Yeh definition KYU? Gate sirf wohi mobile charge "own" kar sakta hai jiska depletion charge seedha
iske neeche baitha ho. Source aur drain junctions apne khud ke depletion regions
(triangular wedges) banate hain jo channel mein xdS aur xdD tak laterally extend karte hain. Jab L
bada hota hai toh yeh wedges channel ka ek negligible fraction hain; jab L shrink hoke
xdS+xdD ke paas pahunchta hai toh woh poora channel consume kar lete hain, isliye gate simple model ke assumption se kaafi kam charge govern karta hai.
Gate ke neeche depletion region ko rectangle ke bajaye trapezoid ki tarah model karo. Gate
trapezoidal charge "own" karta hai; source/drain junctions dono triangular corners own karte hain.
Maano xj = junction depth aur xdm = vertical (bulk ke andar) gate depletion depth.
Trapezoid ki geometry gate ke paas bacha hua bulk charge ka fraction deti hai:
QBQB′=1−Lxj(1+xj2xdm−1)
Yeh step KYU? Rectangle se remove kiye gaye dono triangles ka total area
xj (junctions kitni dur pahunchti hain) ke proportional hai aur
L ke inversely (ek fixed corner ek
short channel ka zyada bada fraction hota hai). Reduced charge substitute karne par:
Yeh step KYU?θ (units V−1) capture karta hai ki vertical field
E⊥∝(VGS−VT)/tox kitni strongly carriers ko interface mein crush karta hai. Zyada overdrive →
chhota μeff → drive current VGS ke saath sublinearly badhti hai, velocity-
saturation ceiling ke upar se bhi. Dono effects milke ideal ∝(VGS−VT)2 law ko severely blunt kar dete hain.
Recall Feynman: ek 12-saal ke bachche ko explain karo
Ek garden hose (source→drain) imagine karo jisme tumhara haath (gate) flow control karne ke liye use dabaata hai.
Agar hose lamba hai, tumhara haath clearly in-charge hai. Ab hose ko super short karo — tumhara
dabaav aur dono end-fittings almost touch kar rahe hain. Fittings khud hose ko squeeze karti hain,
toh paani tab bhi leak hota hai jab tum band karne ki koshish karo, aur door waale end (drain voltage) ka pressure
tumhare haath se past push kar sakta hai. Woh "ends ab flow ko boss kar rahe hain tumhare bajaye"
exactly short-channel effects hai.
Jab L, source aur drain ke lateral depletion widths ke sum ke comparable ho, roughly L≲xdS+xdD (woh point jahan dono depletion regions milti hain).
VT chhote L ke saath kyun roll off (decrease) hota hai?
Source/drain junction depletion regions bulk charge ka kuch hissa support karti hain, isliye gate kam charge QB′ support karta hai aur kam voltage chahiye; ΔVT∝1/L.
DIBL kya hai?
Drain-Induced Barrier Lowering: drain field source-channel barrier ko neeche karta hai, isliye zyada VDS effectively VT lower karta hai aur leakage badhata hai. VT=VT(0)−ηVDS.
Velocity saturation saturation current law ke saath kya karta hai?
ID,sat ko ∝(VGS−VT)2 se ∝(VGS−VT) mein change kar deta hai, kyunki v→vsat=μEcrit.
Vertical-field mobility degradation kis wajah se hoti hai?
High VGS carriers ko rough Si–SiO₂ interface ke against press karta hai, surface-roughness/remote-coulomb scattering add karta hai; μeff=μ0/(1+θ(VGS−VT)) overdrive badhne par girta hai.
Channel-length modulation kya hai aur yeh output resistance ko kaise affect karta hai?
Saturation pinch-off effective L ko ΔL se shorten karta hai jab VDS badhta hai; ID=ID,sat(1+λVDS), finite output resistance deta hai, λ∝1/L.
Punch-through kya hota hai?
Jab drain aur source depletion regions merge ho jaayein, ek ungated current path banta hai; gate control kho deta hai aur switch fail ho jaata hai.
DIBL numerically off-state leakage ko kaise affect karta hai?
Δ ka VT drop Ioff ko 10Δ/S se badhata hai, jahaan S subthreshold slope hai.
Charge sharing se threshold roll-off ka formula kya hai?