1.1.7Measurement, Vectors & Kinematics

Vector representation — magnitude, direction, components

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1. Two ways to describe the same arrow

WHY two forms? Polar form is how nature gives us data ("50 N at 30°"). Component form is how we compute (we add components, not arrows). We constantly translate between them.

Figure — Vector representation — magnitude, direction, components

2. Derivation: from magnitude–direction → components

Draw the arrow A\vec A from the origin. Drop a perpendicular from its tip to the x-axis. This makes a right triangle:

  • hypotenuse = AA (the whole arrow),
  • angle at origin = θ\theta,
  • the side along x is adjacent to θ\theta,
  • the side along y is opposite to θ\theta.

By the definitions of cosine and sine in a right triangle: cosθ=adjacenthyp=AxA,sinθ=oppositehyp=AyA.\cos\theta=\frac{\text{adjacent}}{\text{hyp}}=\frac{A_x}{A},\qquad \sin\theta=\frac{\text{opposite}}{\text{hyp}}=\frac{A_y}{A}.

Solving each:


3. Derivation: from components → magnitude & direction

Now go the other way. The same right triangle has legs Ax,AyA_x,A_y. By Pythagoras (legs² sum to hypotenuse²): A2=Ax2+Ay2    A=Ax2+Ay2.A^2 = A_x^2 + A_y^2 \;\Rightarrow\; A=\sqrt{A_x^2+A_y^2}.

For the angle, divide the two component equations: AyAx=AsinθAcosθ=tanθ    θ=tan1 ⁣(AyAx).\frac{A_y}{A_x}=\frac{A\sin\theta}{A\cos\theta}=\tan\theta \;\Rightarrow\; \theta=\tan^{-1}\!\left(\frac{A_y}{A_x}\right).

WHY the quadrant check? tan1\tan^{-1} on a calculator only returns angles in (90°,90°)(-90°,90°). But an arrow pointing into the 2nd or 3rd quadrant has the same Ay/AxA_y/A_x ratio as one pointing into the 4th or 1st. You must look at the signs of Ax,AyA_x,A_y to know the true quadrant.

Sign of AxA_x Sign of AyA_y Quadrant Fix to calculator angle
+ + I none
+ II add 180°180°
III add 180°180°
+ IV add 360°360° (or leave negative)

4. Unit vector — direction stripped of size

Dividing by AA scales the length to 1 while every component shrinks by the same factor, so direction is untouched. In 2D: A^=(cosθ)i^+(sinθ)j^\hat A=(\cos\theta)\hat i+(\sin\theta)\hat j.


5. Worked examples


6. Common mistakes (steel-manned)


Recall Feynman: explain to a 12-year-old

Imagine giving directions to a friend: "walk fast, that way!" You said how fast (the size) and which way (the direction) — that's a vector arrow. But it's hard to walk "diagonally that way." So you say instead: "walk 3 steps East, then 4 steps North." Those two simple steps are the components. Both descriptions land at the same spot. Pythagoras tells you the straight-line distance was 5 steps, and the slant of the path tells you the direction. Components are just the "go East then go North" version of any slanted arrow.


7. Active recall

What two quantities does a vector carry?
Magnitude (how much) and direction (which way).
Component of A\vec A along x in terms of A,θA,\theta (angle from +x)?
Ax=AcosθA_x=A\cos\theta.
Component along y?
Ay=AsinθA_y=A\sin\theta.
Why does the x-component use cosine?
The angle is measured from the x-axis, so the x-side is adjacent → cosine.
Magnitude from components?
A=Ax2+Ay2A=\sqrt{A_x^2+A_y^2} (Pythagoras on the legs).
Direction from components?
θ=tan1(Ay/Ax)\theta=\tan^{-1}(A_y/A_x), with a quadrant correction from the signs.
When must you add 180°180° to the calculator's tan1\tan^{-1}?
When Ax<0A_x<0 (vector points into quadrant II or III).
What is a unit vector and how do you get it?
A length-1 vector of the same direction; A^=A/A\hat A=\vec A/|\vec A|.
Can magnitude be negative?
No, A0A\ge0; sign info lives in components/angle.
Components of A=3i^+4j^\vec A=-3\hat i+4\hat j: magnitude and true angle?
A=5A=5, θ=127°\theta=127° (quadrant II).
Why can't you just add magnitudes of two vectors?
Arrows can cancel partially; add components first, then take magnitude.

Connections

Concept Map

contrasts with

described by

described by

drop perpendicular gives

defines

multiply by A

converts

legs give

yields

divide equations

needs

recover

recover

Vector - an arrow

Scalar cannot hold both

Polar form: magnitude and angle

Component form: Ax i + Ay j

Right triangle

Sine and cosine

Ax = A cos θ, Ay = A sin θ

Pythagoras

A = sqrt of Ax squared + Ay squared

θ = arctan of Ay over Ax

Quadrant check on signs

Hinglish (regional understanding)

Intuition Hinglish mein samjho

Dekho, ek vector basically ek arrow hai jo do baatein batata hai: kitna (magnitude) aur kis taraf (direction). Ek normal number, jaise 5, sirf "kitna" bata sakta hai — woh scalar hai. Lekin "50 N at 30°" jaisi cheez ke liye humein dono chahiye, isliye vector use karte hain.

Ab problem ye hai ki tedhe (slanted) arrow ko add karna mushkil hai. Toh hum use todte hain do clean parts mein — horizontal (x) aur vertical (y) — inhe components kehte hain. Right-angle triangle banao jismein arrow hypotenuse hai. Phir simple trig se: Ax=AcosθA_x = A\cos\theta aur Ay=AsinθA_y = A\sin\theta. Yaad rakho — angle hamesha x-axis se naapte hain, isliye x ke saath cos aata hai (x adjacent side hai), aur y ke saath sin.

Ulta jaana ho — components se magnitude nikalni ho — toh Pythagoras lagao: A=Ax2+Ay2A=\sqrt{A_x^2+A_y^2}, aur angle ke liye θ=tan1(Ay/Ax)\theta=\tan^{-1}(A_y/A_x). Bas ek dhyaan ki baat: calculator ka tan1\tan^{-1} kabhi galat quadrant deta hai, isliye AxA_x aur AyA_y ke signs dekh kar, agar AxA_x negative hai toh 180°180° add kar do.

Ye topic JEE/NEET ka foundation hai — projectile motion, force resolution, dot/cross product, sab yahin se chalta hai. Ek baar components solid ho gaye, toh aage ka mechanics aasan ho jaata hai. Practice tip: har vector problem mein pehle arrow draw karo, phir triangle, phir formula — ratta mat maaro.

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