Intuition The ONE core idea
A flying rocket only ever does two kinds of thing: its center point moves through space, and its body twists around that point. Everything in the 6DOF equations is just careful bookkeeping of how fast those two things change — and the trick is that "how fast" looks different to someone standing on the ground than to someone riding the rocket, so we need a tool to translate between the two viewpoints.
Before you can read the parent note, you need to own every symbol it throws at you. This page builds each one from nothing — plain words, a picture, and the reason the topic can't live without it. Read top to bottom; each block leans on the one above it.
An object whose parts never change their distances from each other — it can move and spin, but it can't bend, stretch, or squish.
Think of a solid steel rocket versus a floppy noodle. The rocket is rigid: if you know where one bolt goes and how the whole thing is turned, you know where every bolt is. That's why we can describe the entire rocket with just one point (its balance point) plus one orientation (how it's twisted). Six numbers total — the six degrees of freedom.
Why the topic needs it: the clean split into "point moves" + "body twists" is a theorem that only holds for rigid bodies . A noodle would need infinitely many numbers.
A
A quantity with both a size and a direction . We draw it as an arrow: length = size, way-it-points = direction.
"The rocket moves 300 m/s north-east and up " is a vector. "The temperature is 20°" is not — it has no direction. Force, velocity, and spin-rate are all arrows; that's why they wear the little hat: F , v , ω .
A vector in 3D is really three numbers stacked — one for each axis. Look at the figure: the arrow A casts a shadow onto each axis, and those three shadow-lengths A x , A y , A z are its components . Writing A = A x e ^ x + A y e ^ y + A z e ^ z just means "walk A x along x , then A y along y , then A z along z , and you land at the arrow tip."
e ^ x , e ^ y , e ^ z
Three arrows of length exactly 1 , pointing along the three axes. The little hat ^ means "length one" (a unit vector). They are the "one step" in each direction that we scale and add to build any vector.
Why the topic needs it: every quantity in 6DOF (force, velocity, spin) is a vector, and the transport theorem is derived by asking how the basis vectors e ^ i themselves move when the rocket turns.
d t d A , also written A ˙
"How fast A is changing right now, per second." The single dot on top is shorthand for one time-derivative.
Zoom in on a tiny slice of time d t . The arrow A nudges to a slightly new arrow. The difference between them, divided by that tiny time, is A ˙ — itself an arrow pointing in the direction the tip is drifting.
Why the topic needs it: Newton's law and Euler's law are both statements about a rate of change — momentum's rate equals the push. Without the dot there is no law.
v , components ( u , v , w )
The rate of change of the center-of-mass position — how fast, and which way, the rocket's balance point is flying. In body axes we name its three components u (forward), v (sideways), w (up/down).
Definition Angular velocity
ω , components ( p , q , r )
One arrow that captures all the spinning at once. Its direction = the axis the body turns about (by the right-hand rule); its length = how fast (radians per second). Components: p = roll (barrel-roll about the nose axis), q = pitch (nose up/down), r = yaw (nose left/right).
Intuition Why spin needs an
arrow , not just a number
A spin has to say which axis and how fast . Point your right thumb along ω and your curling fingers show the way the body turns (look at the figure). Roll, pitch, yaw are simply this one arrow's shadows on the three body axes — exactly like A 's shadows in §1.
"p-q-r spins Roll-Pitch-yaw, in that order x-y-z." p ↔x ↔roll, q ↔y ↔pitch, r ↔z ↔yaw.
Why the topic needs it: v is the star of Newton's equation, ω the star of Euler's. Both equations carry a "ω × " term, so you must first know what ω is .
a × b
Takes two arrows and makes a third arrow that is perpendicular to both . Its length is ∣ a ∣ ∣ b ∣ sin θ (largest when the two are at right angles, zero when they point the same way).
Intuition The picture — why this exact tool?
Question we're answering: "If a point sits on a spinning body, which way and how fast does it fly?" The answer must be sideways to both the spin-axis and the point's position — that is precisely what a cross product produces. That's why ω × A , and not addition or a dot product, shows up: only the cross product turns "spin" into "the sideways velocity spinning causes."
