Before you can derive the critical angle, you must own every letter and picture the parent note throws at you. This page builds each one from nothing, in the order they depend on each other.
The whole story happens at a flat surface where two see-through materials meet — say glass sitting under air, or water under air.
Look at the figure: the horizontal chalk line is the boundary (also called the interface). Medium 1 fills the bottom, Medium 2 the top. A single ray of light climbs up and hits the boundary at one point.
You cannot say "the angle of the ray" without saying angle from what. In optics we never measure angles from the surface itself. We measure from a special line called the normal.
In the figure the normal is the vertical dashed chalk line. Notice the little square corner symbol — that marks the 90° between the normal and the surface.
Now that we have a reference line, we can name the angles.
Study this figure carefully — it is the whole geometry of refraction on one board:
The incident ray (chalk blue) comes up from the bottom, hitting the surface.
θ1 is the pale-yellow angle between it and the normal.
The refracted ray (chalk pink) continues into Medium 2, bent.
θ2 is the angle between that and the normal.
Recall Quick self-check on the picture
If a ray goes straight up along the normal, what are θ1 and θ2? ::: Both 0° — the ray is on the normal, so there is no gap between ray and normal, and it passes straight through with no bending.
Before we can write Snell's Law we must first meet the one piece of mathematics it leans on: the sine of an angle. You should never use a symbol you cannot picture, so we build sinθ from zero before it appears in any law.
The figure shows a right triangle with the angle θ marked. The pink side is oppositeθ; the long slanted side is the hypotenuse. As θ grows, the opposite side grows toward the hypotenuse's full length, so the ratio climbs toward 1.
Recall Sine sanity values
sin0°=? ::: 0 (the opposite side has zero length — ray lies on the normal).
sin90°=? ::: 1 (opposite side equals the hypotenuse — ray lies flat along the surface).
sin30°=? ::: 0.5 (a handy value used in Example 3 of the parent).
Everything above now lets us state the payoff symbol precisely — including the exact conditions under which it even exists.
This is why the domain condition matters: the formula sinθc=n2/n1 only gives a value ≤1 (a valid sine) when n2<n1. If you ever plug in n1<n2 and get "sinθc>1", that is the maths telling you no critical angle exists.
With this in hand, the parent's derivation reads cleanly: set θ2=90°, use sin90°=1, and Snell collapses to sinθc=n2/n1; then apply sin−1 (principal branch) to read off the angle.