1.6.17Oscillations & Waves

Interference — constructive, destructive conditions

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1. What is interference?

WHAT we add: displacements, not intensities. Intensity comes only at the end, after we know the resultant amplitude.


2. Deriving the resultant — from first principles

Take two waves arriving at a point PP, same frequency ω\omega, same amplitude aa, but a phase difference ϕ\phi:

y1=asin(ωt),y2=asin(ωt+ϕ)y_1 = a\sin(\omega t), \qquad y_2 = a\sin(\omega t + \phi)

Superpose (just add): y=y1+y2=asinωt+asin(ωt+ϕ)y = y_1+y_2 = a\sin\omega t + a\sin(\omega t+\phi)

Use sinA+sinB=2sinA+B2cosAB2\sin A + \sin B = 2\sin\frac{A+B}{2}\cos\frac{A-B}{2} with A=ωt, B=ωt+ϕA=\omega t,\ B=\omega t+\phi:

y=2acosϕ2resultant amplitude A  sin ⁣(ωt+ϕ2)y = \underbrace{2a\cos\tfrac{\phi}{2}}_{\text{resultant amplitude } A}\;\sin\!\left(\omega t + \tfrac{\phi}{2}\right)

Why this step? The sum of two sines of equal frequency is still a sine of the same frequency — only its amplitude and phase change. The amplitude is the bracketed factor.

Why IA2I\propto A^2? Energy (and brightness/loudness) of a wave scales with amplitude squared — a universal wave fact.


3. The conditions (the 80/20 core)

The whole subtopic lives in when is cos2(ϕ/2)\cos^2(\phi/2) maximum or zero.

Constructive — waves in step, amplitudes add: ϕ=2πn    cosϕ2=±1    Amax=2a,Imax=4I0\phi = 2\pi n \implies \cos\tfrac{\phi}{2}=\pm1 \implies A_{\max}=2a,\quad I_{\max}=4I_0 Δx=nλn=0,±1,±2,\boxed{\Delta x = n\lambda}\qquad n=0,\pm1,\pm2,\dots

Destructive — waves opposite, cancel: ϕ=(2n+1)π    cosϕ2=0    Amin=0,Imin=0\phi = (2n+1)\pi \implies \cos\tfrac{\phi}{2}=0 \implies A_{\min}=0,\quad I_{\min}=0 Δx=(n+12)λn=0,±1,\boxed{\Delta x = \left(n+\tfrac12\right)\lambda}\qquad n=0,\pm1,\dots

Figure — Interference — constructive, destructive conditions

4. Worked examples


5. Common mistakes


6. Active recall

Recall Flip me

Q: Two coherent waves, phase diff ϕ\phi, each intensity I0I_0 — resultant II? A: I=4I0cos2(ϕ/2)I = 4I_0\cos^2(\phi/2).

Q: Path difference for destructive interference? A: Δx=(n+12)λ\Delta x = (n+\tfrac12)\lambda.

Q: Why Imax=4I0I_{\max}=4I_0 if each is I0I_0? A: Amplitudes add → 2a2aI(2a)2=4I0I\propto(2a)^2=4I_0; energy redistributed, average still 2I02I_0.

Recall Feynman: explain to a 12-year-old

Imagine two kids pushing the same swing. If they push together at the right moment, the swing flies high — that's constructive. If one pushes forward exactly when the other pulls back, the swing barely moves — that's destructive. Waves do the same: pushes that line up make a big wave, pushes that fight make nothing. The "right moment" is set by how far each wave travelled.


