4.3.14 · D1Semiconductor Fabrication

Foundations — Atomic layer deposition (ALD)

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Before you can read the parent note Atomic layer deposition (ALD), you need every symbol it throws at you defined from absolute zero. This page is the toolbox. Nothing below assumes you have seen chemistry notation, exponentials, or calculus before.


1. A "surface" and a "site" — the picture everything rests on

Imagine the top face of a wafer — a flat solid — zoomed in so hard you see individual atoms. The atoms at the very top edge are special: they have dangling arms with nothing bonded above them. Chemists write these top-most reactive spots as little sticky flags. In the picture each teal flag is one reactive site — one place where an incoming gas molecule is allowed to grab on.

Why the topic needs it: ALD's entire magic — that a reaction stops by itself — only makes sense once you accept that the number of parking spaces is finite. Run out of spaces → reaction ends. That is the whole story.


2. Counting the sites:

Picture a fixed square of surface, say . Count every teal flag inside it. That count is . A bigger wafer just has more squares — the density stays the same.

Why the topic needs it: to convert "fraction of spaces filled" into an actual amount of material, you must know how many spaces there were to begin with. is that conversion number.


3. The coverage fraction — the star of the show

Now watch the parking lot fill up over time. We do not track each car individually — too many. Instead we track one clean number: what fraction of the lot is full.

Because is the filled fraction, the empty fraction is whatever is left over:

Why the topic needs it: ALD "self-limits" precisely because shrinks to zero. Everything in the derivation is built to describe how climbs to 1 and then flatlines.


4. Time and rate of change — why calculus enters

Coverage is not instant; it grows while the gas flows. We need a way to say how fast is climbing at any instant.

Picture the slope of the filling curve in the figure of §5: the derivative is that slope. Where the curve is steep, is large; where it flattens, .


5. Pressure , rate constant , and the filling law

Two more inputs decide the filling speed:

Put the three pieces together. The filling speed is: (how much gas is arriving, ) × (how many empty spaces are left, ):


6. The exponential — what "stops by itself" looks like

Solving the filling law (the parent note does the algebra) gives the shape of the whole curve:

You must understand two symbols here.

Why the topic needs it: this exponential is the equation the whole parent note is built to derive and use. Recognising its shape — rise then flatten — is recognising ALD itself.


7. Growth per cycle (GPC) and total thickness

Once one full A→B cycle finishes, it has added a thin, fixed slab of material.


Prerequisite map

Reactive surface site

Site density N0

Coverage fraction theta

Free fraction one minus theta

Time t

Rate d theta dt

Pressure P and constant k

Filling law

Exponential saturation curve

Growth per cycle GPC

Total thickness d

Atomic Layer Deposition

Each foundation feeds the next: sites → how many → how full → how fast filling → the law → its exponential solution → thickness. Master them in that order and the parent note reads effortlessly.


Where these tools reappear


Equipment checklist

Test yourself — reveal only after answering.

What does the asterisk * mean in ?
It marks a species bonded to the surface, not free in the gas.
What is and its units?
The number of reactive sites per unit area, e.g. sites per cm².
What does represent, and what range can it take?
The fraction of sites already reacted; a pure number from 0 to 1.
If , what is the free-site fraction?
, i.e. 20% of sites are still open.
Why do we use a derivative instead of plain algebra?
Because the filling speed itself changes over time; a derivative gives the exact instantaneous rate.
In the filling law, why is there a factor ?
Reactions can only happen on still-free sites; when none are free, the rate is zero — this causes self-limiting.
What shape does have as grows?
It starts at 1 and fades smoothly toward 0, never quite reaching it.
Why does coverage flatten instead of rising forever?
Late-arriving molecules increasingly hit already-filled sites, so the remaining fraction shrinks in proportion to itself — an exponential approach to full.
Convert 5 nm to ångström.
50 Å (since 1 nm = 10 Å).
Write the total-thickness formula.
.
What does the up-arrow in signify?
The product leaves as a gas and is purged away.