We use linearized supersonic slender-body theory. A slender body's disturbance can be built from a line of sources of strength f(x) along the axis. The local source strength that produces a body of cross-section A(x) is
f(x)=U∞dxdA,
The drag is the streamwise momentum lost to the waves. Carrying through the linearized supersonic Green's function (von Kármán, 1935), the wave drag of a slender body of length ℓ is the von Kármán–Sears integral:
Minimizing Dw over all A(x) with fixed length ℓ and fixed maximum area (or fixed volume) is a calculus-of-variations problem. The minimizer is the Sears–Haack body, whose area distribution is
What quantity does transonic wave drag primarily depend on, per the area rule?
The longitudinal distribution of total cross-sectional area A(x), regardless of how it's split between components.
Why is the fuselage pinched ("Coke-bottle") near the wings?
So the fuselage area dips to cancel the wing's area bump, keeping total A(x) smooth and A′′ small.
What drives wave drag in the von Kármán–Sears integral?
The second derivative (curvature) A′′(x) — abrupt area changes/kinks give huge A′′ → strong shocks → drag.
State the von Kármán–Sears wave-drag integral.
Dw=−4πρU2∬A′′(x1)A′′(x2)ln∣x1−x2∣dx1dx2.
What is the minimum-wave-drag area distribution for fixed length?
The Sears–Haack body: A(x)=Amax[4ξ(1−ξ)]3/2, ξ=x/ℓ.
How does Sears–Haack wave drag scale with length at fixed volume?
Dw∝V2/ℓ4 — doubling length cuts wave drag to 1/16.
What changes for the supersonic (Jones) area rule vs M≈1?
Cut the body with Mach planes tilted at μ=arcsin(1/M) (averaged over roll), not perpendicular planes.
What real aircraft proved the area rule?
The F-102A — re-shaped (area-ruled) it broke Mach 1, which the un-ruled YF-102 could not.
Does area ruling reduce skin-friction drag?
No — only wave drag near and above Mach 1; friction and induced drag are unaffected.
Why is source strength f(x)=U∞A′(x)?
A growing cross-section must displace volume at rate U∞dA per length, equal to a line source of that strength.
Recall Feynman: explain to a 12-year-old
Imagine air flowing past a plane like water sliding around a smooth stick. If the stick suddenly gets fat in the middle (because of the wings), the water has to shove out of the way really fast and splashes — that splash near the speed of sound is a shock wave that drags the plane back. Whitcomb said: just squeeze the middle of the body in where the wings stick out, so the whole thing looks like a smooth, gently-fattening stick again. The air slides by calmly, the "splash" almost disappears, and the plane goes faster on the same engine. That pinched-waist shape is why some fast jets look like a Coke bottle!
Dekho, transonic speed (Mach ≈ 1) par jab hawa plane ke around flow karti hai, to woh poore plane ko alag-alag pieces (fuselage, wing, tail) ke roop mein nahi dekhti — woh sirf yeh feel karti hai ki total cross-sectional area A(x) distance ke saath kaise badal rahi hai. Agar yeh area curve mein achanak bump aa jaaye (jaise wing ke jagah area suddenly badh jaaye), to hawa ko bahut tezi se idhar-udhar hatna padta hai, aur isse strong shock waves banti hain — jo wave drag create karti hain. Yahi transonic drag rise ka main reason hai.
Whitcomb ka jabardast idea: fuselage ko wahin patla (pinch) kar do jahan wing apni area add kar rahi hai, taaki total area curve smooth rahe. Yahi reason hai ki kuch fast jets "Coke-bottle" ya "wasp-waist" jaise dikhte hain — beech mein patle. Mathematically, wave drag A′′(x) (area ki curvature) par depend karta hai (von Kármán–Sears integral). Smooth curve ⇒ chhota A′′ ⇒ kam drag. Yeh F-102 ki real story hai: pehle woh Mach 1 cross nahi kar paaya, lekin area-ruled karne ke baad easily cross kar gaya.
Ek aur important baat — yeh sirf wave drag kam karta hai, friction ya induced drag nahi. Aur fixed volume ke liye Sears–Haack body sabse kam wave drag deti hai, jismein Dw∝V2/ℓ4. Matlab body jitni lambi aur smooth, drag utna kam — isiliye supersonic missiles aur jets long aur slender hote hain. Bas yaad rakho: "Smooth the SUM, not the part!"