We use isentropic, steady, 1-D flow of a perfect gas, ratio of specific heats γ, gas constant R. Stagnation (reservoir) conditions p0,T0,ρ0 are fixed.
Why the T0/T step? Divide h0=h+21V2 by cpT: TT0=1+2cpTV2. Now 2cpTV2=2cpTM2γRT=2cpM2γR=2γ−1M2. Done — pure algebra, no memorization.
What Mach number occurs at the throat of a choked nozzle?
M=1 (sonic).
Why does mass flow stop increasing once choked?
Throat is sonic; pressure signals can't travel upstream past M=1, so the throat can't "feel" lower back pressure.
Critical pressure ratio p∗/p0 for air (γ=1.4)?
≈0.528.
Critical temperature ratio T∗/T0 for air?
≈0.833 (=2/(γ+1)).
General formula T∗/T0?
γ+12.
General formula p∗/p0?
(γ+12)γ/(γ−1).
At what M is m˙ per unit throat area maximized?
At M=1 (where dm˙/dM=0).
How does m˙max scale with p0, T0, A∗?
∝p0, ∝A∗, ∝1/T0.
Choked-flow max mass-flow formula?
m˙max=A∗p0γ/(RT0)(2/(γ+1))(γ+1)/2(γ−1).
To get supersonic exit, what nozzle shape is required?
Converging–diverging (de Laval).
When choked, where does remaining expansion to ambient occur?
Outside the nozzle (under-expanded jet).
Recall Feynman: explain to a 12-year-old
Imagine squeezing toothpaste through the narrowest part of a tube. As you suck harder on the far end, more comes out — for a while. But once the toothpaste at the narrow spot is moving as fast as a "message" can travel through it (the speed of sound), the narrow spot can't hear your sucking anymore. So no matter how hard you pull, the same amount keeps coming out. That "as fast as a sound message" speed is M=1, and the steady stuck amount is the maximum mass flow.
Socho ek converging nozzle hai jisme reservoir (stagnation) se gas bahar nikal rahi hai. Jaise-jaise tum back pressure pb kam karte ho, pehle to mass flow m˙ badhta jaata hai — zyada pressure drop, zyada flow. Lekin ek limit aati hai: jab nozzle ke sabse patle hisse (throat) pe flow ki speed sound ke barabar ho jaati hai, yaani M=1. Iske baad chahe tum back pressure kitna bhi giraao, mass flow nahi badhega. Isi ko choked flow kehte hain.
WHY aisa hota hai? Pressure ki "information" sirf sound ki speed se travel karti hai. Jab throat pe flow already sonic hai, to downstream ka low pressure ka signal upstream throat tak pahunch hi nahi sakta — throat ko "sunai" nahi deta. Isliye throat respond nahi kar paata, aur m˙ apne maximum pe lock ho jaata hai. Maths bhi yahi kehti hai: m˙ ko M ke against maximize karo, to derivative zero M=1 pe hi aata hai. Pure coincidence nahi — exact maximum.
Air ke liye yaad rakhne wali numbers: critical pressure ratio p∗/p0≈0.528 aur temperature ratio T∗/T0≈0.833. Matlab jaise hi pb/p0 giirke 0.528 tak aaya, nozzle choke ho gaya, aur throat ka pressure 0.528p0 pe atak gaya. Ek important point: m˙max∝1/T0 — yaani garam reservoir se kam mass flow milta hai (kyunki density gir jaati hai). Aur dhyan rakho: sirf converging nozzle se supersonic flow nahi milta — uske liye converging–diverging (de Laval) nozzle chahiye.