Level 2 — RecallNuclear & Radiochemistry

Nuclear & Radiochemistry

30 minutes40 marksprintable — key stays hidden on paper

Level: 2 (Recall — definitions, standard problems, short derivations) Time Limit: 30 minutes Total Marks: 40


Q1. Define the following terms in nuclear chemistry: (a) magic numbers, (b) binding energy per nucleon. State why the curve of binding energy per nucleon peaks near iron-56. (4 marks)

Q2. For each decay mode, give the change in atomic number ZZ and mass number AA of the parent nucleus: (a) α\alpha-decay, (b) β\beta^--decay, (c) β+\beta^+-decay, (d) electron capture. (4 marks)

Q3. A radioactive isotope has a half-life of 8.0 days. Calculate: (a) its decay constant λ\lambda (in day1^{-1}), (b) its mean life τ\tau, (c) the fraction of the original sample remaining after 24 days. (5 marks)

Q4. State the first-order decay law and derive the relation between half-life t1/2t_{1/2} and the decay constant λ\lambda. (4 marks)

Q5. The uranium-238 series ends at a stable lead isotope 82206Pb^{206}_{82}\text{Pb}. (a) Determine the total number of α\alpha and β\beta^- particles emitted in the complete series. (b) State the name given to the "4n+24n+2" series. (4 marks)

Q6. Define the Q-value of a nuclear reaction. Calculate the Q-value (in MeV) for the D–T fusion reaction 12H+13H24He+01n^2_1\text{H} + {}^3_1\text{H} \rightarrow {}^4_2\text{He} + {}^1_0\text{n} given masses (u): 2^2H = 2.01410, 3^3H = 3.01605, 4^4He = 4.00260, n = 1.00867. (1 u = 931.5 MeV) (5 marks)

Q7. (a) Define critical mass. (b) State two differences between a thermal reactor and a fast reactor. (c) What is the role of a moderator? (4 marks)

Q8. A bone sample shows a 14^{14}C activity that is 25% of the activity of living tissue. Given the half-life of 14^{14}C is 5730 years, estimate the age of the sample. (4 marks)

Q9. Match the radiation-safety units with the quantities they measure and give the SI definition of each: (a) becquerel (Bq), (b) gray (Gy), (c) sievert (Sv). State one common shielding material for γ\gamma-rays. (4 marks)

Q10. State one medical application each of (a) Tc-99m and (b) I-131, and explain why Pu-238 is used in radioisotope thermoelectric generators (RTGs) for spacecraft. (2 marks)


End of Paper

Answer keyMark scheme & solutions

Q1. (4 marks) (a) Magic numbers — numbers of protons or neutrons (2, 8, 20, 28, 50, 82, 126) at which nuclei show extra stability, corresponding to closed nuclear shells. (1) (b) Binding energy per nucleon — the total nuclear binding energy divided by the mass number AA; measures average energy needed to remove one nucleon. (2) Peaks near 56^{56}Fe because attractive nuclear force saturates while Coulomb repulsion grows with ZZ; the balance gives maximum stability (~8.8 MeV/nucleon) around iron. (1)

Q2. (4 marks) (1 each) (a) α\alpha: ZZ2Z \to Z-2, AA4A \to A-4. (b) β\beta^-: ZZ+1Z \to Z+1, AA unchanged. (c) β+\beta^+: ZZ1Z \to Z-1, AA unchanged. (d) EC: ZZ1Z \to Z-1, AA unchanged.

Q3. (5 marks) (a) λ=ln2t1/2=0.6938.0=0.0866 day1\lambda = \dfrac{\ln 2}{t_{1/2}} = \dfrac{0.693}{8.0} = 0.0866\ \text{day}^{-1}. (2) (b) τ=1λ=t1/20.693=11.5 days\tau = \dfrac{1}{\lambda} = \dfrac{t_{1/2}}{0.693} = 11.5\ \text{days}. (1) (c) After 24 days = 3 half-lives: fraction =(1/2)3=1/8=0.125= (1/2)^3 = 1/8 = 0.125 (12.5%). (2)

