3.1.7Advanced Trigonometry

Graphs of cosec x, sec x, cot x

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WHAT are these functions?


WHY the graphs look the way they do (derive, don't memorise)

Core reasoning tool: think about the reciprocal of a number as it changes.

Building cscx\csc x (from sinx\sin x) — HOW step by step

  1. Draw sinx\sin x lightly as a guide.
  2. Every zero of sinx\sin x (x=nπx=n\pi) becomes a vertical asymptote of cscx\csc x. Why? 1/01/0 blows up.
  3. Every maximum of sinx\sin x (sinx=1\sin x = 1) becomes a minimum of cscx\csc x at y=1y=1. Why? 1/1=11/1 = 1, and just around it the reciprocal is slightly bigger, so it's a lowest point of the upper branch.
  4. Every minimum of sinx\sin x (sinx=1\sin x = -1) becomes a maximum of cscx\csc x at y=1y=-1.
  5. Between each pair of asymptotes sits one U-shaped branch (opening up above y=1y=1, opening down below y=1y=-1).

Building secx\sec x (from cosx\cos x)

Same recipe with cosx\cos x. Because cosx=sin(x+π2)\cos x = \sin(x+\tfrac{\pi}{2}), the sec\sec graph is just the csc\csc graph shifted left by π2\tfrac{\pi}{2}. Asymptotes at x=π2+nπx = \tfrac{\pi}{2}+n\pi; touches at (0,1)(0,1), (π,1)(\pi,-1), etc.

Building cotx\cot x (from tanx\tan x)

cotx=cosxsinx\cot x = \dfrac{\cos x}{\sin x}.

  • Asymptotes where sinx=0\sin x = 0: x=nπx = n\pi (why? denominator zero).
  • Zeros where cosx=0\cos x = 0: x=π2+nπx = \tfrac{\pi}{2}+n\pi (why? numerator zero).
  • It is decreasing on every interval (nπ,(n+1)π)(n\pi,(n+1)\pi), running from ++\infty down to -\infty. (This is opposite to tanx\tan x, which increases.)
  • Period =π=\pi.
Figure — Graphs of cosec x, sec x, cot x

Key features at a glance


Worked examples


Common mistakes (Steel-man + fix)


Recall Feynman: explain to a 12-year-old

Imagine a number and its "upside-down twin" (11 over it). If the number is tiny, its twin is huge. If the number is exactly 11, the twin is also 11 — they high-five. Now sin\sin, cos\cos, tan\tan are wavy numbers. Their upside-down twins (csc,sec,cot\csc,\sec,\cot) go crazy-tall wherever the original hits zero (you draw a "wall" there — an asymptote), and they gently touch at 11 and 1-1 where the original touches its own top and bottom. So you never draw a fresh graph — you flip the one you know!


Flashcards

Where are the vertical asymptotes of cscx\csc x?
At x=nπx=n\pi (where sinx=0\sin x=0).
Where are the vertical asymptotes of secx\sec x?
At x=π2+nπx=\tfrac{\pi}{2}+n\pi (where cosx=0\cos x=0).
Where are the vertical asymptotes of cotx\cot x?
At x=nπx=n\pi (where sinx=0\sin x=0).
What is the range of cscx\csc x and secx\sec x?
(,1][1,)(-\infty,-1]\cup[1,\infty) — no values in (1,1)(-1,1).
What is the range of cotx\cot x?
All real numbers, (,)(-\infty,\infty).
Period of cscx\csc x, secx\sec x, cotx\cot x?
2π2\pi, 2π2\pi, and π\pi respectively.
Is cotx\cot x increasing or decreasing on each interval?
Decreasing (from ++\infty to -\infty).
Why has cscx\csc x no zeros?
Because 1/sinx1/\sin x can never equal 00; a fraction with numerator 11 is never zero.
At x=π2x=\tfrac{\pi}{2}, what is cscx\csc x?
11 (a minimum of the upper branch, since sin=1\sin=1).
Where does cotx=0\cot x=0?
At x=π2+nπx=\tfrac{\pi}{2}+n\pi (where cosx=0\cos x=0).
Even or odd: secx\sec x?
Even, because sec(x)=secx\sec(-x)=\sec x.
How is the secx\sec x graph related to cscx\csc x?
It is cscx\csc x shifted left by π2\tfrac{\pi}{2}.

Connections

Concept Map

generates

generates

reciprocal

reciprocal

reciprocal

zeros give

shape

u=plus or minus 1

sin bounded

shift left pi over 2

opposite of tan

Reciprocal rule y=1 over u

sin x graph

cos x graph

tan x graph

csc x

sec x

cot x

Vertical asymptotes

Touch at plus or minus 1

Forbidden band neg1 to 1

Decreasing branches

Hinglish (regional understanding)

Intuition Hinglish mein samjho

Dekho, yeh teen functions — cscx\csc x, secx\sec x, cotx\cot x — koi naye alien graph nahi hai. Ye bas sin\sin, cos\cos, tan\tan ke reciprocal (ulta, 11 divided by) hai. Toh inhe alag se ratne ki zaroorat hi nahi. Rule simple hai: jahan neeche wala part (denominator) zero hota hai, wahan graph phat jaata hai — infinity ki taraf bhaagta hai, aur wahan hum ek vertical asymptote (khadi deewar) khinch dete hai.

Jahan original function ka value 11 ya 1-1 hota hai, wahan reciprocal bhi 11 ya 1-1 hi rehta hai — matlab dono curve wahan "touch" karte hai. Aur ek important baat: kyunki sin\sin aur cos\cos kabhi 11 se zyada nahi hote, unke reciprocal csc\csc aur sec\sec kabhi bhi 1-1 aur 11 ke beech nahi aa sakte. Yeh "forbidden band (1,1)(-1,1)" bahut common exam trap hai.

cotx\cot x thoda special hai: iski asymptotes wahan hai jahan sin=0\sin=0 (x=nπx=n\pi), aur zeros wahan jahan cos=0\cos=0. Aur yaad rakho — tan\tan badhta hai par cot\cot har interval me ghatata hai. Mnemonic: "co-sec aur co-tangent, dono sine ke saath mrte hai; se-C cosine ke saath." Bas graph flip karo, ratna band karo — exam me time bachega aur galti kam hogi.

Go deeper — visual, from zero

Test yourself — Advanced Trigonometry

Connections