2.5.7Optics

Power of a lens, combination of lenses

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1. What is Power?

WHY define it this way? Imagine a ray parallel to the axis hitting a lens at height hh from the axis. After refraction it crosses the axis at the focus, a distance ff away. The angle of bending δ\delta satisfies (for small angles): tanδδ=hf\tan\delta \approx \delta = \frac{h}{f}

So the bending angle per unit height =δh=1f= \dfrac{\delta}{h} = \dfrac{1}{f}. This is exactly the deviation-producing strength of the lens — and that is precisely what we christen power. Hence P=1/fP = 1/f is not arbitrary; it is the natural measure of "deviation per unit ray height."


2. Combination of Thin Lenses in Contact

Derivation from scratch (two thin lenses in contact):

Place two thin lenses of focal lengths f1,f2f_1, f_2 touching each other. An object at distance uu forms an image through lens 1.

Step 1 — Lens 1 alone: 1v11u=1f1\frac{1}{v_1} - \frac{1}{u} = \frac{1}{f_1} Why this step? This is the thin-lens equation applied to the first lens; v1v_1 is its image, which becomes the object for lens 2.

Step 2 — Lens 2 alone: The image I1I_1 (at v1v_1) acts as the object for lens 2. Since the lenses are in contact, the object distance for lens 2 is also v1v_1: 1v1v1=1f2\frac{1}{v} - \frac{1}{v_1} = \frac{1}{f_2} Why this step? Lens 2 takes whatever lens 1 produced and refracts again; final image is at vv.

Step 3 — Add the equations: Add them so v1v_1 cancels: 1v1u=1f1+1f2\frac{1}{v} - \frac{1}{u} = \frac{1}{f_1} + \frac{1}{f_2} Why this step? The intermediate v1v_1 is internal bookkeeping — it must vanish, leaving an equation in object/image only.

Step 4 — Define the equivalent lens: Compare with 1v1u=1F\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{F}: 1F=1f1+1f2P=P1+P2\boxed{\frac{1}{F} = \frac{1}{f_1} + \frac{1}{f_2}} \quad\Longleftrightarrow\quad \boxed{P = P_1 + P_2}

Figure — Power of a lens, combination of lenses

3. Lenses Separated by a Distance dd

WHY the extra term? When the lenses are apart, the ray bent by lens 1 travels a distance dd and lands at a different height on lens 2 than it entered lens 1. Lens 2's bending depends on that height, so the bends no longer add cleanly — the correction term dP1P2-dP_1P_2 accounts for this. Note when d=0d=0 it reduces to P1+P2P_1+P_2 ✓ (a good sanity check).


4. Worked Examples


5. Common Mistakes


Recall Feynman: explain to a 12-year-old

A lens is like a slide that pushes light toward one spot. A "strong" lens pushes the light really hard, so it meets quickly — that strong push is its power. A "weak" lens pushes gently, light meets far away. We measure the push with a number called dioptres. If you put two lenses right against each other, you get both pushes one after another — so you just add their power numbers. A concave lens pushes light outward instead, so we give it a minus push that cancels some of the plus.


Flashcards

What is the power of a lens, and its unit?
P=1/fP = 1/f (f in metres); unit = dioptre (D) = m⁻¹.
A lens has f=25f=-25 cm. What is its power?
P=1/(0.25)=4DP = 1/(-0.25) = -4\,\text{D} (concave, negative).
Why do powers add for lenses in contact?
Light is bent successively; adding the two thin-lens equations cancels the intermediate image distance, giving 1/F=1/f1+1/f21/F=1/f_1+1/f_2.
Combined power of two lenses separated by distance dd?
P=P1+P2dP1P2P = P_1+P_2 - dP_1P_2.
Lenses in contact behave like which resistor configuration?
Parallel resistors (reciprocals add).
Net magnification of a lens combination?
m=m1×m2×m = m_1 \times m_2 \times \dots
Two lenses +5+5\,D and 2-2\,D in contact: net power and focal length?
+3+3\,D; F=+33.3F=+33.3 cm.
Why does small focal length mean high power?
Bending angle per unit ray height =1/f=1/f, so smaller ff bends light more strongly.

Connections

  • Thin Lens Equation — the foundation we added together to get 1/F1/F.
  • Lensmaker's Equation — gives P=(n1)(1/R11/R2)P=(n-1)(1/R_1-1/R_2).
  • Magnification of Lenses — net mm multiplies.
  • Microscope and Telescope — use lens combinations (objective + eyepiece).
  • Resistors in Parallel — same reciprocal-addition mathematics.
  • Defects of Vision — spectacle power in dioptres prescribed by opticians.

Concept Map

reciprocal

SI unit

equals 1 over f

gives

larger n or small R

so

so

add to

add to

yields

in terms of power

enables

Focal length f

Power P equals 1 over f

Dioptre D

Ray bending delta over h

Lensmaker relation

P equals n minus 1 times curvature

More power

Convex lens f positive

P positive

Concave lens f negative

P negative

Lens 1 equation

Cancel v1

Lens 2 equation

1 over F equals sum of 1 over f

P equals P1 plus P2

Hinglish (regional understanding)

Intuition Hinglish mein samjho

Dekho, lens ka kaam hai light ko mod-na (bend karna). Jo lens light ko zyada zor se modta hai, woh "strong" hai aur uska focal length chhota hota hai. Is strength ko hum power kehte hain, aur formula simple hai: P=1/fP = 1/f, jahan ff metre mein hona chahiye. Unit hai dioptre (D). Convex lens ka power positive, concave ka negative. Yaad rakho — chhota ff matlab bada power, kyunki bending angle =h/f= h/f hota hai.

Jab do lens ek doosre se chipke (in contact) hote hain, toh light pehle lens se bend hoti hai, phir turant doosre se. Do bending ek saath add ho jaati hain, isliye P=P1+P2P = P_1 + P_2. Isko derive karne ke liye dono lens ka thin-lens equation likho aur add kar do — beech ka image distance v1v_1 cancel ho jaata hai, aur seedha 1/F=1/f1+1/f21/F = 1/f_1 + 1/f_2 mil jaata hai. Ye bilkul parallel resistors jaisa hai, series jaisa NAHI — yahi sabse common galti hai.

Agar lenses ke beech gap dd ho, toh ek extra term aata hai: P=P1+P2dP1P2P = P_1 + P_2 - dP_1P_2. Kyun? Kyunki gap mein ray thodi spread ho jaati hai aur doosre lens pe alag height pe girti hai, isliye correction chahiye. Check: agar d=0d=0 ho toh wapas P1+P2P_1+P_2 aa jaata hai — perfect.

Exam tip: hamesha pehle cm ko metre mein convert karo, sign dhyan se lagao (concave = minus), aur "Power Inverts, Contact Adds" yaad rakho. Bas itna pakka kar lo, ye topic full marks ka hai!

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