For Q<0, you might guess you just need to supply ∣Q∣. Wrong — momentum must also be conserved, so the products must keep moving; some incoming energy is "locked up" as center-of-mass motion and is unavailable.
Setup: a beam of intensity I (particles/area/time) enters a slab. In a thin slice of thickness dx with n nuclei per unit volume, the number of "targets" per unit beam-area is ndx, each blocking area σ.
Fraction removed in dx:
I−dI=nσdx(Why? covered-area fraction = ndx⋅σ)
Integrate from 0 to x:
∫I0IIdI=−nσ∫0xdx⇒lnI0I=−nσx
Q=[(ma+mX)−(mY+mb)]c2; energy released = lost rest mass.
Sign of Q for exoergic vs endoergic
Q>0 exoergic (mass lost, energy out); Q<0 endoergic (mass gained, energy in).
Q in terms of binding energy
Q=(BY+Bb)−(BX+Ba); exoergic if products more tightly bound.
Threshold energy formula
Eth=−Q(ma+mX)/mX (target at rest).
Why threshold exceeds |Q|
Momentum conservation locks some energy into CM motion, unavailable for reaction.
Conversion factor mass→energy
1 u = 931.5 MeV/c².
Cross-section unit
1 barn = 10⁻²⁸ m² = 10⁻²⁴ cm².
Physical meaning of σ
Effective target area = probability measure for the reaction (not literal size).
Beam attenuation law
I=I0e−nσx, with n = nuclei per volume.
Macroscopic cross-section & mean free path
Σ=nσ (cm⁻¹); mean free path = 1/Σ.
Reaction rate per nucleus
R=σϕ where φ = flux = nv.
Compact reaction notation X(a,b)Y means
target X + projectile a → product Y + ejected b.
Recall Feynman: explain to a 12-year-old
Throwing balls at targets. The Q-value is like a piggy bank: when the balls and targets snap together into a tidier shape, some "mass" turns into energy and pops out (that's the money you get). Sometimes the new shape is heavier, so you must pay in energy — and you have to pay extra because the pieces fly off afterwards and can't fully stop. The cross-section is just how big the target looks: a bigger target is easier to hit, so the reaction happens more often. Some targets look way bigger than they really are because of a quantum "magnet" effect.
Dekho, nuclear reaction matlab do nuclei ka collision jisme particles rearrange ho jaate hain, jaise a+X→Y+b. Yahan do cheezein important hain. Pehli — Q-value: ye batata hai ki reaction me energy nikli (release hui) ya lagi (absorb hui). Formula simple hai: reactants ka total mass minus products ka total mass, into c2. Agar mass kam ho gaya (products halke), to wo missing mass energy ban ke nikal aati hai — ye exoergic, Q>0. Agar products heavy ho gaye, to humein energy deni padti hai — endoergic, Q<0. Yaad rakho: 1 u = 931.5 MeV.
Ab ek twist: endoergic reaction me students sochte hain ki bas ∣Q∣ jitni energy de do. Galat! Momentum bhi conserve karna padta hai, isliye reaction ke baad products aage move karte rehte hain, aur thodi energy uss "getaway" me chali jaati hai. Isliye actual threshold energy thodi zyada hoti hai: Eth=∣Q∣(ma+mX)/mX. Isko "tax on the escape" samjho.
Dusri cheez — cross-section σ: ye reaction hone ki probability ka measure hai, units me area (barn, 10−24cm2). Socho target nucleus ek dartboard hai; jitna bada bullseye dikhega, utni asaani se dart lagega. Lekin yahan quantum effect ki wajah se kabhi target apne real size se hazaar guna bada bhi dikh sakta hai (resonance). Jab beam ek slab me ghusti hai to intensity exponentially kam hoti hai: I=I0e−nσx. Ye reactor physics me bahut kaam aata hai — boron jaise high-σ material neutrons ko turant rok dete hain. Bas ye samajh lo: Q = energy ka hisaab, σ = chance ka hisaab.