2.3.16 · D5Modern Physics

Question bank — Pauli exclusion principle

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Before the traps, let's make this page stand on its own — every symbol you need is defined right here, with a picture, so you never have to leave.

Figure — Pauli exclusion principle
Figure — Pauli exclusion principle
Figure — Pauli exclusion principle

With these anchored, the four quantum numbers, the antisymmetric , and the capacity all appear below on their own footing.


True or false — justify

Every item: decide true or false, then give the reason — a bare verdict scores nothing.

The Pauli principle is a fourth force of nature, alongside gravity and electromagnetism.
False. It is not a force at all — it is a consequence of wavefunction antisymmetry. The apparent "push" is the energy cost of promoting fermions to higher empty states, not a field between them.
A single electron, all alone, still obeys the Pauli principle.
True but vacuously. The principle forbids two identical fermions from sharing a state; with only one particle there is no pair to swap, so nothing is constrained — yet the rule still "holds," it just has nothing to exclude.
Protons in a nucleus obey the Pauli principle.
True. Protons are spin- fermions, so no two can share the same quantum state — this is why nuclear shells exist, exactly analogous to electron shells (see Spin-statistics theorem).
Two electrons in the same orbital always violate Pauli.
False. One orbital is only ; two electrons there take and , so their full quantum sets differ — perfectly legal.
Photons can be crammed without limit into one state.
True. Photons are spin-1 bosons with symmetric wavefunctions; setting does not give , so they crowd freely — this is the basis of the Bose-Einstein condensate and lasers.
The Pauli principle would still work if electrons were bosons.
False. The exclusion comes from the minus sign in . Bosons carry a plus sign, so gives a nonzero (in fact enhanced) amplitude — no exclusion whatsoever.
counts electrons per shell because there are orbitals doubled by spin.
True. orbitals (the first odd numbers tile an square), and each holds two spins, so capacity — the factor 2 is precisely the spin freedom Pauli permits.
The total two-fermion wavefunction is antisymmetric, so both its spatial and spin parts must be antisymmetric.
False. Only the product must be antisymmetric; that means one factor is symmetric and the other antisymmetric. E.g. a symmetric spatial part pairs with the antisymmetric (singlet) spin part.

Spot the error

Each statement contains one flaw. Name it and correct it.

"Helium's two electrons violate Pauli because both are in the ."
Error: "same orbital" is treated as "same state." Their sets and differ in , so Pauli is satisfied, not violated.
"Degeneracy pressure in a white dwarf is electrostatic repulsion between electrons."
Error: it is not electromagnetic. It is the energy cost of forcing fermions into higher momentum states because the low ones are full — a purely quantum, statistical pressure (see White dwarf and neutron star).
"The antisymmetric two-fermion state is , and it's normalized."
Error: the normalization factor is missing. Without it (for orthonormal ) equals , not .
"Since Carbon has two electrons, they pair up in one orbital."
Error: Hund's rule plus Pauli push them into different orbitals with parallel spins, lowering repulsion — same-orbital pairing is not the ground state.
"Lithium's third electron goes into with a new spin."
Error: has only two states , both filled by the first two electrons. The third must start — that forced jump is what creates shell structure.
" ranges from to ."
Error: runs from to , giving values. Dropping the negatives undercounts orbitals and breaks the derivation.

Why questions

Give the causal reason, not a restatement.

Why does setting make the antisymmetric vanish?
The two terms and become identical and subtract to zero; a zero wavefunction means zero probability, so that shared state cannot exist.
Why does the Pauli principle give atoms their structure?
Because each electron needs a unique address, they cannot all collapse into the lowest state — they stack into successive shells, and that stacking is what distinguishes one element from the next (the Periodic table structure).
Why is the exclusion tied to half-integer spin specifically?
The Spin-statistics theorem proves that half-integer spin forces the minus sign (antisymmetry), while integer spin forces the plus sign — the exclusion follows only from the minus.
Why can't we say "electrons repel to avoid the same spot"?
Because the exclusion holds even for non-interacting (chargeless-in-principle) fermions; it is built into the wavefunction's symmetry, independent of any electromagnetic force. The antisymmetry also creates an exchange hole: same-spin fermions avoid each other automatically, no force needed.
Why does lead to only two possibilities?
Identical particles are indistinguishable, so swapping cannot change any measurable; that forces — exactly two sign choices, giving fermions () and bosons ().
Why do neutron stars need the Pauli principle to exist?
Neutrons are fermions, so they refuse to share states; the resulting degeneracy pressure resists gravitational collapse once fusion stops (see White dwarf and neutron star).

Edge cases

The scenarios most people never think to check.

Can two electrons in different atoms share all four quantum numbers?
In practice yes — the principle applies to identical fermions in one system; spatially separated electrons occupy different states because their positions (part of the full state) differ. For truly overlapping systems you must antisymmetrize over all electrons together.
What happens to at ?
Only exists, giving electrons — the minimum shell, exactly the two of Helium. It's the degenerate smallest case, not an exception.
Is there an upper limit to how many bosons occupy one state?
No — the symmetric wavefunction never vanishes, so occupancy is unbounded; at low temperature they macroscopically pile into the ground state, forming a Bose-Einstein condensate.
Does a composite particle made of an even number of fermions obey Pauli?
No — it behaves as a boson. E.g. an -particle (2 protons + 2 neutrons = even count) has integer total spin and can share states, despite being built from fermions.
Does the Pauli principle require electrons to have opposite spins to coexist at all?
Only when they share the same orbital . If any of , , or differs, they may have the same spin — differing in even one quantum number is enough.
In the limit of an infinitely deep potential well, does the capacity of a single-particle state (one full space-plus-spin state) change?
No — each single-particle state (a specific spatial mode with a specific spin) holds exactly one fermion; a spatial energy level with two spin choices therefore holds two. Deepening the well shifts energies but never changes this counting.
What if two fermions are of different species, e.g. an electron and a muon?
They are not identical particles — different intrinsic type, not merely different mass — so no antisymmetrization is required between them and both may sit in . Pauli forbids sharing only among truly indistinguishable particles of the same species.

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