Look at the figure: a point at position A on a body spinning at ω swings along the green arrow ω × A — tangent to its circle, at right angles to both the axis and the radius.
Common mistake The zero case people forget
If A points along the spin axis (parallel to ω ), then sin θ = sin 0 = 0 , so ω × A = 0 . Meaning: a point on the axis doesn't move — it's the still center of the spin. Always check this degenerate case; it's why a spin-stabilized rocket's nose (on-axis) stays put while its fins whirl.
Why the topic needs it: the whole reason the body-frame equations differ from the ground-frame ones is this ω × term. It is the transport theorem's punchline.
Two cameras film the same rocket. The ground camera (I ) sees the true acceleration Newton talks about. The onboard camera (B ) is easiest for reading instruments (a thruster always points along body-x ) — but it's itself spinning , so what it measures as "not changing" may actually be changing to the ground camera. The gap between the two cameras is exactly one ω × .
Why the topic needs it: this is the central tension the parent note resolves. Measure in B , but the law lives in I — the transport theorem is the bridge. See Reference frames and rotation matrices and Transport theorem (rotating frames) to go deeper.
m · Momentum p = m v · Force F
Mass = how much stuff (one number, its stubbornness against speeding up). Momentum = mass × velocity, "how much oomph is moving." Force = a push or pull (an arrow).
Newton's law F = p ˙ reads: the push equals how fast the oomph changes. For fixed mass this is the familiar F = m a . For a rocket, mass drops as fuel burns — that subtlety is handled in Meshchersky / Tsiolkovsky variable-mass dynamics , but foundationally you just need "push changes momentum."
Why the topic needs it: these three are the entire cast of the translational equation.
Definition Inertia tensor
I
The rotational version of mass — but because a body resists twisting differently about different axes , one number isn't enough. I is a 3 × 3 block of numbers (a tensor ) that stores "how hard to spin about each axis."
Intuition The picture — why a tensor, not a scalar?
Spin a pencil about its long thin axis: easy. Spin it end-over-end: harder. Same object, different resistance depending on axis. A single number can't say that; you need a table — the tensor. On the special principal axes the table simplifies to just three numbers on its diagonal, diag ( I x , I y , I z ) . (See Inertia tensor and principal axes .)
Definition Angular momentum
H = I ω
The "rotational oomph." Feeding the spin arrow ω through the resistance-table I gives H . Crucially H need not point the same way as ω — twisting about an easy axis and a hard axis at once tilts H away from the spin. That tilt is the seed of tumbling (Angular momentum conservation , Dzhanibekov effect / intermediate axis theorem ).
Definition Moment / torque
M
The twisting version of force: a force applied off-center, at a lever-arm, that spins the body. M = H ˙ is the rotational Newton's law.
Why the topic needs it: M = H ˙ ∣ I = I ω ˙ ∣ B + ω × ( I ω ) is Euler's equation. Every symbol in it — I , ω , H , M , the cross product, the two frames — you now own.
Cross product omega cross A
Everything funnels into the transport theorem , which then produces both the Newton and Euler equations of the parent note the 6DOF topic .
Draw a 3D vector and label its three components. An arrow whose shadows on the
x , y , z axes are
A x , A y , A z , so
A = A x e ^ x + A y e ^ y + A z e ^ z .
What does the dot in A ˙ mean, and what two things can make it nonzero? One time-derivative; nonzero if the vector's length changes OR its direction swings (basis rotates).
Name ( u , v , w ) and ( p , q , r ) . Body-frame velocity components (forward, side, up) and angular-velocity components (roll p , pitch q , yaw r ).
What does ω × A physically give, and when is it zero? The sideways velocity a point at
A gets from spinning; zero when
A is parallel to the axis
ω .
Why do we need both an inertial frame I and a body frame B ? Newton/Euler laws are only valid in I , but measurements are easiest in B ; the transport theorem bridges the two.
Why is inertia a tensor I instead of a single number like mass? A body resists twisting differently about different axes, so one number can't capture it — you need a 3 × 3 table.
Write the rotational analog of F = p ˙ . M = H ˙ with
H = I ω — torque equals rate of change of angular momentum.