karta hai ( + ) .
Is page pe hum zyataar v e , m ˙ , F ki size (magnitude) positive numbers mein quote karte hain, lekin picture mind mein rakho: dono directions hamesha opposite hain. Jab parent topic kisi vector formula mein minus sign likhta hai, woh sirf "backward" ke liye bookkeeping hai. Magnitude kabhi negative nahi hoti; direction ho sakti hai.
Neeche jo bhi hai, woh sab ek mental picture mein hai: ek person frictionless skateboard pe baith ke balls throw kar raha hai.
Intuition Yeh figure kya dikhata hai
Ek person frictionless skateboard pe orange balls left (backward, − direction) mein v e speed se phenkta hai; green arrow dikhata hai skateboard right (forward, + direction) mein roll kar raha hai. Ground line sirf isliye draw ki gayi hai taaki tum motion dekh sako — ek real rocket ke liye koi ground nahi hoti, aur yeh frictionless board usi ko copy karta hai. Jab bhi koi naya symbol aaye, is picture ko apne dimag mein chalate raho; har symbol sirf ek number hai jo balls ke phenkne ko describe karta hai, aur dono arrows hamesha opposite directions mein point karte hain.
m
Kisi object mein "stuff" ki quantity, kilograms (kg) mein measured. Ise jitni tennis balls tum pakad rahe ho ke roop mein socho — zyada balls, zyada mass. Mass ka koi direction nahi hota, isliye yeh hamesha positive number hota hai.
Topic ko iske liye kyun chahiye: propellant (balls) hi mass hai. Har equation count karti hai ki ship se kitni mass jaati hai.
t aur ek tiny slice d t
t ordinary clock time hai seconds (s) mein. Symbol d t (padho "dee-tee") matlab hai time ka ek super-short flash — ek single film frame imagine karo, itna chhota ki us mein tum exactly ek ball throw karte ho.
d t ko slow-motion video ke ek frame ki tarah socho. Hum poochhenge "ek frame mein kitna hua?" aur isi se neeche wale har rate ka janam hoga.
d t ek ajeeb naya operation hai."
Kyun galat lagta hai: letter d lagta hai jaise multiply kar raha ho.
Fix: d t ka matlab "d times t " nahi hai. Yeh ek single symbol hai jiska matlab hai "time ka thoda sa hissa." Ise ek word ki tarah padho: "a-tiny-bit-of-time."
Definition Speed / velocity
v
Koi cheez kitni tezi se move karti hai: metres travelled per second (m/s) . Ek flying ball imagine karo: agar woh har second 5 metres cover kare, toh uski speed v = 5 m/s hai.
Velocity speed mein ek direction add karta hai. Hamare convention ke hisaab se, forward velocity + v hai aur backward − v hai. Balls backward fly karti hain, isliye unki velocity mein minus sign aata hai; ship forward move karti hai, isliye uski velocity positive hai. Is topic mein yeh opposite directions hi poori baat hain.
v e
Balls (propellant) ki speed (sirf size, hamesha positive) jaise woh thruster se nikalti hain , ship ke relative. Chhota e sirf ek label hai jiska matlab "exhaust" hai. Units: m/s . Balls backward travel karti hain, isliye velocity ke roop mein yeh − v e hai; speed ke roop mein hum positive number v e likhte hain.
Intuition Yeh figure kya dikhata hai
Do bars exhaust speed compare karti hain. Red bar (chemical rocket) sirf ≈ 4.5 km/s tak pahunchti hai; blue bar (electric ion thruster) ≈ 30 km/s tak pahunchti hai — lagbhag saat guna tez . Yeh picture poore subject ki ek headline ek nazar mein dikhati hai: electric propulsion apni balls bahut tezi se phenkta hai.
Topic ko iske liye kyun chahiye: v e electric propulsion mein sabse important number hai. Chemical rockets v e ≈ 4500 m/s ke paas stuck hain; electric wale v e ≈ 30 , 000 m/s tak pahuncht jaate hain. Poora subject yeh hai ki "bade v e ke liye tumhe kya milta hai?"
Definition Mass flow rate
m ˙
Ship se har second kitni mass nikalti hai. Upar dot ka matlab hai "per second" (rate). "m ˙ " ko m-dot padho. Units: kg/s. Yeh positive number hai — mass sach mein nikalti hai.
Ise har second kitni balls throw karte ho ke roop mein socho. Har second ek 0.5 kg ball throw karo → m ˙ = 0.5 kg/s .
Kisi bhi letter ke upar dot ka matlab hai "yeh cheez per second kitni tezi se change/nikal rahi hai." m ˙ = mass per second nikal rahi hai.
p
"Motion ki quantity" = mass times velocity: p = m v . Units: kg·m/s. Ise ek moving object tumhe hit kare toh kitna dhakka dega ke roop mein socho — ek fast heavy ball mein bahut momentum hota hai, ek slow light wali mein thoda. Kyunki ismein velocity hai, momentum ka ek direction hota hai : backward ball negative momentum ( − ) carry karti hai, aur ship barabar positive momentum ( + ) gain karti hai.
