1.2.7Newton's Laws & Dynamics

Coefficients of friction — measurement, material dependence

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WHAT is a coefficient of friction?

WHY a ratio? Experiment shows friction scales linearly with how hard the surfaces are squeezed together (NN). Dividing it out gives a number that's the same regardless of weight — so we can predict friction for any load.


HOW do we measure μ\mu? (Two classic methods — derive both)

Method 1 — The inclined plane (angle of repose)

Place the block on a ramp and slowly tilt until it just begins to slip. At that critical angle θc\theta_c:

Set up coordinates along/perpendicular to the incline. Forces on the block:

  • Weight mgmg splits into: along-slope mgsinθmg\sin\theta (drives sliding), into-slope mgcosθmg\cos\theta (presses surfaces).
  • Normal force NN.
  • Friction ff up the slope.

Perpendicular balance (no motion off the surface): N=mgcosθ— Why? No acceleration perpendicular to ramp.N = mg\cos\theta \quad\text{— Why? No acceleration perpendicular to ramp.}

At the verge of slipping, friction is maxed out: f=μsNf = \mu_s N, and along-slope balance still holds: mgsinθc=μsN=μsmgcosθcmg\sin\theta_c = \mu_s N = \mu_s\, mg\cos\theta_c

Cancel mgmg (Why? mass-independence — the same trick that makes Galileo's ramps work): μs=tanθc\boxed{\mu_s = \tan\theta_c}

Beautiful result: the mass cancels, so you only need a protractor — no force meter, no scale!

For μk\mu_k: tilt slightly past θc\theta_c and find the angle where the block slides at constant velocity (zero acceleration). Same algebra gives ==μk=tanθslide\mu_k = \tan\theta_{\text{slide}}==.

Figure — Coefficients of friction — measurement, material dependence

Method 2 — Horizontal pull

Pull horizontally with a spring scale until the block just moves; read the force FmaxF_{\max}. N=mgμs=FmaxmgN = mg \quad\Rightarrow\quad \mu_s = \frac{F_{\max}}{mg} Then keep it moving steadily (constant velocity, a=0a=0): the reading FslideF_{\text{slide}} gives μk=Fslidemg.\mu_k = \frac{F_{\text{slide}}}{mg}. Why constant velocity? If a=0a=0 then applied force exactly equals kinetic friction — no leftover net force to confuse the reading.


Material dependence — what changes μ\mu?

Surface pair μs\mu_s (approx) Why
Rubber / dry concrete 1.0\sim 1.0 soft rubber deforms into every pore → huge interlocking
Wood / wood 0.3\sim 0.3 moderate roughness
Steel / steel (dry) 0.6\sim 0.6 metallic cold-welding
Steel / steel (oiled) 0.1\sim 0.1 film separates asperities
Teflon / Teflon 0.04\sim 0.04 weak molecular adhesion
Ice / steel 0.03\sim 0.03 meltwater lubricant

Factors: material hardness/softness, surface roughness, contamination/lubricants, and surface cleanliness. NOT (to first order): apparent contact area, sliding speed, weight.


Worked examples



Recall Feynman: explain to a 12-year-old

Imagine two LEGO baseplates pressed face to face — the little bumps poke into each other. To slide them you must climb the bumps out of their slots. Press harder and more bumps lock in, so it's harder to slide — that's why pushing down increases grip. The "grippiness number" μ\mu tells you how bumpy/sticky that specific pair is. Rubber-on-road is super grippy (μ1\mu\approx1); ice is slippery (μ0.03\mu\approx0.03). To measure it, tilt a ramp until the thing slides — the tilt angle's tangent IS the number, no scale needed!


