This page assumes you have seen none of the notation on the parent note. We build every symbol from the ground up, in the order they depend on each other. Nothing is used before it is drawn.
Since the whole page keeps pointing back to them, let us state the two rules of Special Relativity up front, in plain words.
We will lean on Postulate 2 especially: it is the reason the photon in our light-clock (§6) is forced to travel at exactly c even when the clock is sliding sideways.
Before any physics, we need the two most basic words.
Look at the figure: the black grid belongs to a person standing still; the red grid belongs to someone gliding to the right. The same event (the dot) sits at different grid coordinates for each — that is the entire drama of relativity in one picture.
Not every frame is fair game. Postulate 1 only speaks about inertial frames.
Before the picture-test, we must name the "mysterious tug".
The picture-test: put a ball on a frictionless table.
On a smoothly cruising train → ball stays put. Inertial. ✓
On a train that suddenly brakes → ball rolls forward with no one touching it. That phantom shove is a pseudo-force; the braking frame is non-inertial. ✗
On a spinning merry-go-round → the ball curves sideways on its own (the Coriolis pseudo-force), and feels flung outward. A rotating frame is therefore also non-inertial, even at constant spin rate — because turning is a kind of acceleration. ✗
Why the topic needs it: Postulate 1 is only claimed for inertial frames. Accelerating and rotating frames need General Relativity — a different, later story.
The red arrow is the velocity of the moving frame. Throughout the parent note, v is always the relative speed between two observers — never the speed of light, which gets its own letter (next).
The single most important fact — the thing that makes relativity relativity — is that every inertial observer measures this samec (that is exactly Postulate 2), even if they are chasing the light beam. Contrast this with v, which is different for different observers.
Recall Why the letter "c"?
It comes from Latin celeritas ("swiftness"). You don't need the etymology — just remember c is reserved for light and never means anything else.
Now we combine two symbols we own. The parent note constantly writes v2/c2. Let's earn every piece.
v/c = "what fraction of light-speed am I going?" A rocket at v=0.6c has v/c=0.6, i.e. 60% of light-speed.
Squaring (v2/c2) removes the sign: whether you move left or right, v2 is positive. Direction shouldn't change how much time slows, so squaring is exactly the right tool — it answers "how fast" while ignoring "which way".
The parent's key expression is 1−v2/c2. Where does this exact shape come from? From Pythagoras applied to a device called the light-clock. First, what is that device?
Now watch the same clock from a frame in which it glides right at speed v. Consider one half-tick (light going from bottom mirror up to top mirror). Two frames watch it:
In the clock's own rest frame the light just goes straight up a distance L0, taking a proper half-tick time we will label 21Δt0.
In the frame where the clock moves, the top mirror slides forward while the light climbs, so the light traces a diagonal. Call this observer's half-tick time 21Δt (this is the moving-frame interval — the very Δt we define in §8).
The diagonal (red) is the hypotenuse of a right triangle whose three sides, all measured in the moving frame, are:
vertical leg=L0 (the mirror gap — unchanged, because motion is sideways, not up-down),
horizontal leg=v⋅21Δt (how far the mirror slid during this half-tick),
hypotenuse=c⋅21Δt (the light's actual path — it must go at c, by Postulate 2, even though its path is longer).
Step 1 — apply Pythagoras (leg² + leg² = hypotenuse²). Writing τ≡21Δt to keep the algebra clean:
L02+(vτ)2=(cτ)2What we did: related the three sides. Why: the right triangle is exactly what "moving light-clock" draws, and Pythagoras is the one tool linking legs to hypotenuse.
Step 2 — gather the τ2 terms on one side:c2τ2−v2τ2=L02⇒τ2(c2−v2)=L02
Step 3 — solve for τ by dividing then taking a square root:
τ=c2−v2L0
Step 4 — pull a c out of the root so the fraction v2/c2 appears. Write c2−v2=c2(1−c2v2), and c2(⋯)=c⋯:
τ=c1−v2/c2L0
There it is: the exact shape 1−v2/c2emerges from the triangle, not by decree. In the clock's own rest frame the half-tick is just L0/c (no sideways slide), so the moving observer's half-tick τ is longer by the factor 1/1−v2/c2. Doubling both to get full ticks turns this into the parent note's Δt=γΔt0 once we name that factor (§7).
