1.3.1Work, Energy & Power

Work — definition, dot product F·d, sign convention

1,953 words9 min readdifficulty · medium1 backlinks

What is Work?

WHAT do the symbols mean?

  • FF = magnitude of the force (N)
  • dd = magnitude of displacement (m) — note: displacement, not distance/path length
  • θ\theta = angle between the two vectors when drawn tail-to-tail

Deriving W=FdcosθW = Fd\cos\theta from first principles

Step 1 — Resolve the force. Split F\vec F into components relative to d\vec d: F=FcosθF=FsinθF_\parallel = F\cos\theta \qquad F_\perp = F\sin\theta Why this step? Because energy transfer is one-dimensional along the path; decomposing isolates the part that actually moves with the object.

Step 2 — Define work as (along-motion force) × (displacement). W=Fd=(Fcosθ)d=FdcosθW = F_\parallel \, d = (F\cos\theta)\,d = Fd\cos\theta Why this step? The perpendicular component FF_\perp produces zero displacement in its direction, so it does zero work. Only FF_\parallel survives.

Step 3 — Recognize this is the dot product. By the very definition of the scalar product, Fd=Fdcosθ\vec F\cdot\vec d = Fd\cos\theta. So work is naturally a dot product — which automatically encodes the cosθ\cos\theta and the sign. W=Fd=Fxdx+Fydy+Fzdz\boxed{W = \vec F\cdot\vec d = F_xd_x + F_yd_y + F_zd_z} Why this step? The component form lets you compute work without ever finding θ\theta — useful when forces are given as vectors.

Figure — Work — definition, dot product F·d, sign convention

Sign Convention — the heart of the matter

The sign of WW comes entirely from cosθ\cos\theta:


Worked Examples


Common Mistakes (Steel-manned)


Recall Feynman: explain to a 12-year-old

Imagine pushing a toy car. If you push it the way it's already going, you help it go faster — that's positive work, you gave it energy. If you push against it to stop it, that's negative work, you took energy away. If you push it sideways — only turning it but not speeding it up — you did no work at all. Work is just "how much energy your push gave to the moving thing." Holding something still, even if your arms ache, gives it nothing — so it's zero work!


Active Recall

Work done by a constant force is defined as
W=Fd=FdcosθW = \vec F\cdot\vec d = Fd\cos\theta
The SI unit of work and its base-unit equivalent
joule, 1J=1N⋅m1\,\text{J} = 1\,\text{N·m}
Why is the perpendicular component of force ignored in work
it produces no displacement in its own direction, so it transfers no energy
Work is positive when the angle between force and displacement is
between 0° and 90°90° (so cosθ>0\cos\theta>0)
Work is zero when
force is perpendicular to displacement (θ=90°\theta=90°), or displacement is zero
Sign of work done by gravity on an object thrown upward
negative (force down, motion up, θ=180°\theta=180°)
Sign of work done by kinetic friction on a sliding body
negative (θ=180°\theta=180°, opposes motion)
Component form of work for F\vec F and d\vec d
W=Fxdx+Fydy+FzdzW = F_xd_x+F_yd_y+F_zd_z
Why is work a scalar despite involving two vectors
the dot product of two vectors yields a scalar
Work done by centripetal tension in uniform circular motion
zero, since tension is always perpendicular to velocity

Connections

Concept Map

combined via

combined via

equals

split by

gives

gives

does work

does zero work

contains

determines

also written as

measures

positive speeds up, zero steers

Force vector F

Displacement d

Work W scalar

Dot product F·d

Resolve force into components

F parallel = F cos theta

F perp = F sin theta

cos theta term

Sign of work

Component form Fx dx + Fy dy + Fz dz

Energy transfer

Hinglish (regional understanding)

Intuition Hinglish mein samjho

Dekho, "Work" ka physics-wala matlab roz-marra ke matlab se alag hai. Agar tum deewar ko poora din push karte raho aur woh hile hi nahi, to physics kehta hai tumne us par zero work kiya — kyunki displacement zero hai. Work ka asli funda yeh hai: W=Fd=FdcosθW = \vec F\cdot\vec d = Fd\cos\theta. Yahan sirf force ka woh part kaam karta hai jo displacement ke direction mein hai (yani FcosθF\cos\theta). Jo perpendicular part hai, woh sirf direction badalta hai, energy nahi deta.

Sign convention sabse important hai. Agar force aur motion same direction mein (θ<90°\theta<90°), to cos\cos positive, matlab positive work — object ko energy mil rahi hai, speed badhegi. Agar force motion ke against (θ>90°\theta>90°, jaise friction ya upar phenke ball par gravity), to cos\cos negative, matlab negative work — energy chhin rahi hai, speed kam hogi. Aur agar force bilkul perpendicular ho (θ=90°\theta=90°, jaise circular motion mein tension), to cos90°=0\cos90°=0, matlab zero work.

Ek common galti: log sochte hain "lambi distance = zyada work" ya "sinθ\sin\theta lagao". Galat! Work mein hamesha cosθ\cos\theta aata hai aur woh angle force aur displacement ke beech wala hota hai. Bag uthaake horizontal chalne par work zero hota hai kyunki upar wali force aur horizontal motion ke beech 90°90° hai — thakaan biological hai, physics work nahi. Yaad rakho: "Cos for the force, along the road" — bas yeh formula aur sign table pakad lo, to is poore topic ke 80% sawaal nikal jaayenge.

Go deeper — visual, from zero

Test yourself — Work, Energy & Power

Connections