Intuition The one core idea
Inside a sealed box of reacting gases, "how crowded a gas is" (concentration) and "how hard it pushes on the walls" (pressure) are the same thing scaled by R T . Because of this, the two ways of writing an equilibrium constant — K c from crowding and K p from pushing — differ only by a factor of R T raised to a small whole number, and that number is just the change in how many gas molecules exist.
Before we can trust the formula K p = K c ( R T ) Δ n , we must earn every single symbol in it. This page is the toolbox. We open every drawer, name every tool, draw the picture it stands for, and say why the topic can't work without it. Nothing here assumes you've seen chemistry notation before.
Definition A reversible reaction
When we write
a A + b B ⇌ c C + d D
we mean: substances A and B turn into C and D , and C and D turn back into A and B , at the same time.
A , B , C , D = the chemical species (the kinds of molecules). Think of them as four different colours of marble.
a , b , c , d = the coefficients — how many of each marble the recipe uses. If a = 1 , b = 3 , then "1 of A plus 3 of B."
⇌ = the double arrow : the reaction runs both ways at once .
Intuition Why the double arrow, not a single one?
A single arrow → means "goes to completion and stops." The double arrow means the forward and backward changes never stop — they just reach a balance where the amounts stop appearing to change. That balance is what the whole chapter (equilibrium) is about. Without it, there would be no constant K to talk about.
Figure 1 — the two teams. The left lavender box holds the reactants (a A + b B ): four big lavender marbles (species A ) and three small coral marbles (species B ). The right mint box holds the products (c C + d D ). The two arrows between them — coral pointing right ("forward"), lavender pointing left ("backward") — are the double arrow ⇌ drawn as motion: both changes happen at once. Every symbol later in this page is really a question about these two teams.
Definition Molar concentration
[ X ] (read "concentration of X ", the square brackets are just shorthand) means:
[ X ] = V n X = volume of box moles of X ( unit: mol L − 1 )
Picture a box of fixed size. Count how many molecules of one kind are packed inside, then divide by the box's volume. ==More molecules in the same box = higher concentration = more crowded.==
Intuition Why concentration and not just "number of molecules"?
Two boxes might hold the same number of molecules but one is tiny and one is huge — the tiny one is far more crowded, and crowding is what drives reactions. Dividing by volume V removes the "how big is the box" question and leaves pure crowding. This is exactly the ingredient K c is built from.
Here n X = number of moles of X (a mole is just "a fixed huge count of molecules" — like a "dozen" but enormous). V = volume of the container in litres (L).
Definition Partial pressure
p X = the pressure that gas X on its own would exert on the walls of the box, ignoring all the other gases.
Picture only the red molecules in a mixture, drumming on the walls. The force per unit area from just those is p X .
In a mixture, several gases share the same box and all hammer the walls together. Dalton's Law says the total push is just the sum of each gas pushing separately: p total = p A + p B + … . So each gas gets a "partial" share of the total pressure. K p is built from these partial pressures — one per gas.
Figure 2 — same box, two descriptions. The left (butter) panel describes the gas by crowding : count the coral marbles and divide by the litres of box → concentration [ X ] , which feeds K c . The right (lavender) panel describes the same gas by pushing : the little grey arrows are molecules hammering the walls → partial pressure p X , which feeds K p . The coral caption between them, p X = [ X ] × R T , is the bridge that turns one description into the other — the single equation the whole topic rests on.
Definition The ideal gas law
For a gas in a container:
p V = n R T
p = pressure (push on walls)
V = volume of the box
n = number of moles of gas
R = the gas constant (a fixed conversion number, explained below)
T = temperature, in kelvin (explained below)
See Ideal Gas Law PV=nRT for the full story.
Common mistake The ideal-gas assumption is hidden but real
p V = n R T is exact only for an ideal gas — one whose molecules take up no volume of their own and don't attract each other. Real gases obey it approximately , and the approximation is excellent at ordinary lab pressures and above room temperature. Every step on this page (including p X = [ X ] R T and the final K p = K c ( R T ) Δ n ) inherits this assumption. At very high pressure or very low temperature it would need corrections — but for exam-level equilibrium problems we treat all gases as ideal.
Intuition Why THIS law, and no other?
We need a rule that connects pushing (p ) to crowding (n / V ). The ideal gas law is exactly that rule. Rearrange it for one gas X :
p X = V n X R T = [ X ] R T
Read this out loud: push = crowd × R T . This single equation is the whole engine of the topic. Every partial pressure can be swapped for "concentration times R T ," which is how K p gets rewritten in terms of K c .
R — the unit-matching number
R is a fixed number that makes p V = n R T balance. Its numerical value depends on which units you use — and crucially, the volume V inside p V = n R T must use the same volume unit as your concentration (litres with mol L⁻¹, cubic metres with mol m⁻³). Never mix L and m³.
Pressure unit
Concentration / volume unit
R
atm
mol L⁻¹ (so V in L)
0.0821 L atm K − 1 mol − 1
bar
mol L⁻¹ (so V in L)
0.08314 L bar K − 1 mol − 1 (≈ 0.083 )
Pa (SI)
mol m⁻³ (so V in m³)
8.314 J K − 1 mol − 1
R have different values?
R is like a currency-exchange rate. The amount of money is the same, but "how many dollars" versus "how many rupees" gives different numbers. Same physics, different unit-labels, so different numeric R . You must pick the R whose labels match your K p and K c — and, since V lives inside the same law, make sure V 's unit matches too (litres with the L-based R , cubic metres with the SI R ).