Intuition Yeh figure kya dikhata hai
Upar orange ball chhoti hai lekin tez; neeche blue ball badi hai lekin dheemi. Unke arrows (velocities) ki lengths bahut alag hain, phir bhi caption dikhata hai dono ek hi momentum p = m v carry kar sakti hain — zyada mass times thodi speed = thodi mass times zyada speed. Yahi wajah hai ki thrust formula F = m ˙ v e mein dono mass rate aur speed count karne padte hain.
Topic ko iske liye kyun chahiye: is subject ka sabse gehra law yeh hai ki momentum conserved hota hai — balls ka backward momentum ( − ) bilkul ship ke forward momentum ( + ) se cancel hona chahiye. Yeh exactly Newton's Third Law ka number form hai.
F aur thrust
Ek push , newtons (N) mein measured. Ek newton lagbhag tumhare haath mein ek chhote apple ke weight jitna hota hai. Thrust ek rocket ko mass backward phenkne se milne wali forward push ka specific naam hai. Kyunki ship ko forward push milti hai, thrust + direction mein point karta hai.
Key idea, upar ki pictures se build hua:
"Per second" kyun? Force ek continuous push hai. Ek ball phenkna ek single dhakka deta hai; balls har second phenkna ek steady push deta hai — aur steady push per second exactly force hai.
Definition Kinetic energy
E
Kisi object mein energy jo uske move karne ki wajah se hoti hai: E = 2 1 m v 2 . Units: joules (J) . v 2 (v-squared, v times v ) crucial hai: speed double karne se energy char guna ho jaati hai. Kyunki v squared hai, direction gayab ho jaata hai — energy hamesha positive hoti hai.
P
Energy per second deliver hoti hai: watts (W) , jahan 1 watt = 1 joule per second. Symbols mein, power "energy change per tiny bit of time" hai, likha jaata hai P = d t d E (padho: ek film-frame d t mein E kitna change hota hai). Ise tumhara haath balls throw karne ke liye kitni mehnat karta hai ke roop mein socho. Bada solar panel = zyada watts = zyada mazboot "arm."
Intuition Yeh figure kya dikhata hai
Exhaust speed v e ke against do curves. Green line (push per ball , ∝ v e ) ek straight line ki tarah badhti hai. Red curve (energy per ball , ∝ v e 2 ) upar ki taraf bend karti hai aur jaldi green line ko bahut peeche chhod deti hai. Yahi crux hai: balls ko tez karna energy bill bahut tezi se badhata hai push badhane ke muqable — yeh ek fact hi poore trade-off ko force karta hai neeche.
Common mistake Energy aur power ko mix karna.
Kyun galat lagta hai: dono "kitne strong hain" jaisa lagte hain.
Fix: Energy (J) total thrown hai; power (W) per second hai (P = d E / d t ). Ek kamzor arm (low power) phir bhi bahut zyada total energy throw kar sakti hai — bas zyada waqt lagega.
Pehle, us specific power ka naam rakho jis ki hume parwah hai.
P j e t
P j e t bas balls ki beam ki power P hai — balls har second kitni kinetic energy le jaati hain. Yeh §2.8 wali P jaisi hi "energy-per-second" idea hai; subscript "jet" sirf yeh batata hai ki hum kaun si energy stream ki baat kar rahe hain (exhaust jet). Toh P j e t , P ka ek special case hai, watts mein measured.
Ab iska formula build karo, ek ek honest step se.
Step A — ek second mein throw ki gayi mass ki energy. Ek second mein hum m ˙ mass throw karte hain (yahi m ˙ ka matlab hai). Iska har kilogram v e speed se move karta hai, toh E = 2 1 m v 2 se uski kinetic energy 2 1 m ˙ v e 2 hai.
Step B — energy-per-second ko power mein convert karo. Woh energy har second nikalti hai, toh P = d E / d t (energy per second) se jet power bas wohi number hai:
P j e t = d t d E = 2 1 m ˙ v e 2 .
Yeh kyun allowed hai: humne per-mass energy 2 1 v e 2 ko mass flow m ˙ (mass per second) se multiply kiya, aur "energy per mass × mass per second = energy per second = power." Kuch assume nahi kiya gaya.
Step C — m ˙ v e ko F se replace karo. §2.7 dekho: thrust F = m ˙ v e hai. Toh formula ke andar hum m ˙ ke saath ek v e ko group kar sakte hain:
P j e t = 2 1 m ˙ v e 2 = 2 1 = F ( m ˙ v e ) v e = 2 1 F v e .
2 1 kahan se aaya: yeh wahi 2 1 hai jo E = 2 1 m v 2 mein hai — energy, momentum nahi, woh factor carry karta hai. Thrust (momentum se) mein 2 1 nahi hota; power (energy se) mein hota hai. Substitution bas us original 2 1 ko untouched carry karta hai.
