This page assumes nothing. Every squiggle, letter, and arrow the parent note throws at you gets built here from the ground up. Read it top to bottom — each block earns the symbol used in the next.
Everything in this topic lives in the AC world. So the very first thing to see is that wave.
Figure 1 — Two voltage-vs-time graphs. The flat yellow horizontal line is DC (a steady, unchanging push). The blue wave is AC (the push swings positive then negative). The red double-arrow marks one cycle: one full up-then-down-then-back trip.
The wave repeats. One full up-then-down-then-back is called one cycle. Hold that picture — every symbol below is a way of describing this wave precisely.
Why a cosine, cos? A cosine is nature's smoothest back-and-forth. Picture a dot going around a circle at steady speed: its horizontal shadow traces a cosine as time passes. AC voltage behaves exactly like that shadow. We are nearly ready to write the formula — but it needs one more symbol, the spin-speed, which we build in §3. For now just hold the shape in mind.
Figure 2 — On the left, a white circle with a yellow radius arm; the red dot spins around it. Its green horizontal shadow (dashed) drops onto the axis. On the right, that shadow, plotted against time, traces the blue cosine curve. This is why AC voltage is a cosine: it is the shadow of steady circular motion.
Why do we need ω when we already have f? Because the cosine "thinks" in angle, not in cycles. One full trip around the circle is 2π radians (a radian is just a way to measure angle where a full circle =2π≈6.28). So each second the dot sweeps 2π radians per cycle, f cycles' worth:
Now — with Vm, t, and ω all defined — we can finally write the AC voltage wave:
Two waves of the same speed can still be shifted — one crests while the other is still climbing. That shift is a phase.
Lag = arrives later (behind). "Current lags" → current crests after voltage does.
Lead = arrives earlier (ahead). "Current leads" → current crests before voltage does.
Figure 3 — The yellow curve is voltage, the blue curve is current. The blue crest sits a quarter-cycle to the right of the yellow crest, marked by the red 90° double-arrow: the current lags the voltage. This quarter-cycle offset is exactly what the symbol j (§7) will encode.
This picture is the entire reason the topic needs complex numbers: we must carry both a height and a shift. Keep it in mind for §7.
See Ohm's Law for the deep version. This topic's whole plan is: keep this law, but replace the plain fight R with a smarter fight Z that also remembers timing.
The parent note's derivations use two calculus tools. Here's each from zero.
Why we need it: an inductor's whole personality is "I fight changes in current," so we literally need a symbol for "rate of change of current." That's dtdi.
Why we need it: if we know a voltage is forcing a certain rate of current change, undoing that (integrating) tells us the current itself. That's the step i(t)=L1∫Vmcos(ωt)dt.
Two facts we'll use: the slope of cos is −sin, and adding up (integrating) cos gives +ω1sin. The ω1 appears because each wiggle is ω times faster, so its total per push is ω times smaller — this ω1 is where reactance's frequency-dependence is born.
Drive it with v(t)=Vmcos(ωt) and find the current. Since vL=Ldtdi, we rearrange to dtdi=LVmcos(ωt) and integrate (undo the slope, §6):
i(t)=L1∫Vmcos(ωt)dt=ωLVmsin(ωt)What we did: used integrating-cos-gives-ω1sin. Why: to turn "voltage forces a rate" into the current itself. The peak current is Im=ωLVm. Compare with Ohm's Law Im=Vm/X — the "fight" is:
Drive it with v(t)=Vmcos(ωt) and take the slope (§6, slope of cos is −sin):
i(t)=Cdtd(Vmcosωt)=−ωCVmsin(ωt)
The peak current is Im=ωCVm, so Vm/Im=ωC1:
From §4 we need a number that carries two facts (height and shift) at once. A plain number can't. A complex number can.
The concrete "why" — how j, ω1, L and C combine into impedance. Instead of carrying sin and cos around, we let the driving voltage be a rotating arrow and ask what "fight" each component applies to it. The key rule is that taking a slope (dtd) of such a rotating arrow is the same as multiplying by jω (it speeds up by ωand turns the timing by 90°, which is exactly what j does):
Inductor:v=Ldtdi⟶ "fight" =iv=jωL. Its size is ωL=XL (matching §7), and the j says "+90°, current lags."
Capacitor:i=Cdtdv⟶ "fight" =iv=jωC1=−ωCj. Its size is ωC1=XC, and the −j says "−90°, current leads." (Here j1=−j because j⋅(−j)=−j2=1 — this is precisely where the capacitor's minus comes from.)
A complex number is written a+jb: a is the real part (in-step, horizontal axis) and b is the imaginary part (90°-shifted, vertical axis). Draw it as an arrow from the origin — its length is the size, its angle is the timing. See Complex Numbers and Phasors.
Combining the components in series adds the fights: Z=R+j(XL−XC). This is an arrow with horizontal leg R and vertical leg X=XL−XC. We need its length and angle.
Why these two and nothing else? Because R points horizontally and X points vertically — they meet at exactly 90°, forming a right triangle. Right triangles are precisely what Pythagoras (length) and tan−1 (angle) were built for.
Figure 4 — The impedance arrow (red) from the origin. Its horizontal green leg is R (real, in-step); its vertical blue leg is X=XL−XC (imaginary, 90°-shifted). The red hypotenuse length is ∣Z∣=R2+X2; the yellow arc is the phase angle ϕ.
So the parent's headline results are just "length of the arrow" and "angle of the arrow":
∣Z∣=R2+(XL−XC)2,ϕ=tan−1RXL−XC
Here ∣Z∣ (bars mean length/magnitude) is the total opposition; ϕ is the phase shift of §4.