1.2.17 · D1Newton's Laws & Dynamics

Foundations — Banking of roads — derivation

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This page assumes you have seen nothing. We build each symbol, draw its picture, and only then let the parent note use it.


0. What a "force" and its arrow mean

Before any letter appears, fix the picture.

Figure — Banking of roads — derivation

Why we need this: the whole derivation is nothing but three arrows (weight, normal, friction) that must add up to one specific arrow (the inward pull). If you cannot picture arrows adding, no equation later will mean anything.


1. — mass, and — gravity's pull

Picture: an arrow of length pointing at the ground, glued to the car's centre. It never tilts, never changes — gravity does not care that the road is banked.

Why the topic needs it: is one of the three forces in the free-body diagram, and it is the thing the road's push must balance vertically.


2. Speed , radius , and "circular motion"

Figure — Banking of roads — derivation

Look at the figure: even when the speed stays constant, the direction the car points keeps changing. A change of direction is still a change of motion — so the car is accelerating, and by Newton's Second Law an acceleration always needs a force.


3. Acceleration — the rate of change of motion

Picture: an arrow, separate from the velocity arrow, showing which way the velocity is being nudged. For circular motion this nudge-arrow always aims at the centre — that is why the pull must be inward.

Why the topic needs it: by Newton's Second Law, force and acceleration are chained together as . We need before we can say how big the inward force must be.


4. The centripetal requirement

This is the single most important quantity in the topic, so we build it slowly.

Read the formula as a story:

  • More mass → harder to swing around → more pull needed (top grows).
  • Faster speed → sharper change of direction each second → much more pull (it grows with , the square).
  • Bigger radius → gentler, lazier curve → less pull needed (bottom grows).
Figure — Banking of roads — derivation

Why the topic needs it: every banking formula is just the sentence "the sideways part of the road's forces must equal ." This is the target the arrows have to hit. Full story in Centripetal force.


5. The banking angle and the tilted road

Picture: the road cross-section is a ramp. The outer edge is lifted; the inner edge (near the centre of the circle) is low, like the inside of a bowl. See the same geometry in Inclined plane and Conical pendulum.


6. Choosing our two axes

Before we split any arrow, we must agree on which two directions to measure things along.

Why this exact choice: if we measure forces along axes that match the acceleration, the bookkeeping in §9 becomes "vertical forces cancel, horizontal forces make " — the simplest possible statement. Any other axes would mix the two together.


7. The normal force — and why it tilts

Figure — Banking of roads — derivation

Because leans, it has TWO useful parts (measured along our two axes from §6):

  • an upward part, , that fights gravity;
  • an inward part, , that points toward the centre — this is the piece that does the turning.

Why the topic needs it: this tilt is the entire trick of banking. A flat road's points straight up and can help turn nothing; a tilted road's donates its inward slice to the centripetal job.


8. Splitting an arrow: and

We keep saying "" and "". Here is why those exact factors appear.

Figure — Banking of roads — derivation

Why these tools and not others: the acceleration is purely horizontal (inward) and zero vertical. So the natural thing is to break every slanted arrow into a vertical piece and a horizontal inward piece. Sine and cosine are exactly the machines that read off those two pieces from a length and an angle. Nothing else does that job.


9. Friction and its coefficient

Picture: an arrow lying flat on the ramp surface. It can point up the slope (when the car is slow and slipping inward) or down the slope (when the car is fast and flying outward). Its length can be anything from up to .


10. Putting it on axes — per direction

That single rule, applied twice, is the derivation. Everything above just earned the symbols it uses — including , the two axes, 's split, and the static .


Prerequisite map

Force is an arrow push or pull

Weight mg points down

Mass m and gravity g

Speed v and radius r

Turning means accelerating

Acceleration a equals v2 over r inward

Centripetal need m a equals mv2 over r

Banking angle theta tilts the road

Normal force N tilts too

Pick vertical and inward axes

Split N with sin and cos

tan theta from dividing the two

Sum of forces equals m a per axis

Static friction f up to mu s N

Banking derivation


Equipment checklist

A force is drawn as what, and what do its length and direction mean?
An arrow; length = strength of the push, direction = direction of the push.
What is weight and which way does it always point?
, pointing straight down, no matter how the road is tilted.
Why does a car turning at constant speed still need a force?
Its velocity direction keeps changing, which is an acceleration, so Newton's Second Law demands a force.
What is acceleration , and how big is it for a circle of radius at speed ?
The rate of change of the velocity arrow; for circular motion , pointing toward the centre.
What is the size and direction of the centripetal requirement?
, horizontal, pointing toward the centre of the circle.
Is centripetal force a separate arrow on the free-body diagram?
No — it is the job (required net inward force); real forces like and fill it.
What is and what does mean?
The banking angle; is a flat road.
Which two axes do we resolve forces along, and why?
Vertical and horizontal-inward, because the acceleration is zero vertically and inward.
Which way does the normal force point, and what happens when the road tilts?
Perpendicular to the road surface; it tilts by the same angle away from vertical.
What are the vertical and horizontal parts of a tilted ?
up and inward.
Why do we split arrows into horizontal and vertical parts specifically?
Because acceleration is horizontal (inward) and zero vertical, so those are the natural axes.
What does dividing horizontal by vertical give, and why is it handy?
; it eliminates and .
Which friction do we use for banking — static or kinetic — and what is its max grip?
Static friction; the car is not skidding, and its max grip is .
Which way does friction point for a fast car versus a slow car?
Fast → down the slope; slow → up the slope.

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