7. Forecast-then-Verify


Connections

  • Principle of Superposition — the parent rule interference rests on.
  • Young's Double Slit Experiment — applies Δx=dsinθ\Delta x = d\sin\theta to these conditions.
  • Standing Waves — interference of oppositely-travelling waves.
  • Beats — interference of different frequencies in time.
  • Coherence and Path Difference — why steady ϕ\phi is required.
  • Energy in Waves — why IA2I\propto A^2 and energy conservation in fringes.
Resultant amplitude of two equal-aa waves with phase ϕ\phi
A=2acos(ϕ/2)A = 2a\cos(\phi/2)
Resultant intensity (each I0I_0) at phase ϕ\phi
I=4I0cos2(ϕ/2)I = 4I_0\cos^2(\phi/2)
Constructive condition (path)
Δx=nλ\Delta x = n\lambda, n=0,±1,n=0,\pm1,\dots
Destructive condition (path)
Δx=(n+12)λ\Delta x = (n+\tfrac12)\lambda
Link between path diff and phase diff
ϕ=(2π/λ)Δx\phi = (2\pi/\lambda)\,\Delta x
Why Imax=4I0I_{\max}=4I_0 not 2I02I_0
amplitudes add to 2a2a; IA2=(2a)2=4I0I\propto A^2=(2a)^2=4I_0
What must sources be for stable interference
coherent (constant phase difference, same frequency)
Is energy conserved in interference
yes — redistributed; spatial average intensity stays 2I02I_0
General resultant of amplitudes a1,a2a_1,a_2
A=a12+a22+2a1a2cosϕA=\sqrt{a_1^2+a_2^2+2a_1a_2\cos\phi}
Intensity at ϕ=π/2\phi=\pi/2 for equal sources
2I02I_0 (the average value)

Concept Map

requires coherent sources

defines

master link phi = 2pi/lambda times dx

superpose two sines

squared

maximised

zero

dx = n lambda, phi = 2 pi n

dx = n+half lambda, phi = 2n+1 pi

governed by

Superposition of displacements

Interference pattern

Constant phase difference

Path difference dx

Phase difference phi

Resultant amplitude A = 2a cos phi/2

Intensity I = 4 I0 cos squared phi/2

Constructive

Destructive

A max = 2a, I max = 4 I0

A min = 0, I min = 0

Hinglish (regional understanding)

Intuition Hinglish mein samjho

Dekho, interference ka core idea ek hi line mein hai: jab do waves ek hi jagah pe milti hain, unke displacements add ho jaate hain — isko Superposition Principle kehte hain. Agar dono waves "step mein" hain (crest se crest), toh wave badi ho jaati hai — ye constructive hai. Agar ek ka crest doosre ke trough se milta hai, toh cancel ho jaate hain — ye destructive hai. Bas itna hi.

Maths bhi simple derive hota hai. Do equal waves asinωta\sin\omega t aur asin(ωt+ϕ)a\sin(\omega t+\phi) ko add karo, sinA+sinB\sin A+\sin B formula lagao, toh resultant amplitude milti hai A=2acos(ϕ/2)A=2a\cos(\phi/2), aur intensity I=4I0cos2(ϕ/2)I=4I_0\cos^2(\phi/2). Yahan se sab nikal aata hai: jab ϕ=2nπ\phi=2n\pi (ya path difference Δx=nλ\Delta x=n\lambda) toh max brightness, aur jab ϕ=(2n+1)π\phi=(2n+1)\pi (ya Δx=(n+12)λ\Delta x=(n+\tfrac12)\lambda) toh total darkness. Yaad rakho: "Whole = Wow, Half = Hush" — poora wavelength loud, aadha extra silent.

Ek common galti: log sochte hain intensity bas 2I02I_0 ho jaayegi. Nahi! Coherent waves mein pehle amplitude add karo, phir square karo — isliye bright point pe 4I04I_0 milta hai aur dark point pe 00. Energy create nahi hoti, sirf redistribute hoti hai; average nikaalo toh 2I02I_0 hi aata hai. Isiliye sources ka coherent hona zaroori hai (constant phase difference), warna pattern band ho jaata hai.

Ye concept bahut jagah kaam aata hai — Young's double slit, sound ke dead spots, thin film ke colours, noise-cancelling headphones. Path difference ko hamesha λ\lambda se compare karo: integer multiple → constructive, half-integer → destructive. Yahi 80/20 hai, baaki sab isi ka application hai.

Go deeper — visual, from zero

Test yourself — Oscillations & Waves

Connections