Intuition The ONE idea of this whole topic
A point walking around a circle of radius 1 is always exactly 1 unit from the centre. Its shadow on the floor (how far right it is) and its height (how far up it is) are the two legs of a right triangle whose slanted long side is that radius. Because "leg-square plus leg-square equals slant-square", those two distances are locked together forever — and that lock is the whole topic. Every symbol in the parent note is just a name for one of the pieces in this picture.
This page assumes nothing . Before you can even read the parent note's headline formula you must already own about a dozen tiny ideas. We build every one from zero, in the order they depend on each other — no symbol is used before its own section defines it . If a symbol shows up on the parent note and you can't picture it, it lives here.
We start here because everything else — directions, circles, distances — is drawn on this grid.
( x , y )
A flat sheet with two number-lines crossing at right angles at a point called the origin . The horizontal line is the ==x -axis; the vertical line is the y -axis==. The first number x is "how far right " of the origin (negative = left); the second number y is "how far up " (negative = down). A dot is pinned down by its pair ( x , y ) .
We need this because a "direction" will eventually land on an actual point , and we describe points with ( x , y ) .
The plane splits into four quadrants , and their sign patterns matter enormously later (they decide ± signs):
Quadrant
where
x sign
y sign
I
top-right
+
+
II
top-left
−
+
III
bottom-left
−
−
IV
bottom-right
+
−
The unit circle is defined by "distance 1 ", so we must first say what distance means on the grid.
Definition Distance in the plane
The straight-line distance from the origin ( 0 , 0 ) to a point ( x , y ) is the length of the slanted line joining them. That slant is the long side of a right triangle whose horizontal side has length x and vertical side has length y . Its length is written
distance = x × x + y × y .
(This is Pythagoras, which we build fully in Section 6; is explained in Section 8. For now: distance = 1 means "the slant is exactly one unit long".)
Intuition Why we need a distance rule at all
"The unit circle is all points at distance 1 " is meaningless until "distance" is pinned down. On a flat grid, distance is always the slant of a right triangle — that is the only ruler we use in this whole chapter.
θ
θ (Greek letter "theta") is just a name for a direction , measured as a turn away from pointing along the positive x -axis (straight right, defined in Section 1). A positive θ turns anticlockwise ; a negative θ turns clockwise (the opposite way).
Definition Units: degrees vs radians
A full loop is either 360 degrees (written 36 0 ∘ ) or 2 π radians (no little circle). Both name the same turn. On this page we use degrees and always write the ∘ symbol; a bare number like π /4 would mean radians. The identities themselves don't care which unit you pick.
Look at the figure below. The amber ray starts flat along the right and swings up. The wedge between "flat right" and the ray is θ .
Intuition Why we need an angle at all
Every quantity in this topic is a machine that eats an angle and spits out a number . Without a clear picture of what an angle is (a turn, not a shape), none of the machines mean anything.
θ = 0 ∘ means "pointing straight right".
θ = 9 0 ∘ means "pointing straight up".
θ = 18 0 ∘ means "pointing left".
θ = − 9 0 ∘ means "pointing straight down " (a clockwise quarter-turn) — same spot as + 27 0 ∘ .
Keep turning past 36 0 ∘ and you just lap the circle again.
Intuition Why negative angles land in the same places
A clockwise turn of 9 0 ∘ ends exactly where an anticlockwise turn of 27 0 ∘ ends. So θ = − 9 0 ∘ and θ = + 27 0 ∘ give the same point , hence the same coordinates. Nothing on this page breaks for negative θ — it just enters the circle from below instead of from above.
The set of all points at distance 1 (Section 2) from the origin. "Unit" just means "one". Drawn out, it's a perfectly round loop of radius 1 centred at the crossing point of the axes.
1 and not 5 ?
Choosing radius 1 is a deliberate simplification . The long slant of every triangle we build will equal the radius, so making the radius 1 makes that slant 1 , and 1 multiplied by itself is still 1 . That single choice is what turns Pythagoras into a clean "= 1 " instead of "= radius-squared". Pick the unit circle and the messy constant vanishes.
Definition Cosine and sine
Send out the ray at angle θ (Section 3). Where it pierces the unit circle, call that point P . Then by definition :
cos θ = the x -coordinate of P ( "how far right" )
sin θ = the y -coordinate of P ( "how far up" )
That's it — cos and sin are not magic; they are literally the shadow-on-the-floor and the height of the point on the circle.
Intuition Why these can be negative
In Quadrant II the point is up-and-left , so its x is negative → cos θ < 0 there. In Quadrant IV it's down-and-right, so y < 0 → sin θ < 0 . This works for negative θ too: θ = − 9 0 ∘ lands at the bottom, where x = 0 and y = − 1 , so cos ( − 9 0 ∘ ) = 0 , sin ( − 9 0 ∘ ) = − 1 . The sign of cos and sin is just which quadrant the point sits in — the same sign table from Section 1. This is the whole reason the parent note keeps saying "the quadrant decides the sign".
sin 2 θ means sin ( θ 2 ) "
Why it tempts you: the little 2 (defined next section) floats near the θ .
Truth: sin 2 θ is shorthand for ( sin θ ) 2 — first take the sine, then square the result. Completely different from sin ( θ 2 ) , which would square the angle first.
2
a 2 means a × a — the number multiplied by itself, once. Geometrically, a 2 is the area of a square whose side has length a . So 3 2 = 3 × 3 = 9 , and 1 2 = 1 × 1 = 1 .
