3.3.29 · D5Rocket Propulsion

Question bank — Film cooling — effectiveness, coverage fraction

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True or false — justify

A higher effectiveness means a hotter wall.
False. measures protection, not heat: puts the wall at the coolant temperature (coldest possible), leaves it at the full hot-gas temperature.
At the injection slot () the effectiveness equals exactly 1.
True. There the film is pure unmixed coolant, so and — the exponential decay hasn't started yet.
Effectiveness can be greater than 1 if the coolant is very cold.
False. can at best reach 1 when ; the wall cannot get colder than the coolant that is warming it, so the ratio is capped at 1.
Doubling the coolant flow doubles the protected length (at a fixed ).
True — for a fixed threshold. Since , length is linear in ; the nonlinearity lives in the that only bites when you change .
Doubling also doubles the coverage fraction .
True as written ( is linear in ) — but only until hits 1; you can't protect more than the whole wall, so past the extra coolant is wasted.
The definition of uses the measured, real wall temperature.
False. It uses , the adiabatic wall temperature (zero conduction into the wall). This isolates the gas-side film physics from the wall's own conduction and regenerative cooling.
If increases, the film protects the wall for a longer distance.
False. Larger means the hot gas heats the film faster, so decays faster and shrinks — sits in the denominator of the coverage length.
Raising the design threshold increases the coverage fraction.
False. A higher is a stricter requirement, so fewer stations qualify; shrinks as , cutting coverage.

Spot the error

"Since shaved 1000 K off, an would shave 2000 K."
Correct here, but check why: is linear in , so at the drop is exactly K. The trap is confusing this linear relation with the exponential relation — different variables.
"To protect twice the length, just inject twice the coolant into the same slot."
Half-error. Length is linear in so this works for a fixed , but a real slot has a maximum injection rate and momentum-ratio limits (too much coolant lifts the film off the wall). Engineers add another slot instead — re-establishing the film.
", so at effectiveness is 0."
Error: , not 0. At the exponent is zero and (perfect protection); the reader confused with .
"The group has units of temperature."
Error: it is dimensionless — a Stanton-number-times-length parameter. has units , and W = J/s makes everything cancel.
"Because is between 0 and 1, so is ."
Error: is dimensionless (0–1) but is a real temperature in kelvin, always lying between and — a blend, not a fraction.
"We measured the real wall at 1800 K, so plug into the formula."
Error: the formula wants , not the conducting-wall . A real wall loses heat by conduction/regen cooling, so ; using blends two separate physics and corrupts .
"Coverage fraction can exceed 1 if you inject enough coolant."
Error: is a fraction of the actual wall length; the formula can compute a value above 1, which simply means one slot over-protects — physically saturates at 1 and the surplus coolant is redundant.

Why questions

Why does the coverage fraction formula contain a logarithm?
Because decays exponentially with distance; inverting an exponential to find "where does hit " produces a . Diminishing returns are built in — protecting deeper costs disproportionately.
Why is effectiveness defined with the adiabatic wall temperature rather than the real one?
To separate concerns: captures only the gas-side film behaviour with zero wall conduction, so film performance can be characterized independently of whatever wall material or regenerative loop is behind it.
Why does more coolant flow slow the decay of ?
is the film's heat capacity — its "cold budget." A bigger budget means the same entrained hot gas raises the film temperature by less per metre, so falls off more slowly.
Why does the film get warmer and thinner as it travels downstream?
Turbulent mixing at the film–core interface entrains hot gas into the film (entrainment); each bit of hot mass added both heats the film and dilutes its coolness, driving toward 0.
Why is a weighted blend rather than a simple average?
Because the wall sees a mixture of hot core and cool film, and is precisely the mixing fraction — the amount of "coolness" surviving at that station sets the weights.
Why does the convective coefficient appear in the decay, and where does it come from physically?
is the gas-side heat transfer coefficient (from the Bartz-type correlation); it sets how fast the hot gas delivers heat into the film per degree of temperature difference — the driver of the decay ODE.
Why can't we just make very small to claim full coverage?
is set by the material limit: below it the wall exceeds its safe temperature. Lowering fictitiously "extends" coverage on paper while the actual wall melts — a design lie, not a fix.

Edge cases

What is as (far downstream, single slot)?
: the film is completely spent, , and the wall sees the full hot gas — the reason multiple slots exist.
What happens to if (no coolant injected)?
The exponent for any , so instantly — with no coolant there is no film and no protection anywhere.
What happens to if (unlimited coolant)?
The exponent , so everywhere — the wall stays at along the whole chamber. Physically unreachable (finite propellant), but it shows the correct limit.
What is exactly at the slot when (coolant no colder than the gas)?
The definition divides by zero — is undefined because there is no temperature gap to protect against; the "coolant" offers no benefit.
If is demanded, what coverage do you get?
, so : perfect protection is only met exactly at the slot (), a set of measure zero — you cannot demand over any finite length from one slot.
If equals the actual at , what is ?
Exactly 1 — the film just barely meets the threshold at the far end, so the whole chamber length qualifies as protected and coverage is complete.
At with , what is in terms of the given temperatures?
— the wall is exactly at coolant temperature, the best any station can do.