3.1.7 · Maths › Advanced Trigonometry
Ye teeno functions sin , cos , tan ke reciprocals hain. Isliye inki poori shape ek simple rule se decide hoti hai: jahan denominator zero hota hai, wahan graph ± ∞ tak blast ho jaata hai (vertical asymptote); jahan denominator ± 1 hota hai, wahan reciprocal bhi ± 1 hota hai (woh touch karte hain). Agar tumhare paas sine/cosine/tangent ke graphs pehle se hain, toh ye teeno tumhe free mein mil jaate hain — inhe alag se memorise karne ki zaroorat nahi.
Definition Reciprocal trig functions
csc x = s i n x 1 , sec x = c o s x 1 , cot x = s i n x c o s x = t a n x 1
csc x (cosecant) undefined hota hai jahan bhi ==sin x = 0 == ho, yaani x = nπ .
sec x (secant) undefined hota hai jahan bhi ==cos x = 0 == ho, yaani x = 2 π + nπ .
cot x (cotangent) undefined hota hai jahan bhi ==sin x = 0 == ho, yaani x = nπ .
Core reasoning tool: ek number ke reciprocal ke baare mein socho jab woh change hota hai.
sin x ko lightly guide ke taur par draw karo.
sin x ka har zero (x = nπ ) csc x ka vertical asymptote ban jaata hai. Kyun? 1/0 blow up karta hai.
sin x ka har maximum (sin x = 1 ) csc x ka minimum ban jaata hai y = 1 par. Kyun? 1/1 = 1 , aur iske aas-paas reciprocal thoda bada hota hai, isliye yeh upper branch ka sabse neecha point hai.
sin x ka har minimum (sin x = − 1 ) csc x ka maximum ban jaata hai y = − 1 par.
Har do asymptotes ke beech ek U-shaped branch hoti hai (upar y = 1 ke oopar khulti hai, neeche y = − 1 ke neeche khulti hai).
Same recipe cos x ke saath. Kyunki cos x = sin ( x + 2 π ) hai, sec graph sirf csc graph ka left shift hai 2 π se . Asymptotes x = 2 π + nπ par; touch hota hai ( 0 , 1 ) , ( π , − 1 ) , etc. par.
cot x = sin x cos x .
Asymptotes jahan sin x = 0 ho: x = nπ (kyun? denominator zero).
Zeros jahan cos x = 0 ho: x = 2 π + nπ (kyun? numerator zero).
Yeh har interval ( nπ , ( n + 1 ) π ) par decreasing hai, + ∞ se − ∞ tak jaata hai. (Yeh tan x ke opposite hai, jo increase karta hai.)
Period = π .
( 0 , π ) par csc x ki ek branch sketch karo
Step: Endpoints x → 0 + aur x → π − asymptotes hain. Kyun? sin 0 = sin π = 0 .
Step: x = 2 π par, sin = 1 isliye csc = 1 — sabse neecha point. Kyun? 1/1 = 1 , upar kholne wali U ka minimum.
Result: Ek U shape jo poori tarah y = 1 par ya uske oopar baithi hai, minimum ( 2 π , 1 ) .
cot x = 0 kahan hota hai?
Step: cot x = cos x / sin x = 0 ⇒ cos x = 0 (aur sin x = 0 ). Kyun? Ek fraction tabhi zero hota hai jab uska numerator zero ho.
Result: x = 2 π + nπ . Ye asymptotes ke bilkul beech mein hain — falling-through-zero shape se match karta hai.
Worked example 4. Forecast-then-verify:
csc ( 6 7 π ) ki value
Forecast: 6 7 π third quadrant mein hai, sin negative hai, isliye csc bhi ≤ − 1 hona chahiye.
Verify: sin 6 7 π = − 2 1 ⇒ csc = − 2 . ✓ Sach mein ≤ − 1 hai, forbidden band ka respect karta hai.
csc x ka graph y = 0 se guzar sakta hai."