T — temperature in kelvin
Kelvin is temperature counted from absolute zero (the coldest possible), not from water's freezing point.
T ( K ) = T ( ° C ) + 273.15
Picture a thermometer whose zero is the point where all molecular motion stops. (In most textbook problems the offset is rounded to 273 ; the exact value is 273.15 .)
Common mistake Using Celsius in the gas law
Wrong: plugging T = 27 for room temperature.
Why it feels right: 27 °C is room temperature.
Fix: p V = n R T only balances in absolute temperature. Convert: T = 27 + 273.15 = 300.15 K (usually rounded to 300 K ). Using 27 would make R T almost eleven times too small.
K
The Law of Chemical Equilibrium says: at balance, this specific combination stays constant.
K c = [ A ] a [ B ] b [ C ] c [ D ] d , K p = p A a p B b p C c p D d
Read the pattern: products on top , reactants on bottom , each raised to the power of its coefficient .
K c uses crowding (concentrations) — see the Kp note for its pressure cousin.
K p uses pushing (partial pressures).
Common mistake Pure solids and liquids do NOT appear in
K c or K p at all
When you build the fraction above, leave out every pure solid and pure liquid — only gases (and, in K c , dissolved species) go in. The reason: a pure solid or liquid has a fixed "activity" of exactly 1 , so including it just multiplies by 1 and changes nothing. Example: for C a C O 3 ( s ) ⇌ C a O ( s ) + C O 2 ( g ) , both K c = [ C O 2 ] and K p = p C O 2 — the two solids are absent. (This is the same rule that later makes us count only gases in Δ n .)
Intuition Why raise to the coefficient power?
If the recipe uses 3 molecules of B , then B 's crowding matters three times over (once per molecule involved), which multiplication-wise means [ B ] 3 . The exponent is just the coefficient b . This is why the a , b , c , d from Section 1 reappear as powers here.
Common mistake Putting reactants on top
K is always products-over-reactants. Flipping it gives 1/ K , a different number. Memory hook: "K for Konstant, products Kome first."
Definition The summation symbol
∑
∑ (Greek capital sigma) just means "add up." ∑ n gas, products means "add the coefficients of all gaseous products."
Δ n — the change in gas moles
The Greek letter Δ ("delta") means "change in" — a final value minus a starting value.
Δ n = gas product moles ( c + d ) − gas reactant moles ( a + b )
In words: (total moles of gas on the product side) minus (total moles of gas on the reactant side).
Figure 3 — counting Δ n . Using N 2 ( g ) + 3 H 2 ( g ) ⇌ 2 N H 3 ( g ) : the left lavender box counts the reactant gas moles (1 + 3 = 4 marbles), the right mint box counts the product gas moles (2 marbles). Subtract product minus reactant: Δ n = 2 − 4 = − 2 . The coral arrow reminds you which side is subtracted from which — always products minus reactants, never the reverse.
Δ n matter at all?
When we swap every p X for [ X ] R T , each species drags one factor of R T along with it. Products contribute R T powers on top; reactants contribute them on the bottom. What survives is R T raised to (top powers − bottom powers), which is exactly Δ n . The next section shows this cancellation explicitly, line by line.
Words like "each species drags one factor of R T " are only convincing if we watch it happen. Here is the complete algebra, starting from K p and using the bridge p X = [ X ] R T from Section 4.
Every tool now has a name, a picture, and a reason:
Symbol
Plain meaning
Why the topic needs it
⇌
reaction runs both ways (Fig 1)
there's a balance to have a constant for
[ X ]
concentration / crowding (Fig 2, left)
builds K c
p X
partial pressure / pushing (Fig 2, right)
builds K p
p V = n R T
push = crowd × R T (ideal gas)
the bridge p X = [ X ] R T
R
unit-matching number
scales push↔crowd
T
temperature (kelvin)
appears in R T
K c , K p
equilibrium constants
the two things we relate
Δ n
change in gas moles (Fig 3)
the exponent of R T
Once these are in hand, the parent formula K p = K c ( R T ) Δ n is nothing more than "swap push for crowd, collect the leftover R T 's" — exactly the five steps of Section 8.
Reversible reaction double arrow
Concentration X = n over V
Gas constant R matches units
Kp from partial pressures
Delta n = product minus reactant gas moles
Kp = Kc RT to the Delta n
What does the double arrow ⇌ mean? The reaction runs forward and backward at the same time, reaching a balance (equilibrium).
What is [ X ] and its unit? Molar concentration n X / V , moles per litre (mol L⁻¹) — how crowded gas X is.
What is a partial pressure p X ? The pressure gas X would exert alone, ignoring the other gases in the mixture.
State the ideal gas law and the bridge it gives (and its assumption). p V = n R T for an ideal gas, giving p X = ( n X / V ) R T = [ X ] R T .
Why does R have different numeric values, and what must V match? It matches the chosen pressure/volume units (atm+L, bar+L, Pa+m³); V in p V = n R T must use the same volume unit as the concentration.
Convert 27 °C to the temperature used in the gas law. 27 + 273.15 = 300.15 K (often rounded to 300 K ).
Write the general form of K c , and what is left out. Products over reactants each to its coefficient, [ A ] a [ B ] b [ C ] c [ D ] d ; pure solids and liquids are omitted (activity = 1).
Define Δ n . Moles of gaseous products minus moles of gaseous reactants (products − reactants).
Which species are excluded from Δ n ? Solids and liquids — only gases are counted.
Why does Δ n become the exponent of R T ? Each gas swaps p X for [ X ] R T ; the R T 's collect as (product powers − reactant powers) = Δ n .