Intuition The ONE core idea
An ellipse is the set of all points whose two distances to two fixed pins add up to the same number every time . That fixed number is called 2 a , and this single fact — constant sum — is the whole soul of the parent topic Sum of Focal Radii = 2a .
Before you can derive that "constant sum," you need to be fluent in a small pile of symbols and pictures that the parent note quietly assumes. This page builds every one of them from nothing, in an order where each idea rests on the previous. Read top to bottom.
A point is a single dot on a flat sheet. To pin down which dot, we give it two numbers: how far right (x ) and how far up (y ) it sits from a chosen crossing-point called the origin O .
We write the dot as P = ( x , y ) .
Picture: a flat cream sheet with two number-lines crossing at the middle. Slide x steps sideways, then y steps up — you land on P .
Why the topic needs this. The whole ellipse is described as "the collection of points ( x , y ) satisfying a rule." Without coordinates we couldn't write a single equation, so this is symbol number one.
x can be negative (go left ) and y can be negative (go down ). Keep that in mind — signs matter later.
Suppose two dots A = ( x 1 , y 1 ) and B = ( x 2 , y 2 ) . How far apart are they in a straight line?
Intuition Why a square root — and why
this tool
The straight gap between two dots is the hypotenuse (the slanted long side) of a right-angled triangle whose flat legs are the sideways gap x 2 − x 1 and the up gap y 2 − y 1 . The one tool that turns two perpendicular legs into a slanted length is the Pythagoras theorem — "leg² + leg² = hypotenuse²." To undo that square and recover the length itself, we take a square root. That is the only reason appears.
Look at the figure: the burnt-orange slanted line is A B ; the teal legs are the two gaps. Squaring removes any minus sign (a gap of − 3 and a gap of + 3 give the same length), which is exactly why distances are always ≥ 0 .
Why the topic needs this. A "focal radius" is literally a distance from a point to a focus. Step 1 of the parent's derivation is this formula. Everything downstream is algebra on this one square root.
a and 2 a
An ellipse is a squashed circle — an oval . Its longest straight width across the middle is the major axis ; the parent calls its full length 2 a . Half of it — from the centre out to the pointy end (a vertex ) — is a , the semi-major axis .
Picture: the oval's widest cut, drawn burnt-orange. Centre to the right tip is a ; tip to tip is 2 a . The word "semi" just means "half."
Why the topic needs this. 2 a is the hidden constant — the fixed number the two distances add up to. The entire property is the sentence "r 1 + r 2 = 2 a ", so a is the star of the show.
b
The shortest width across the middle (perpendicular to the major axis) is the minor axis ; from centre to the top edge is b , the semi-minor axis . For a genuine oval we insist a > b > 0 — longer than it is tall.
In the same figure above, the teal vertical half-height is b . If a = b the oval un-squashes into a perfect circle — a useful sanity limit to keep at the back of your mind.
Why the topic needs this. b never appears in the final answer 2 a , yet it is the bridge that lets us erase y during the derivation (via the relation in §6). Without b the algebra can't collapse.
Definition Foci and focal radii
Inside the oval sit two special pinned points called foci (one focus, two foci). We name them S and S ′ (read "S-prime" — the tick just means "the other one"). For any point P on the ellipse:
r 1 = S P ( distance to S ) , r 2 = S ′ P ( distance to S ′ )
These two distances are the focal radii of P .
Picture the gardener's trick : two nails (S , S ′ ), a loop of string, a pencil pulled taut. As the pencil moves, the two string-segments r 1 and r 2 change — but their sum is frozen at the string's length. That frozen length is exactly 2 a .
Why the topic needs this. These are the two things we add. The whole property compares r 1 + r 2 (turns out constant) with r 1 − r 2 (turns out to vary). See Definition of Conic as Locus for the "constant sum defines the curve" viewpoint.
e
Eccentricity e is a single number that measures how squashed the oval is. For an ellipse 0 < e < 1 . Near e = 0 the shape is almost a circle; as e creeps toward 1 it stretches long and thin.
The foci live at x = ± a e on the major axis — so e literally tells you how far out the pins are pushed from the centre (multiply the half-length a by the fraction e ).
Why this relation, and why the topic needs it. In the derivation we must kill y 2 . The ellipse equation lets us swap y 2 for something with b 2 in it — but b 2 is a stranger to the focus positions, which use a and e . This bridge translates b 2 into the language of a and e , and that translation is exactly what makes the mess fold into a perfect square. It's the hinge of the whole proof. More on e in Eccentricity of Conics .
Read this as a membership test : plug a point ( x , y ) into the left side; if you get exactly 1 , the point is on the oval. This is where a , b , x , y all meet. From it we extract y 2 = b 2 ( 1 − x 2 / a 2 ) — the exact substitution that erases y in Step 2 of the parent. Full construction lives in Ellipse - Standard Equation .
Definition Perfect square
A perfect square is an expression that is literally "something times itself," like ( a − e x ) 2 . It matters because ( something ) 2 collapses to just ∣ something ∣ — the square root and the square undo each other. The derivation is engineered so the mess becomes a perfect square, letting the ugly root vanish cleanly.
Definition Absolute value
∣ q ∣ means "the size of q , forget its sign": ∣ − 4 ∣ = 4 and ∣4∣ = 4 . Crucially, q 2 = ∣ q ∣ , not just q .
( a − e x ) 2 is always a − e x ."
Why it feels right: square and root look like they simply cancel. Fix: in general ( a − e x ) 2 = ∣ a − e x ∣ . We only drop the bars because for a point on the ellipse − a ≤ x ≤ a and 0 < e < 1 , which forces a − e x > 0 . So the quantity is already positive and ∣ a − e x ∣ = a − e x . Always check the sign before removing the bars.
The Directrix and Focal Distance view gives another route to a − e x , cross-checking this one.
Coordinates x y of a point P
Distance formula square root
Focal radii r1 = SP and r2 = S'P
Semi major axis a gives 2a
Eccentricity e places foci at plus minus ae
Bridge b squared = a squared times 1 minus e squared
Replace y squared using the equation
Perfect square a minus ex squared
Absolute value and sign check
Take square root to get a minus ex
Sum of focal radii equals 2a property
Reveal each after you've answered it out loud.
What does P = ( x , y ) mean, and can x be negative? A point at x steps right and y steps up from the origin; yes, negative x means go left.
Write the distance between ( x 1 , y 1 ) and ( x 2 , y 2 ) . Why does a square root appear in distance? Pythagoras gives leg² + leg² = length²; the root undoes the square to recover the length.
What is 2 a in words? The full length of the major axis — the oval's longest width.
What is a versus b ? a = half the longest width (semi-major); b = half the shortest width (semi-minor); a > b > 0 .
What are S , S ′ , r 1 , r 2 ? The two foci and the two distances from a point P to them.
Where do the foci sit and what controls that? At x = ± a e ; the eccentricity e (with 0 < e < 1 ) controls how far out.
State the bridge relation and why we need it. b 2 = a 2 ( 1 − e 2 ) ; it converts b 2 into a , e language so the algebra collapses to a perfect square.
What does the ellipse equation test? Whether a point is on the oval — plug in ( x , y ) ; equals 1 ⇒ on the curve.
Why is ( a − e x ) 2 = a − e x (not just "square cancels root")? Because
q 2 = ∣ q ∣ , and here
a − e x > 0 for points on the ellipse, so the bars drop safely.