Level 2 — RecallOptics

Optics

30 minutes40 marksprintable — key stays hidden on paper

Level 2: Recall — Definitions, Standard Problems, Short Derivations

Time Limit: 30 minutes
Total Marks: 40

Instructions: Answer all questions. Use the standard sign convention (distances measured from the pole/optical centre, real-is-positive not assumed — Cartesian convention). Take c=3×108m/sc = 3\times10^{8}\,\text{m/s} where needed.


Q1. State Snell's law of refraction and define the critical angle. Derive the expression for the critical angle in terms of the refractive indices of two media. (4 marks)

Q2. An object is placed 15cm15\,\text{cm} in front of a concave mirror of focal length 10cm10\,\text{cm}. Find the position, nature and magnification of the image. (5 marks)

Q3. State Malus's law. A beam of intensity I0I_0 passes through two ideal polarizers whose transmission axes are inclined at 3030^\circ. Find the intensity of the emerging light (assume the incident light is already polarized along the first axis). (4 marks)

Q4. Write the lens maker's equation for a thin lens. A biconvex lens has both radii of magnitude 20cm20\,\text{cm} and is made of glass of refractive index 1.51.5. Calculate its focal length and power. (5 marks)

Q5. In Young's double-slit experiment, derive the expression for fringe width β\beta. Hence calculate β\beta for slit separation d=0.5mmd = 0.5\,\text{mm}, screen distance D=1mD = 1\,\text{m} and wavelength λ=600nm\lambda = 600\,\text{nm}. (5 marks)

Q6. State the condition for principal maxima in a diffraction grating. A grating has 50005000 lines per cm. Find the angle of the first-order maximum for light of wavelength 500nm500\,\text{nm}. (4 marks)

Q7. Two thin lenses of powers +5D+5\,\text{D} and 2D-2\,\text{D} are placed in contact. Find the power and focal length of the combination. (3 marks)

Q8. State Brewster's law and derive the relation tanθB=n\tan\theta_B = n (refractive index) using the condition that the reflected and refracted rays are perpendicular. (5 marks)

Q9. Distinguish between chromatic aberration and spherical aberration, giving one method of reducing each. (3 marks)

Q10. State Rayleigh's criterion for resolution and write the expression for the limit of resolution of a telescope of aperture diameter DD. (2 marks)


End of Paper

Answer keyMark scheme & solutions

Q1. (4 marks)

  • Snell's law: n1sinθ1=n2sinθ2n_1\sin\theta_1 = n_2\sin\theta_2 — ratio of sines equals inverse ratio of refractive indices. (1)
  • Critical angle θc\theta_c: the angle of incidence in the denser medium for which the angle of refraction is 9090^\circ. (1)
  • Derivation: put θ1=θc\theta_1 = \theta_c (denser n1n_1) and θ2=90\theta_2 = 90^\circ: n1sinθc=n2sin90n_1\sin\theta_c = n_2\sin90^\circ. (1)
  • So sinθc=n2/n1\sin\theta_c = n_2/n_1, i.e. θc=sin1(n2/n1)\theta_c = \sin^{-1}(n_2/n_1) (for n1>n2n_1>n_2). (1)

Q2. (5 marks)

  • Sign convention: u=15cmu=-15\,\text{cm}, f=10cmf=-10\,\text{cm} (concave). (1)
  • Mirror equation 1v+1u=1f1v=1f1u=110115\dfrac1v+\dfrac1u=\dfrac1f \Rightarrow \dfrac1v = \dfrac1f-\dfrac1u = \dfrac{1}{-10}-\dfrac{1}{-15}. (1)
  • 1v=110+115=3+230=130v=30cm\dfrac1v = -\dfrac1{10}+\dfrac1{15} = \dfrac{-3+2}{30}=-\dfrac1{30}\Rightarrow v=-30\,\text{cm}. (1)
  • Magnification m=vu=3015=2m=-\dfrac{v}{u}=-\dfrac{-30}{-15}=-2. (1)
  • Image at 30cm30\,\text{cm} in front, real, inverted, magnified (2×2\times). (1)

Q3. (4 marks)

  • Malus's law: I=I0cos2θI = I_0\cos^2\theta, where θ\theta is the angle between the polarizer axis and the plane of polarization of incident light. (2)
  • θ=30\theta=30^\circ: I=I0cos230=I0×(0.866)2=0.75I0I = I_0\cos^2 30^\circ = I_0\times(0.866)^2 = 0.75\,I_0. (2)

Q4. (5 marks)

  • Lens maker's equation: 1f=(n1)(1R11R2)\dfrac1f = (n-1)\left(\dfrac1{R_1}-\dfrac1{R_2}\right). (1)
  • Biconvex: R1=+20cmR_1=+20\,\text{cm}, R2=20cmR_2=-20\,\text{cm}. (1)
  • 1f=(1.51)(120120)=0.5×220=0.5×0.1=0.05cm1\dfrac1f = (1.5-1)\left(\dfrac1{20}-\dfrac1{-20}\right)=0.5\times\dfrac{2}{20}=0.5\times0.1=0.05\,\text{cm}^{-1}. (1)
  • f=20cm=0.20mf = 20\,\text{cm}=0.20\,\text{m}. (1)
  • Power P=1f(m)=10.20=+5DP=\dfrac1{f(\text{m})}=\dfrac1{0.20}=+5\,\text{D}. (1)

