Step 1 — Unit vector set up karo.
Line ke along ek unit vector u^ lo. Usse components mein likho:
u^=(ux,uy,uz).
Yeh step kyun? Direction ki apni koi length nahi hoti, isliye hum usse length 1 par standardise karte hain. Isse "kitna door" hat jaata hai, sirf "kaunsi disha" bachti hai.
Step 2 — Har component ko direction cosine ki tarah identify karo.u^ ka x-component x-axis par uska projection hai:
ux=u^⋅i^=cosα=l.
Isi tarah uy=cosβ=m aur uz=cosγ=n.
Yeh step kyun? Ek unit vector ka kisi axis par projection hi us axis ke saath banaye angle ka cosine hota hai — yahi dot product ka geometric matlab hai.
Step 3 — Use karo ki u^ ki length 1 hai.∣u^∣2=ux2+uy2+uz2=1.
Yeh step kyun? Yeh sirf 3D Pythagoras theorem (distance formula) hai jo ek unit vector par apply hua hai.
Agar r=(a,b,c) hai aur magnitude a2+b2+c2 hai, to
l=a2+b2+c2a,m=a2+b2+c2b,n=a2+b2+c2c.
Kyun? Kisi bhi vector ko uski length se divide karne par hamesha ek unit vector banta hai, jiske components automatically l2+m2+n2=1 satisfy karte hain.
Direction cosines ke beech relation batao. → l2+m2+n2=1.
Yeh exactly 1 kyun hota hai? → Kyunki l,m,n ek unit vector ke components hain.
Ratios (a,b,c) se cosines kaise nikaalte hain? → Har ek ko a2+b2+c2 se divide karo.
sin2α+sin2β+sin2γ kya hota hai? → 2.
Kitne direction cosines independent hote hain? → Do.
Recall Feynman: ek 12 saal ke bachche ko samjhao
Socho ek seedha teer ek kamre mein hawa mein tair raha hai. Apne dost ko batane ke liye ki yeh bilkul kaunsi disha mein point kar raha hai, tum puchho: "Yeh daayein waali deewar ki taraf kitna jhuka hai? Aage waali deewar ki taraf? Chhat ki taraf?" Har "jhukav" ek number hai −1 aur 1 ke beech. Yahan magic hai: agar teeno jhukavon ko square karo aur jodo, to HAMESHA exactly 1 milta hai — chahe teer kisi bhi disha mein point kare! Kyunki teer ki length "ek kadam" ki fixed hai, aur yeh teen jhukav yehi batate hain ki us ek kadam ka kitna hissa sideways, aage, aur upar gaya. Pythagoras ke rule se, yeh tukde milke poora kadam banana chahiye: 1.