Flashcards

Define coefficient of static friction
μs=fs,max/N\mu_s = f_{s,\max}/N; ratio of max static friction to normal force, dimensionless.
Why is μ\mu dimensionless
It's force ÷ force.
On an incline, what does the slipping angle give
μs=tanθc\mu_s = \tan\theta_c (angle of repose), mass cancels.
Why does mass cancel in the incline method
Both mgsinθmg\sin\theta (driving) and mgcosθmg\cos\theta (normal) carry mgmg, which divides out.
Why must you pull at constant velocity to get μk\mu_k
Then a=0a=0, so applied force exactly equals kinetic friction.
Why is μsμk\mu_s \ge \mu_k
At rest asperities settle/cold-weld; while sliding they skim, needing less force.
Does apparent contact area affect friction
No; real contact area N\propto N, so f=μNf=\mu N regardless of apparent area.
Is μ\mu a property of one surface
No — it's a property of the pair of surfaces in contact.
Steel on ice μ\mu vs rubber on concrete μ\mu
~0.03 vs ~1.0; ice has lubricating meltwater, rubber interlocks deeply.
Static friction always equals μsN\mu_s N?
No, only at the verge of slipping; otherwise it's just enough to prevent motion.

Connections

  • Newton's Second Law — friction enters as a force term in F=ma\sum F = ma.
  • Static vs Kinetic Friction — the two regimes summarized here.
  • Inclined Plane Dynamics — same coordinate decomposition.
  • Normal Force — the NN that μ\mu multiplies.
  • Lubrication & Tribology — how films lower μ\mu.
  • Free Body Diagrams — tool used in both measurement methods.

Concept Map

defined as

independent of load

max grip case

sliding case

explains

mu_s >= mu_k

balance forces

yields

measures

F_max / mg

F_slide / mg

slide angle

Coefficient of friction mu

Ratio f over N, dimensionless

Property of surface pair

mu_s = f_s,max / N

mu_k = f_k / N

Microscopic interlock and cold-weld

Method 1: inclined plane

Method 2: horizontal pull

mu_s = tan theta_c

Mass mg cancels

Constant velocity, a=0

Hinglish (regional understanding)

Intuition Hinglish mein samjho

Friction ka coefficient μ\mu basically ek number hai jo batata hai ki do surfaces kitni "grippy" hain. Yaad rakho — yeh sirf ek surface ka nahi, balki pair ka property hota hai. "Steel ka μ\mu kya hai?" galat sawaal hai; "steel-on-ice" ya "steel-on-rubber" sahi sawaal hai. μs\mu_s (static) sliding shuru hone se pehle ka maximum grip hai, aur μk\mu_k (kinetic) sliding ke dauraan ka drag. Almost hamesha μsμk\mu_s \ge \mu_k — kyunki rukne par chhoti chhoti bumps ek doosre mein fas jaati hain (cold-welding), sliding mein woh time nahi milta.

Measure kaise karein? Sabse classy method hai inclined plane: ramp ko dheere dheere tilt karo jab tak block bilkul slip karne lage. Us critical angle θc\theta_c par mgsinθ=μsmgcosθmg\sin\theta = \mu_s\, mg\cos\theta, aur mgmg cancel ho jaata hai — toh μs=tanθc\mu_s = \tan\theta_c! Iska matlab tumhe sirf protractor chahiye, na scale na force meter. Mass matter hi nahi karta. Doosra method: horizontal mein spring balance se kheencho, jab move kare toh μs=Fmax/mg\mu_s = F_{max}/mg, aur constant velocity par kheechne par μk=F/mg\mu_k = F/mg.

Material dependence yaad rakho intuitively: rubber-on-concrete bahut grippy (μ1\mu\approx1) kyunki rubber pores mein ghus jaata hai; ice slippery (μ0.03\mu\approx0.03) kyunki meltwater lubricant ban jaata hai; oil daalo toh μ\mu gir jaata hai. Ek common galti: "zyada area = zyada friction" — yeh galat hai, kyunki real contact sirf tiny bumps par hota hai jo NN ke proportional hai, isliye apparent area cancel ho jaata hai. Bas yaad rakho: Tilt to Tan, aur Static Sticks, Kinetic Skips.

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Connections