Q5. (5 marks)

  • Path difference at point yy: Δ=dsinθdyD\Delta = d\sin\theta \approx \dfrac{d\,y}{D}. (1)
  • Bright fringes: dynD=nλyn=nλDd\dfrac{d\,y_n}{D}=n\lambda \Rightarrow y_n=\dfrac{n\lambda D}{d}. (1)
  • Fringe width β=yn+1yn=λDd\beta = y_{n+1}-y_n = \dfrac{\lambda D}{d}. (1)
  • Substitute: β=600×109×10.5×103\beta = \dfrac{600\times10^{-9}\times1}{0.5\times10^{-3}}. (1)
  • β=1.2×103m=1.2mm\beta = 1.2\times10^{-3}\,\text{m}=1.2\,\text{mm}. (1)

Q6. (4 marks)

  • Grating condition: dsinθ=nλd\sin\theta = n\lambda (principal maxima). (1)
  • Grating spacing d=1cm5000=2×104cm=2×106md = \dfrac{1\,\text{cm}}{5000}=2\times10^{-4}\,\text{cm}=2\times10^{-6}\,\text{m}. (1)
  • sinθ=nλd=1×500×1092×106=0.25\sin\theta = \dfrac{n\lambda}{d}=\dfrac{1\times500\times10^{-9}}{2\times10^{-6}}=0.25. (1)
  • θ=sin1(0.25)=14.48\theta = \sin^{-1}(0.25)=14.48^\circ. (1)

Q7. (3 marks)

  • Powers in contact add: P=P1+P2=5+(2)=+3DP = P_1+P_2 = 5+(-2)=+3\,\text{D}. (2)
  • f=1P=13m=+33.3cmf = \dfrac1P = \dfrac1{3}\,\text{m}=+33.3\,\text{cm}. (1)

Q8. (5 marks)

  • Brewster's law: when light is incident at the polarizing angle θB\theta_B, the reflected light is completely plane-polarized; reflected and refracted rays are mutually perpendicular. (1)
  • Geometry: θB+90+θr=180θr=90θB\theta_B + 90^\circ + \theta_r = 180^\circ \Rightarrow \theta_r = 90^\circ-\theta_B. (1)
  • Snell: n=sinθBsinθr=sinθBsin(90θB)n = \dfrac{\sin\theta_B}{\sin\theta_r}=\dfrac{\sin\theta_B}{\sin(90^\circ-\theta_B)}. (1)
  • =sinθBcosθB=\dfrac{\sin\theta_B}{\cos\theta_B}. (1)
  • n=tanθB\therefore n=\tan\theta_B. (1)

Q9. (3 marks)

  • Chromatic aberration: inability of a lens to focus different colours (wavelengths) at the same point, due to variation of nn with λ\lambda; reduced using an achromatic doublet (convex + concave of different glasses). (1.5)
  • Spherical aberration: failure of a spherical mirror/lens to focus marginal and paraxial rays at the same point; reduced by using stops/parabolic surfaces or plano-convex orientation. (1.5)

Q10. (2 marks)

  • Rayleigh criterion: two point sources are just resolved when the central maximum of one diffraction pattern coincides with the first minimum of the other. (1)
  • Limit of resolution: Δθ=1.22λD\Delta\theta = \dfrac{1.22\lambda}{D}. (1)
[
  {"claim":"Q2 image distance v = -30 cm","code":"u=-15; f=-10; v=1/(1/f-1/u); result = abs(v-(-30))<1e-9"},
  {"claim":"Q2 magnification m = -2","code":"u=-15; v=-30; m=-v/u; result = abs(m-(-2))<1e-9"},
  {"claim":"Q4 focal length 20 cm and power 5 D","code":"n=Rational(3,2); R1=20; R2=-20; f=1/((n-1)*(Rational(1,R1)-Rational(1,R2))); P=1/(f/100); result = (f==20) and (P==5)"},
  {"claim":"Q5 fringe width = 1.2 mm","code":"lam=600e-9; D=1; d=0.5e-3; beta=lam*D/d; result = abs(beta-1.2e-3)<1e-12"},
  {"claim":"Q6 sin theta = 0.25 for first order","code":"d=2e-6; lam=500e-9; s=1*lam/d; result = abs(s-0.25)<1e-12"},
  {"claim":"Q7 combined power 3 D, focal length 1/3 m","code":"P=5+(-2); f=1/P; result = (P==3) and abs(f-Rational(1,3))<1e-12"},
  {"claim":"Q3 Malus 30 deg gives 0.75 I0","code":"val=cos(pi/6)**2; result = simplify(val-Rational(3,4))==0"}
]