Before you can read the parent topic, you must own every symbol it throws at you. This page builds each one from a picture — no symbol appears until it is earned.
Inside a running engine the chamber pressure is never perfectly steady. It has a big average part and a small wobble part riding on top:
Why the topic needs this split: stability is never about the big steady pˉ. It is about whether the little wobble p′ grows or shrinks over time. So we watch p′ like a hawk. (Keep the three in mind: pc is the full instantaneous chamber pressure, pˉ its average, p′ its wobble.)
Why the topic needs phase: the entire fate of the engine is set by when heat arrives relative to pressure. "In phase" heat feeds the wobble; "out of phase" heat starves it. Phase is the language for "when."
Why: adding heat to a gas at fixed volume raises its pressure — so q′ is the "shove" that can push p′. The two are physically linked; that link is the whole game.
Now we combine the two wobbles. Their productp′q′ answers one question: are they moving together?
Now the complete criterion — all three sign cases:
∮p′q′dt⎩⎨⎧>0=0<0⇒wobble grows (unstable)⇒neutral (neither grows nor decays)⇒wobble shrinks (stable, damped)
Why the topic needs ∮: a single instant means nothing — heat can help now and hurt later. Only the balance over one whole cycle decides growth, decay, or a knife-edge neutral state. That balance is the Rayleigh Criterion.
To turn heat into pressure and pressure into frequency, we need the gas's personality.
Why a looks like this — and why a square root: pressure waves are just sound. How fast a disturbance runs across the chamber sets the fast clock (screaming). The formula is not hand-waving: a sound wave is a tiny ripple where pressure p and density ρ rise and fall together, and by definition its speed obeys a2=∂p/∂ρ (how steeply pressure climbs as you compress the gas — the "stiffness" of the gas divided by how heavy it is). For an ideal gas the equation of state p=ρRgasT (pressure = density × gas constant × temperature) combined with the fact that sound compressions are fast and springy (adiabatic, which brings in γ) gives exactly a2=γRgasTc. Taking the square root gives a. So the is a genuine consequence of "speed squared = pressure stiffness per density," not a slogan.
Which quantity, if quartered, drops a by a factor 2?
any of γ, Rgas, or Tc (they sit under one square root, so dividing one by 4 divides a by 4=2)
Why: a bigger drop forces a stiffer, more steady flow. When chamber pressure pc dips, the drop grows and more propellant rushes in — that response is the seed of chugging. See Injector Design & Pressure Drop.
Why τ is the star of chugging: the whole low-frequency loop is timed by this one delay. The parent's headline result fchug∼1/(4τ) says: quarter-cycle of delay lines the late heat up with rising pressure.
These build the fast clock (screaming), the ringing of the gas — see Acoustic Modes of a Cylindrical Cavity.
The figure below shows the most dangerous of these patterns so you can picture what a "mode" actually is:
How to read the figure: the circle is the chamber's round cross-section (radius R marked by the arrow from the centre). In the first tangential (1T) mode the gas pressure is high on one side (pink half) and low on the other (blue half) at one instant; a moment later they swap. The yellow double-arrow shows the gas sloshing side to side across the chamber. This is the worst offender because that sloshing scrubs hot gas along the wall and can melt it in seconds — which is exactly why the topic cares about tangential modes and their Bessel root α10.
Why: these plug into the mode-frequency formula to give kHz whistles, the fast clock that produces screaming.