Note 1−v2/c2 is always between 0 and 1 (since v2/c2 sits between 0 and 1), so its square root is also between 0 and 1.
Since the bottom (denominator) is a number between 0 and 1, dividing 1 by it gives something ≥1. So γ is always at least 1, and grows without bound as v→c.
Read the curve: at low v it hugs 1 (Newton's world), then rockets skyward near v=c. Every relativistic effect — slower clocks, shorter rulers — is measured by how far above 1γ has climbed. A few landmark values:
The symbol Δ (Greek "delta") means "a change in" or "an interval of". So Δt = "an amount of elapsed time" — the gap between two events' timestamps.
The parent's headline result is Δt=γΔt0. Because γ≥1, the moving observer always measures a longer interval — the moving clock is seen to tick slow. That is Time Dilation.
A length is a distance in metres — like the mirror gap in the light-clock. But just like time, a length depends on who measures it, so we keep two symbols, exactly matching the L0 we already used in §6.
This same γ that stretched time now shrinks length.
Read the chain top-down. Frames (built from events) tell us who measures. The two speeds c and v form the ratio v2/c2. Pythagoras on the moving light-clock shapes that ratio into 1−v2/c2, whose reciprocal is the Lorentz factor γ. Finally γ, together with the two postulates ("same laws" forces "c is constant"), produces time dilationΔt=γΔt0 and length contraction L=L0/γ.
who measuresevent→frame→inertial⟶the stretch factorc,v→c2v2→1−c2v2→γ⟶the payoffΔt=γΔt0
A single happening pinned to one place and one moment — a dot with a timestamp.
What does a "frame of reference" physically consist of?
An observer's own ruler (for position) and their own clock (for time).
State the two postulates of SR in plain words.
(1) The laws of physics are the same for every constant-velocity observer; (2) the speed of light in vacuum is the same number for all of them, whatever the source or observer does.
What makes a frame inertial?
A free object stays still or moves straight at constant speed — no pseudo-forces appear.
What is a pseudo-force and how does it differ from a real force?
It has no physical source; it appears only because your frame is accelerating (or rotating) and vanishes in a non-accelerating frame.
Is a car turning at constant speed inertial?
No — its direction changes, so its velocity changes; it is accelerating.
Is a steadily spinning merry-go-round inertial?
No — rotation is acceleration; it introduces pseudo-forces (e.g. Coriolis).
What does the symbol v stand for, and its picture?
The relative speed between two frames, in m/s, drawn as an arrow (length = fast, direction = which way).
What is special about c compared to v?
c is the same for every inertial observer (Postulate 2); v differs from observer to observer.
Why do we square in v2/c2?
To ignore direction (sign) and keep only "how fast"; squaring makes left/right motion count the same.
What is the value range of v2/c2?
Between 0 (rest) and just under 1 (near light-speed); it never reaches 1.
What is a light-clock, and what counts as one tick?
Two mirrors a gap L0 apart; a light flash bounces up and down, and one up-and-down round trip is one tick.
Where does 1−v2/c2 come from, in one line of algebra?
From L02+(vτ)2=(cτ)2, solved for the half-tick τ and factoring a c out of the root.
Why is γ≥1 always?
Because γ is 1 divided by a number that lies strictly between 0 and 1 (namely 1−v2/c2), and dividing 1 by something less than 1 always gives a result at least 1.
Difference between Δt0 and Δt?
Δt0 is proper time (clock's own frame, same place); Δt is the longer time a moving observer measures.
Difference between proper length L0 and contracted length L?
L0 is measured in the object's rest frame; L=L0/γ is the shorter length a moving observer sees along the motion.
Which way does the multiply go in time dilation?
Δt=γΔt0 — multiply the proper time by γ to get the bigger observed time.