WHY define it this way?
Imagine a ray parallel to the axis hitting a lens at height h from the axis. After refraction it crosses the axis at the focus, a distance f away. The angle of bending δ satisfies (for small angles):
tanδ≈δ=fh
So the bending angle per unit height=hδ=f1. This is exactly the deviation-producing strength of the lens — and that is precisely what we christen power. Hence P=1/f is not arbitrary; it is the natural measure of "deviation per unit ray height."
Derivation from scratch (two thin lenses in contact):
Place two thin lenses of focal lengths f1,f2 touching each other. An object at distance u forms an image through lens 1.
Step 1 — Lens 1 alone:v11−u1=f11Why this step? This is the thin-lens equation applied to the first lens; v1 is its image, which becomes the object for lens 2.
Step 2 — Lens 2 alone: The image I1 (at v1) acts as the object for lens 2. Since the lenses are in contact, the object distance for lens 2 is also v1:
v1−v11=f21Why this step? Lens 2 takes whatever lens 1 produced and refracts again; final image is at v.
Step 3 — Add the equations: Add them so v1 cancels:
v1−u1=f11+f21Why this step? The intermediate v1 is internal bookkeeping — it must vanish, leaving an equation in object/image only.
Step 4 — Define the equivalent lens: Compare with v1−u1=F1:
F1=f11+f21⟺P=P1+P2
WHY the extra term? When the lenses are apart, the ray bent by lens 1 travels a distance d and lands at a different height on lens 2 than it entered lens 1. Lens 2's bending depends on that height, so the bends no longer add cleanly — the correction term −dP1P2 accounts for this. Note when d=0 it reduces to P1+P2 ✓ (a good sanity check).
A lens is like a slide that pushes light toward one spot. A "strong" lens pushes the light really hard, so it meets quickly — that strong push is its power. A "weak" lens pushes gently, light meets far away. We measure the push with a number called dioptres. If you put two lenses right against each other, you get both pushes one after another — so you just add their power numbers. A concave lens pushes light outward instead, so we give it a minus push that cancels some of the plus.
Dekho, lens ka kaam hai light ko mod-na (bend karna). Jo lens light ko zyada zor se modta hai, woh "strong" hai aur uska focal length chhota hota hai. Is strength ko hum power kehte hain, aur formula simple hai: P=1/f, jahan fmetre mein hona chahiye. Unit hai dioptre (D). Convex lens ka power positive, concave ka negative. Yaad rakho — chhota f matlab bada power, kyunki bending angle =h/f hota hai.
Jab do lens ek doosre se chipke (in contact) hote hain, toh light pehle lens se bend hoti hai, phir turant doosre se. Do bending ek saath add ho jaati hain, isliye P=P1+P2. Isko derive karne ke liye dono lens ka thin-lens equation likho aur add kar do — beech ka image distance v1 cancel ho jaata hai, aur seedha 1/F=1/f1+1/f2 mil jaata hai. Ye bilkul parallel resistors jaisa hai, series jaisa NAHI — yahi sabse common galti hai.
Agar lenses ke beech gap d ho, toh ek extra term aata hai: P=P1+P2−dP1P2. Kyun? Kyunki gap mein ray thodi spread ho jaati hai aur doosre lens pe alag height pe girti hai, isliye correction chahiye. Check: agar d=0 ho toh wapas P1+P2 aa jaata hai — perfect.
Exam tip: hamesha pehle cm ko metre mein convert karo, sign dhyan se lagao (concave = minus), aur "Power Inverts, Contact Adds" yaad rakho. Bas itna pakka kar lo, ye topic full marks ka hai!