3.1.6Advanced Trigonometry

Graphs of sin x, cos x, tan x — key features, period, amplitude

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1. Building sin and cos from the circle

WHY the range is [1,1][-1,1]: the point lives on a circle of radius 11, so neither coordinate can ever exceed 11 in size. Hence 1sinx1,1cosx1.-1 \le \sin x \le 1, \qquad -1 \le \cos x \le 1.

WHY they repeat: going once round the circle is 360=2π360^\circ = 2\pi radians. After that you are at the same point, so the values repeat. This "repeat length" is the period.

Figure — Graphs of sin x, cos x, tan x — key features, period, amplitude

2. Reading off key points

Track the moving point at the four "corners" of the circle:

Angle xx Point on circle cosx\cos x sinx\sin x
00 right (1,0)(1,0) 11 00
π/2\pi/2 top (0,1)(0,1) 00 11
π\pi left (1,0)(-1,0) 1-1 00
3π/23\pi/2 bottom (0,1)(0,-1) 00 1-1
2π2\pi back to right 11 00

Key features to say out loud:

  • sinx\sin x: passes through origin, odd (rotational symmetry about 00: sin(x)=sinx\sin(-x)=-\sin x), max at π/2\pi/2, min at 3π/23\pi/2, zeros at 0,π,2π,0,\pi,2\pi,\dots
  • cosx\cos x: starts at max, even (mirror symmetry in yy-axis: cos(x)=cosx\cos(-x)=\cos x), zeros at π/2,3π/2,\pi/2, 3\pi/2,\dots

3. Building tan from sin and cos

WHY the vertical asymptotes: wherever cosx=0\cos x=0 (at x=±π2, ±3π2,x=\pm\tfrac{\pi}{2},\ \pm\tfrac{3\pi}{2},\dots) we divide by zero, so tanx\tan x shoots to ±\pm\infty. These are vertical asymptotes at x=π2+nπx=\tfrac{\pi}{2}+n\pi.

WHY the period is π\pi, not 2π2\pi (derivation): Move half a turn round the circle (xx+πx\to x+\pi). The point flips to the exact opposite side, so both coordinates negate: sin(x+π)=sinx,cos(x+π)=cosx.\sin(x+\pi)=-\sin x,\qquad \cos(x+\pi)=-\cos x. Therefore tan(x+π)=sinxcosx=sinxcosx=tanx.\tan(x+\pi)=\frac{-\sin x}{-\cos x}=\frac{\sin x}{\cos x}=\tan x. The two minus signs cancel, so tan\tan repeats twice as fast: period =π=\pi.


4. Transformations (WHAT each number does)

For y=Asin(Bx+C)+Dy=A\sin(Bx+C)+D:


5. Worked examples


6. Common mistakes (Steel-manned)


7. Active recall

Recall Test yourself (hide the answers)
  • What are the coordinates of a unit-circle point at angle xx? → (cosx,sinx)(\cos x,\sin x)
  • Why is the range of sin\sin exactly [1,1][-1,1]? → radius is 1, coordinate can't exceed it
  • Why is tan's period π\pi? → both sin, cos negate at +π+\pi, signs cancel in ratio
  • Period of y=5cos(x2)y=5\cos(\tfrac{x}{2})? → 2π/(1/2)=4π2\pi/(1/2)=4\pi; amplitude 55
Recall Feynman: explain to a 12-year-old

Imagine a kid on a Ferris wheel going round and round. How high they are above the middle, drawn against time, makes a smooth up-and-down wave — that's sine. How far left/right they are makes the same wave but starting from the top — that's cosine. Both waves repeat every full circle. Tan is a sneaky one: it's "height divided by sideways", and every time the kid passes straight up or straight down, the "sideways" becomes zero, so dividing by it makes the number blow up to a cliff. That's why tan has those steep walls (asymptotes) and repeats twice as often.


Connections

Coordinates of a unit-circle point at angle x
(cosx,sinx)(\cos x, \sin x)
Period of sin x and cos x
2π2\pi
Period of tan x
π\pi
Amplitude of sin x and cos x
11
Amplitude of tan x
undefined (unbounded)
Range of sin x and cos x
[1,1][-1,1]
Range of tan x
all real numbers
Why does tan x have period π
sin and cos both negate at x+π, so the two minus signs cancel in sin/cos
Where are tan x's asymptotes
where cos x = 0, i.e. x=π2+nπx=\tfrac{\pi}{2}+n\pi
Zeros of sin x
x=nπx=n\pi
Zeros of cos x
x=π2+nπx=\tfrac{\pi}{2}+n\pi
cos x in terms of sin
cosx=sin(x+π2)\cos x = \sin(x+\tfrac{\pi}{2})
Period of y=A sin(Bx)
2π/B2\pi/|B|
Period of y=tan(Bx)
π/B\pi/|B|
Amplitude of y=A sin(Bx)+D
A|A|
Is sin x odd or even
odd, sin(x)=sinx\sin(-x)=-\sin x
Is cos x odd or even
even, cos(x)=cosx\cos(-x)=\cos x

Concept Map

y-coord gives

x-coord gives

on radius 1 so

one lap = 2 pi

half of swing

quarter turn ahead

divided by cos

divided into sin

where cos=0

repeats every

Unit circle radius 1

cos x = x-coordinate

sin x = y-coordinate

Range -1 to 1

Period 2 pi

Amplitude 1

cos = sin shifted

tan x = sin/cos

Vertical asymptotes

tan period pi

Hinglish (regional understanding)

Intuition Hinglish mein samjho

Socho ek point unit circle (radius 1) par anticlockwise ghoom raha hai, aur xx uska angle hai. Us point ki height yani y-coordinate hoti hai sinx\sin x, aur uski horizontal distance yani x-coordinate hoti hai cosx\cos x. Bas isi ek picture se saari cheezein nikal aati hain — koi ratta nahi maarna. Radius 1 hai isliye height ya width kabhi 1 se zyada nahi ho sakti, tabhi range [1,1][-1,1] aata hai. Ek poora chakkar 2π2\pi ka hota hai, isliye graph har 2π2\pi baad repeat karta hai — yahi hai period, aur half-swing =1=1 hai isliye amplitude =1=1.

tanx=sinx/cosx\tan x = \sin x / \cos x — yani height bata width. Jahan bhi cosx=0\cos x = 0 hota hai (top ya bottom point, x=π/2x=\pi/2 type), wahan width zero ho jaati hai, aur zero se divide karne par value ±\pm\infty tak udd jaati hai — yeh hote hain vertical asymptotes. Aur ek mast baat: half-turn (x+πx+\pi) par sin aur cos dono ka sign ulta ho jaata hai, lekin ratio mein dono minus cancel ho jaate hain, isliye tan\tan ka period sirf π\pi hota hai, na ki 2π2\pi. Yeh point exam mein bahut students galat karte hain.

Transformation yaad rakho y=Asin(Bx+C)+Dy=A\sin(Bx+C)+D mein: AA height stretch karta hai (amplitude =A=|A|), BB speed badhata hai isliye period chhota ho jaata hai =2π/B=2\pi/|B| (multiply nahi, divide!), CC left-right shift, DD upar-neeche shift. Yeh chhoti si samajh 80% questions cover kar deti hai. Ferris wheel wali picture dimaag mein rakho — sab kuch apne aap click ho jayega.

Go deeper — visual, from zero

Test yourself — Advanced Trigonometry

Connections