Start from the physical picture. The gate + oxide + substrate form a capacitor. The gate charge induces an opposite charge in the substrate.
NMOS on a p-substrate:
p-substrate is full of holes. Put VG positive relative to source.
Positive gate charge repels holes away from the surface → a depletion region.
Push VG higher: it now attracts minority electrons to the surface.
When the surface has as many electrons as the bulk had holes → strong inversion. The surface is now effectively n-type: a conducting n-channel bridges the two n regions.
The gate voltage at which this happens is the thresholdVTn.
So the condition to turn ON:
VGS>VTn(VTn>0)
Define the overdriveVov=VGS−VTn. Channel exists only when Vov>0.
PMOS is the exact dual: everything's flipped in sign, so ON means
VGS<VTp⟺VSG>∣VTp∣
Electrons move faster than holes in silicon:
μn≈2–3×μp
WHY? Holes conduct via the valence band which has heavier effective mass and more scattering. So for the sameW/L and overdrive, an NMOS delivers ~2–3× the current of a PMOS.
Consequence (the 80/20 takeaway): In CMOS, to make the pull-up (PMOS) as strong as the pull-down (NMOS), designers make the PMOS wider, typically Wp≈2–3Wn. This single fact explains most CMOS layout asymmetry.
The higher-potential terminal (where holes enter).
Why is PMOS made wider than NMOS in CMOS?
Because μp<μn; widening compensates lower hole mobility for equal drive.
Typical mobility ratio μn/μp?
About 2–3.
In a CMOS inverter, which device pulls the output HIGH?
The PMOS (pull-up).
Which device passes a strong logic 0?
NMOS.
Saturation current form for NMOS?
ID=21μnCoxLW(VGS−VTn)2.
Define overdrive voltage.
Vov=VGS−VTn (NMOS); channel exists only if Vov>0.
What sizing gives equal NMOS/PMOS drive if μn=3μp?
Wp=3Wn.
Recall Feynman: explain it to a 12-year-old
Imagine two kinds of water gate. The NMOS gate opens when you push its handle UP, and it lets fast little swimmers (electrons) through. The PMOS gate opens when you push its handle DOWN, and it lets slower bubbles (holes) through. Because the bubbles are slower, you make the bubble-gate a bit wider so the same amount gets through in the same time. In a computer we glue an up-gate and a down-gate together: when you push, one closes and the other opens — so the output always flips. That flip is how computers say "not."
Dekho, MOSFET basically ek voltage-controlled switch hai. Gate pe voltage lagao, aur wahi decide karta hai ki drain-source ke beech current chalega ya nahi. Do types hote hain: NMOS aur PMOS, aur ye ek dusre ke mirror-image hain. NMOS electrons se conduct karta hai aur ON hota hai jab gate HIGH ho (VGS>VTn, threshold positive). PMOS holes se conduct karta hai aur ON hota hai jab gate LOW ho (gate source se neeche, threshold negative).
Ek important cheez: source hamesha carriers ke entry point se define hota hai, pin ke naam se nahi. NMOS me source low voltage wala terminal, PMOS me source high voltage wala terminal. Isliye PMOS me source ko VDD pe rakhte hain aur NMOS me source ko ground pe. Ye samajh gaye to CMOS inverter automatic clear ho jayega: input 0 diya to NMOS OFF, PMOS ON, output HIGH — yani NOT gate ban gaya, aur static current bhi nearly zero.
Sabse bada practical point: silicon me electrons holes se 2-3 guna fast chalte hain (μn>μp). Iska matlab same size pe NMOS zyada strong hota hai. Isiliye designers PMOS ko chauda (wider) banate hain, roughly Wp≈2 se 3Wn, taaki pull-up aur pull-down dono barabar strong ho. Bas yehi ek asymmetry poore CMOS layout ka reason hai. Yaad rakho: "N goes UP, P goes DOWN" — NMOS pull-down, PMOS pull-up.