Q4. (4 marks) Law: rate of decay dNdt=λN-\dfrac{dN}{dt} = \lambda N (first order). (1) Integrate: dNN=λdtlnN=λt+C\dfrac{dN}{N} = -\lambda\,dt \Rightarrow \ln N = -\lambda t + C, so N=N0eλtN = N_0 e^{-\lambda t}. (2) At t=t1/2t=t_{1/2}, N=N0/2N = N_0/2: 12=eλt1/2ln2=λt1/2\tfrac12 = e^{-\lambda t_{1/2}} \Rightarrow \ln 2 = \lambda t_{1/2}, hence t1/2=ln2λ=0.693λt_{1/2} = \dfrac{\ln 2}{\lambda} = \dfrac{0.693}{\lambda}. (1)

Q5. (4 marks) (a) Mass change =238206=32=4×nαnα=8= 238 - 206 = 32 = 4 \times n_\alpha \Rightarrow n_\alpha = 8. (1.5) Charge: α\alpha decays reduce ZZ by 2×8=162\times8 = 16, from 92 to 9216=7692-16 = 76; actual Z=82Z=82, so β\beta^- needed =8276=6= 82 - 76 = 6. (1.5) So 8 α and 6 β⁻. (b) The 4n+24n+2 series is the uranium (radium) series. (1)

Q6. (5 marks) Definition: Q-value = energy released (or absorbed) in a nuclear reaction = (ΣmreactantsΣmproducts)c2(\Sigma m_{\text{reactants}} - \Sigma m_{\text{products}})c^2; positive Q means exothermic. (1) Δm=(2.01410+3.01605)(4.00260+1.00867)\Delta m = (2.01410 + 3.01605) - (4.00260 + 1.00867) =5.030155.01127=0.01888 u= 5.03015 - 5.01127 = 0.01888\ \text{u}. (2) Q=0.01888×931.5=17.59 MeVQ = 0.01888 \times 931.5 = 17.59\ \text{MeV}. (2)

Q7. (4 marks) (a) Critical mass: minimum mass of fissile material needed to sustain a self-propagating chain reaction (neutron multiplication factor k=1k=1). (1) (b) Any two: thermal reactor uses slow (thermal) neutrons + moderator, uses 235^{235}U-enriched fuel; fast reactor uses fast neutrons, no moderator, uses higher-enrichment fuel / can breed 239^{239}Pu. (2) (c) Moderator slows fast neutrons to thermal energies to increase fission probability in 235^{235}U. (1)

Q8. (4 marks) 25%=(1/2)nn=225\% = (1/2)^n \Rightarrow n = 2 half-lives. (2) Age =2×5730=11460= 2 \times 5730 = 11460 years. (2)

Q9. (4 marks) (1 each) (a) Bq — activity; 1 Bq = 1 decay per second. (b) Gy — absorbed dose; 1 Gy = 1 J kg1^{-1}. (c) Sv — equivalent (biological) dose; = absorbed dose × radiation weighting factor, unit J kg1^{-1}. Shielding for γ-rays: lead (or concrete). (1)

Q10. (2 marks) (a) Tc-99m: γ-emitting tracer for imaging (e.g. bone/organ scans). (0.5) (b) I-131: treatment/diagnosis of thyroid disorders (β/γ emitter). (0.5) Pu-238: long half-life (~88 yr) α-emitter producing steady heat converted to electricity by thermocouples — reliable, long-lived power where solar is impractical. (1)

[
  {"claim":"Half-life 8 days gives decay constant 0.0866/day",
   "code":"lam=ln(2)/8; result = abs(float(lam)-0.0866)<0.001"},
  {"claim":"Fraction remaining after 24 days (3 half-lives) is 0.125",
   "code":"f=(Rational(1,2))**3; result = f==Rational(1,8)"},
  {"claim":"U-238 to Pb-206 emits 8 alpha and 6 beta particles",
   "code":"na=(238-206)/4; nb=82-(92-2*na); result = (na==8 and nb==6)"},
  {"claim":"D-T fusion Q-value is 17.59 MeV",
   "code":"dm=(2.01410+3.01605)-(4.00260+1.00867); Q=dm*931.5; result = abs(Q-17.59)<0.05"},
  {"claim":"C-14 activity 25% corresponds to 11460 years",
   "code":"n=log(4)/log(2); age=n*5730; result = abs(float(age)-11460)<1"}
]