3.1.9 · D1Advanced Trigonometry

Foundations — Pythagorean identities — sin² + cos² = 1, derivations of the other two

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This page assumes nothing. Before you can even read the parent note's headline formula you must already own about a dozen tiny ideas. We build every one from zero, in the order they depend on each other — no symbol is used before its own section defines it. If a symbol shows up on the parent note and you can't picture it, it lives here.


1. The coordinate plane —

We start here because everything else — directions, circles, distances — is drawn on this grid.

We need this because a "direction" will eventually land on an actual point, and we describe points with .

The plane splits into four quadrants, and their sign patterns matter enormously later (they decide signs):

Quadrant where sign sign
I top-right
II top-left
III bottom-left
IV bottom-right

2. Distance between two points — the metre-stick of the plane

The unit circle is defined by "distance ", so we must first say what distance means on the grid.


3. The angle — what a "direction" is

Look at the figure below. The amber ray starts flat along the right and swings up. The wedge between "flat right" and the ray is .

Figure — Pythagorean identities — sin² + cos² = 1, derivations of the other two
  • means "pointing straight right".
  • means "pointing straight up".
  • means "pointing left".
  • means "pointing straight down" (a clockwise quarter-turn) — same spot as .
  • Keep turning past and you just lap the circle again.

4. The unit circle — radius exactly

Figure — Pythagorean identities — sin² + cos² = 1, derivations of the other two

5. and — the coordinates of the walking point

That's it — and are not magic; they are literally the shadow-on-the-floor and the height of the point on the circle.

Figure — Pythagorean identities — sin² + cos² = 1, derivations of the other two

6. Squaring and the little superscript


7. Pythagoras' theorem — the engine

Figure — Pythagorean identities — sin² + cos² = 1, derivations of the other two

Feeding our triangle into Pythagoras: The absolute-value bars vanish because squaring makes signs irrelevant (Section 6, job 1). This is the master identity the parent note derives — and you now own every symbol in it.


8. Square roots and the symbol


9. The division cousins —

To read the other two identities you need four more machines. Each is built purely from and (full detail lives in Reciprocal and Quotient trig identities).


Prerequisite map

Coordinate plane x, y axes

Distance = slant of right triangle

Angle theta as a turn, plus or minus

Unit circle radius 1

cos = x-coord, sin = y-coord

Squaring kills signs

Right triangle and Pythagoras

sin^2 + cos^2 = 1

Divide by a squared leg

tan sec cot csc

1 + tan^2 = sec^2 and 1 + cot^2 = csc^2

plus or minus square root

Quadrant sign table


Equipment checklist

Cover the right side. If any answer surprises you, reread that section before the parent note.

What are the -axis and -axis?
The horizontal ("how far right") and vertical ("how far up") number-lines crossing at the origin
How do you measure the straight-line distance from origin to ?
— the slant of a right triangle with legs and
What does physically represent?
A turn from the positive -axis; positive = anticlockwise, negative = clockwise
What unit does this page use for angles, and how is it marked?
Degrees, always written with the symbol
Where does point, and what point equals it?
Straight down; same point as
What is the unit circle?
All points at distance from the origin
Define and on the unit circle
= -coordinate, = -coordinate of the point where the ray hits the circle
In which quadrants is negative?
Quadrants II and III (point is to the left, )
In which quadrants is negative?
Quadrants III and IV (point is below the axis, )
What does the superscript mean in ?
— take the cosine first, then square it
Why does squaring make the identity work in every quadrant?
Squaring erases minus signs, so is positive regardless of 's sign
State Pythagoras' theorem
leg² + leg² = hypotenuse²
Why is the hypotenuse equal to here?
It is the radius of the unit circle, which is
Write , , , in terms of and
, , ,
Get from the master identity
Divide every term of by
When are and undefined?
When (e.g. )
Why does solving need a ?
Two numbers square to ; only the quadrant fixes the sign

Connections