Kyun sahi lagta hai: sin x 0 se guzarta hai, isliye log wahi copy kar lete hain. Sach: precisely un hi points par csc x undefined hota hai — zero se divide kar rahe ho. Fix: sin ke zeros csc ke asymptotes ban jaate hain, zero-crossings nahi. csc x ke koi zeros hi nahi hote.
csc x sin x ki tarah saari values leta hai."
Kyun sahi lagta hai: dono related hain, isliye ranges similar lagti hain. Sach: sin x ∈ [ − 1 , 1 ] isliye uske reciprocal ki magnitude ≥ 1 hoti hai. Fix: range hai ( − ∞ , − 1 ] ∪ [ 1 , ∞ ) — open band ( − 1 , 1 ) mein kuch nahi rehta.
cot x tan x ki tarah increase karta hai."
Kyun sahi lagta hai: yeh sirf 1/ tan hai, isliye log same trend assume kar lete hain. Sach: reciprocal lene se trend ulta ho jaata hai; saath hi cot x = − tan ( x − 2 π ) mein ek minus sign bhi hai. Fix: cot x har period par decrease karta hai.
sec ke asymptotes x = nπ par rakhna.
Kyun sahi lagta hai: csc / cot ke saath confuse ho jaate hain. Fix: sec wahan blow up karta hai jahan cos = 0 ho, yaani x = 2 π + nπ .
Recall Feynman: ek 12-saal ke bachche ko samjhao
Ek number aur uske "ulte twin" (1 us par) ke baare mein socho. Agar number tiny hai, toh uska twin bahut bada hai. Agar number exactly 1 hai, toh twin bhi 1 hai — dono high-five karte hain. Ab sin , cos , tan wavy numbers hain. Inke ulte twins (csc , sec , cot ) jahan bhi original zero ho wahan crazy-tall ho jaate hain (wahan ek "deewar" draw karo — asymptote), aur jahan original apne top aur bottom ko touch kare wahan 1 aur − 1 par gently touch karte hain. Isliye tum koi fresh graph nahi banate — jo graph tumhe pata hai, usse hi flip kar do!
Asymptotes ke liye "Co-Ca-Co" : Co secant aur Co tangent wahan khatam hote hain jahan sine khatam hoti hai (x = nπ ); SeCa nt wahan khatam hota hai jahan cosine khatam hoti hai (x = 2 π + nπ ). Saath hi: "3rd letter rule" — co S ec Sine ke saath pair karta hai, se C Cosine ke saath pair karta hai.
csc x ke vertical asymptotes kahan hain?x = nπ par (jahan sin x = 0 ho).
sec x ke vertical asymptotes kahan hain?x = 2 π + nπ par (jahan cos x = 0 ho).
cot x ke vertical asymptotes kahan hain?x = nπ par (jahan sin x = 0 ho).
csc x aur sec x ka range kya hai?( − ∞ , − 1 ] ∪ [ 1 , ∞ ) — ( − 1 , 1 ) mein koi value nahi.
cot x ka range kya hai?Saare real numbers, ( − ∞ , ∞ ) .
csc x , sec x , cot x ka period?Krama se 2 π , 2 π , aur π .
cot x har interval par increasing hai ya decreasing?Decreasing (from + ∞ to − ∞ ).
csc x ke zeros kyun nahi hote?Kyunki 1/ sin x kabhi 0 nahi ho sakta; numerator 1 wala fraction kabhi zero nahi hota.
x = 2 π par csc x kya hai?1 (upper branch ka minimum, kyunki sin = 1 ).
cot x = 0 kahan hota hai?x = 2 π + nπ par (jahan cos x = 0 ho).
Even ya odd: sec x ? Even, kyunki sec ( − x ) = sec x .
sec x graph csc x se kaise related hai?Yeh csc x ka 2 π left shift hai.
Reciprocal rule y=1 over u