η
Greek letter "eta" (bolo "AY-ta"). 0 aur 1 ke beech ka number jo batata hai tumhari electrical power ka kitna fraction actually balls ki beam mein pahunchta hai , yani η = P j e t / P in jahan P in feed ki gayi electrical power hai. η = 0.65 matlab 65% useful, 35% heat ke roop mein waste.
Topic ko iske liye kyun chahiye: real thrusters power waste karte hain, aur waste hissa heat ban jaata hai jise spacecraft ko Thermal Control (radiators) se dump karna padta hai.
Definition Standard gravity
g 0
Ek fixed number, g 0 = 9.81 m/s 2 — Earth ka surface pe gravity ka pull. Yahan yeh sirf ek conversion constant ki tarah use hota hai, ship pe real gravity ki tarah nahi.
Definition Specific impulse
I s p
Ek fuel-economy score , jaise rockets ke liye "miles per gallon." Yeh exhaust speed ko g 0 se rescale karta hai:
I s p = g 0 v e , measured in == seconds == .
High I s p = push ki har unit ke liye bahut kam propellant use hota hai. Dekho Specific Impulse .
I s p ko speed ki tarah padhna.
Kyun galat lagta hai: I s p aur v e proportional hain.
Fix: I s p seconds mein hai, m/s mein nahi. Real speed paane ke liye g 0 se multiply karo: v e = g 0 I s p .
Δ v , m 0 , m f , ln
Δ v ("delta-vee") = ek rocket jo total speed change achieve kar sakta hai. Δ ka matlab "mein change" hai. Units: m/s.
m 0 = ship ki mass start pe (propellant se bhari); m f = finish pe mass (tanks khaali hote hue).
ln = natural logarithm , ek math function jo poochta hai "is mass ratio tak pahunchne ke liye ek fixed factor se kitni baar multiply karna hoga?" Yeh dheere badhta hai — neeche picture dekho.
Intuition Yeh figure kya dikhata hai (
ln dheere kyun badhta hai)
Green curve ln ( x ) hai. Notice karo yeh pehle tezi se chadhta hai, phir flat ho jaata hai: ln = 1 se ln = 2 tak jaane ke liye mass ratio 2.7 se lekar 7.4 tak jaana padta hai, aur ln = 3 tak pahunchne ke liye 20 ka ratio chahiye. Toh zyada fuel se Δ v double karne ke liye wildly bade tanks chahiye , jabki v e double karne se Δ v seedha double ho jaata hai. Yahi exactly wajah hai ki electric propulsion — jo bada v e kharidta hai — sirf fuel add karne se behtar hai. Yeh Tsiolkovsky Rocket Equation hai; tumhe yahan sirf letters pehchanne hain.
Mass flow m-dot per second
Thrust F = m-dot times v_e
Kinetic energy E = half m v squared
Jet power P_jet = half m-dot v_e squared
Trade-off P_jet = half F v_e
Specific impulse I_sp = v_e over g0
Delta-v = v_e times ln mass ratio
Electric propulsion topic
m ˙ mein dot ka kya matlab hai?"per second" — yeh ek rate hai; m ˙ = mass per second nikal rahi hai (kg/s).
Directions ke liye hamaara sign convention kya hai? Forward (ship ki motion) + hai; backward (balls phenkna) − hai; magnitudes positive rehti hain.
Momentum symbols aur words mein kya hai? p = m v ; "motion ki quantity," aur iska ek direction hota hai (backward ball = negative).
Thrust F = m ˙ v e ek "per second" quantity kyun hai? Force ek steady push hai = har second peeche pheka gaya momentum.
Power ko energy ke rate ke roop mein likho. P = d E / d t — energy per second deliver hoti hai (1 W = 1 J/s).
E = 2 1 m v 2 se P j e t = 2 1 m ˙ v e 2 kaise milta hai?Per-mass energy 2 1 v e 2 ko mass flow m ˙ (mass per second) se multiply karo = energy per second = power.
P j e t = 2 1 F v e mein 2 1 kahan se aaya?E = 2 1 m v 2 se; energy mein 2 1 hota hai, momentum (isliye thrust) mein nahi — substitution ise carry karta hai.
Kya P j e t aur P ek hi tarah ki cheez hain? Haan — P j e t specifically exhaust jet ki power P hai; subscript batata hai kaunsi energy stream hai.
Efficiency η kya measure karta hai? η = P j e t / P in : electrical power ka fraction jo beam tak pahunchta hai; baaki heat ban jaati hai.
I s p (seconds) ko exhaust speed mein convert karo?v e = g 0 I s p jahan g 0 = 9.81 m/s 2 .
P j e t , F , v e ko relate karne wala trade-off seed state karo.P j e t = 2 1 F v e — fixed jet power pe, zyada v e matlab kam F .
ln extra fuel ko losing game kyun banata hai?ln dheere badhta hai, isliye fuel se Δ v double karne ke liye bahut bada tank chahiye; v e double karne se Δ v seedha double ho jaata hai.
m 0 aur m f kya stand karte hain?Start pe ship mass (bhari) aur finish pe (khaali hoti).