Definition Right triangle & Pythagoras
A right triangle is a triangle with one 9 0 ∘ (square) corner. The two short sides touching that corner are the legs ; the long slanted side opposite it is the hypotenuse . Pythagoras Theorem says:
( leg 1 ) 2 + ( leg 2 ) 2 = ( hypotenuse ) 2 .
(Now that 2 is defined in Section 6, this reads "leg-area plus leg-area equals hypotenuse-area".)
looks like
Build a square on each side of the triangle (see figure). The two squares on the legs, glued together, have exactly the same total area as the big square on the hypotenuse. That area-balance is the whole theorem — and it is the same rule we used to measure distance in Section 2.
Intuition Why this specific tool, here?
Our point P = ( cos θ , sin θ ) makes a right triangle: horizontal leg = ∣ cos θ ∣ , vertical leg = ∣ sin θ ∣ , hypotenuse = radius = 1 . Pythagoras is the one law that relates the two legs to the hypotenuse , and relating "how far right" to "how far up" to "distance 1 " is precisely the question this whole chapter asks. No other tool connects those three lengths.
Feeding our triangle into Pythagoras:
∣ cos θ ∣ 2 + ∣ sin θ ∣ 2 = 1 2 ⟹ cos 2 θ + sin 2 θ = 1.
The absolute-value bars vanish because squaring makes signs irrelevant (Section 6, job 1). This is the master identity the parent note derives — and you now own every symbol in it.
and ±
k ("square root of k ") asks: what positive number, squared, gives k ? The symbol ± ("plus-or-minus") reminds you there are two numbers whose square is k — one positive, one negative — because squaring (Section 6) hides the sign.
± is unavoidable
If cos 2 θ = 25 16 , then cos θ could be + 5 4 or − 5 4 ; the equation alone can't tell them apart. Only knowing the quadrant (Section 1's sign table) picks the right sign. This is the single most-forgotten step in the worked examples.
To read the other two identities you need four more machines. Each is built purely from sin and cos (full detail lives in Reciprocal and Quotient trig identities ).
Intuition Why "divide by a leg" gives the other two identities
The parent note derives the child identities by dividing the master identity by a squared leg. Divide every term of cos 2 θ + sin 2 θ = 1 by cos 2 θ :
c o s 2 θ c o s 2 θ + c o s 2 θ s i n 2 θ = c o s 2 θ 1 .
Each fraction simplifies using the definitions above: cos 2 θ cos 2 θ = 1 , cos 2 θ sin 2 θ = tan 2 θ , and cos 2 θ 1 = sec 2 θ . Putting these in gives the first child identity in full:
1 + tan 2 θ = sec 2 θ .
Now divide the master identity by sin 2 θ instead:
s i n 2 θ c o s 2 θ + s i n 2 θ s i n 2 θ = s i n 2 θ 1 ⟹ cot 2 θ + 1 = csc 2 θ ,
using sin 2 θ cos 2 θ = cot 2 θ and sin 2 θ 1 = csc 2 θ . So the second child identity in full is
1 + cot 2 θ = csc 2 θ .
The four cousins are exactly the pieces that pop out when you divide the master identity.
Common mistake Forgetting these are undefined sometimes
tan θ and sec θ divide by cos θ , so they blow up when cos θ = 0 (i.e. θ = 9 0 ∘ , 27 0 ∘ ). Likewise cot , csc die when sin θ = 0 . The identity 1 + tan 2 θ = sec 2 θ simply doesn't apply at those angles.
Coordinate plane x, y axes
Distance = slant of right triangle
Angle theta as a turn, plus or minus
cos = x-coord, sin = y-coord
Right triangle and Pythagoras
1 + tan^2 = sec^2 and 1 + cot^2 = csc^2
plus or minus square root
Cover the right side. If any answer surprises you, reread that section before the parent note.
What are the x -axis and y -axis? The horizontal ("how far right") and vertical ("how far up") number-lines crossing at the origin
How do you measure the straight-line distance from origin to ( x , y ) ? x × x + y × y — the slant of a right triangle with legs
x and
y What does θ physically represent? A turn from the positive x -axis; positive = anticlockwise, negative = clockwise
What unit does this page use for angles, and how is it marked? Degrees, always written with the ∘ symbol
Where does θ = − 9 0 ∘ point, and what point equals it? Straight down; same point as θ = + 27 0 ∘
What is the unit circle? All points at distance 1 from the origin
Define cos θ and sin θ on the unit circle cos θ = x -coordinate, sin θ = y -coordinate of the point where the ray hits the circle
In which quadrants is cos θ negative? Quadrants II and III (point is to the left, x < 0 )
In which quadrants is sin θ negative? Quadrants III and IV (point is below the axis, y < 0 )
What does the superscript 2 mean in cos 2 θ ? ( cos θ ) 2 — take the cosine first, then square it
Why does squaring make the identity work in every quadrant? Squaring erases minus signs, so cos 2 θ is positive regardless of cos θ 's sign
State Pythagoras' theorem leg² + leg² = hypotenuse²
Why is the hypotenuse equal to 1 here? It is the radius of the unit circle, which is 1
Write tan θ , sec θ , csc θ , cot θ in terms of sin and cos tan = sin / cos , sec = 1/ cos , csc = 1/ sin , cot = cos / sin
Get 1 + tan 2 θ = sec 2 θ from the master identity Divide every term of cos 2 + sin 2 = 1 by cos 2 θ
When are tan θ and sec θ undefined? When cos θ = 0 (e.g. θ = 9 0 ∘ )
Why does solving cos 2 θ = k need a ± ? Two numbers square to k ; only the quadrant fixes the sign