Oscillations & Waves
Level 1: Recognition Test
Time limit: 20 minutes Total marks: 30 Instructions: Answer all questions. For True/False, a correct justification is required for full marks.
Section A — Multiple Choice (1 mark each) [10 marks]
Q1. In simple harmonic motion, the restoring force is: (a) constant in magnitude (b) proportional to displacement and directed towards equilibrium (c) proportional to velocity (d) proportional to acceleration squared
Q2. The angular frequency , period and frequency are related by: (a) (b) (c) (d)
Q3. For a mass on a spring in SHM, the velocity is maximum when: (a) (b) (c) (d)
Q4. The period of a simple pendulum of length is: (a) (b) (c) (d)
Q5. In a longitudinal wave, the particle oscillations are: (a) perpendicular to wave propagation (b) parallel to wave propagation (c) circular (d) zero
Q6. The condition for constructive interference (path difference ) is: (a) (b) (c) (d)
Q7. A critically damped oscillator: (a) oscillates forever (b) returns to equilibrium in the shortest time without oscillating (c) overshoots many times (d) has no damping
Q8. The beat frequency produced by two waves of frequencies and is: (a) (b) (c) (d)
Q9. The Mach number is defined as: (a) (sound speed / source speed) (b) (source speed / sound speed) (c) (d)
Q10. A quantity that stays constant throughout the motion of an ideal SHM oscillator is: (a) kinetic energy (b) potential energy (c) total mechanical energy (d) displacement
Section B — Matching (1 mark each) [8 marks]
Q11. Match each term with its correct expression/description:
| # | Term | Expression / Description | |
|---|---|---|---|
| i | SHM displacement | P | |
| ii | Total energy in SHM | Q | |
| iii | Wave speed | R | point of zero displacement in a standing wave |
| iv | Node | S |
Q12. Match the oscillator/wave concept with its keyword:
| # | Concept | Keyword | |
|---|---|---|---|
| i | Resonance | P | energy loss, amplitude decays |
| ii | Damping | Q | driving frequency = natural frequency |
| iii | Overtone | R | frequency above the fundamental |
| iv | Q factor | S | sharpness of resonance / quality |
Section C — True / False with Justification (2 marks each) [12 marks]
(1 mark correct T/F, 1 mark justification)
Q13. In SHM, acceleration is maximum at the equilibrium position.
Q14. For a transverse wave on a string, wave speed depends on the tension and the linear mass density.
Q15. At resonance in a lightly damped forced oscillator, the amplitude is at its maximum.
Q16. The frequency of a wave changes when it passes from one medium to another.
Q17. When a source of sound moves towards a stationary observer, the observed frequency is lower than the emitted frequency.
Q18. Doubling the amplitude of an SHM oscillator doubles its total energy.
Answer keyMark scheme & solutions
Section A — MCQ (1 mark each)
Q1 — (b). SHM is defined by : force proportional to displacement, opposite in direction. (1)
Q2 — (a). and , so . (1)
Q3 — (c). From , is maximum () at . (1)
Q4 — (b). Small-angle pendulum: . (1)
Q5 — (b). Longitudinal waves oscillate parallel to propagation (e.g. sound). (1)
Q6 — (b). Constructive interference: whole-number of wavelengths, . (1)
Q7 — (b). Critical damping returns to equilibrium fastest without oscillating. (1)
Q8 — (c). Beat frequency . (1)
Q9 — (b). = source speed ÷ sound speed. (1)
Q10 — (c). KE and PE interchange, but total is constant. (1)
Section B — Matching (1 mark each pairing)
Q11: i→Q, ii→P, iii→S, iv→R (1 each = 4)
Q12: i→Q, ii→P, iii→R, iv→S (1 each = 4)
Section C — True/False with Justification
Q13 — FALSE. (1) Acceleration is proportional to ; it is zero at equilibrium and maximum at . (1)
Q14 — TRUE. (1) Wave speed on a string , depending on tension and linear density . (1)
Q15 — TRUE. (1) Forced oscillation amplitude peaks when the driving frequency approaches the natural frequency (resonance), especially sharp for low damping (high Q). (1)
Q16 — FALSE. (1) Frequency is set by the source and is unchanged; wave speed and wavelength change between media (, constant). (1)
Q17 — FALSE. (1) Source approaching → wavefronts compressed → observed frequency higher (). (1)
Q18 — FALSE. (1) , so doubling quadruples the energy. (1)
[
{"claim":"v_max occurs at x=0 for v=omega*sqrt(A^2-x^2)",
"code":"A,w,x=symbols('A w x',positive=True); v=w*sqrt(A**2-x**2); result = (v.subs(x,0)==w*A) and (v.subs(x,A)==0)"},
{"claim":"Total SHM energy is constant = kA^2/2",
"code":"k,A,w,t,phi=symbols('k A w t phi',positive=True); m=k/w**2; x=A*cos(w*t+phi); v=diff(x,t); E=simplify(Rational(1,2)*m*v**2+Rational(1,2)*k*x**2); result = simplify(E-Rational(1,2)*k*A**2)==0"},
{"claim":"Doubling amplitude quadruples energy",
"code":"k,A=symbols('k A',positive=True); E1=Rational(1,2)*k*A**2; E2=Rational(1,2)*k*(2*A)**2; result = simplify(E2/E1)==4"},
{"claim":"Approaching source raises observed frequency",
"code":"f,c,vs=symbols('f c vs',positive=True); fp=f*c/(c-vs); result = simplify(fp - f) .subs({f:1,c:340,vs:30}) > 0"}
]