Intuition The one core idea
Out of all imaginable routes a system could take between a fixed start and a fixed finish, nature picks the single route where one running total — the action — stops changing under any tiny nudge of the path. To even read that sentence in symbols, you first need to speak "function", "derivative", "integral", and "a number that eats a whole function"; this page builds every one of those from nothing.
This page is the toolbox for the parent derivation . Nothing here is assumed — we start below zero.
Picture a bead sliding along a wire. At each moment in time it sits somewhere . That "somewhere" is a single number if the wire is a straight track.
t and coordinate q
t (plain word: time ) is the clock reading. Picture: a number on a stopwatch that only goes up.
q (a generalized coordinate ) is "where the system is right now", boiled down to a number. For a bead on a wire, q is the distance along the wire. For a pendulum, q could be the swing angle.
Why "generalized"? So the same machinery works whether the natural label is a length, an angle, or anything else. The topic needs ONE symbol that means "the state" regardless of the setup.
Look at the blue curve above: the horizontal axis is time t , the vertical axis is position q . A single dot is "where the bead is at that instant". String all the dots together and you get a path .
q ( t )
A function is a machine: feed it a time t , it hands back the position q at that time. We write it q ( t ) , read "q of t".
Picture: the whole blue curve in the figure above — the complete history of the bead, not just one moment.
Intuition Two different things wearing the letter q
The function q (or "q ( ⋅ ) ") is the whole path — the entire blue curve.
The value q ( t ) is the single number the path returns at one instant t — one dot on the curve.
Keep these apart: variations act on the whole path, while energies are computed from the instantaneous value.
Intuition Why the parent obsesses over "the whole path"
Newton describes motion instant-by-instant (force now → acceleration now ). Hamilton's principle instead judges the entire curve at once . So the fundamental object we manipulate is a whole function q , not a single number. Hold that thought — it's the whole plot twist.
Related deeper ideas live in Newton's Second Law and Lagrangian Mechanics .
The bead isn't just somewhere ; it's moving . How fast?
Definition The dot means "rate of change in time"
q ˙ (read "q-dot") is the velocity : how fast q changes each second. It is the derivative of q with respect to t , written d t d q .
Picture: the steepness (slope) of the blue curve at a point. Steep curve = moving fast; flat curve = momentarily still.
Intuition WHY a derivative and not just a difference?
We want the instantaneous speed — the slope exactly at time t , not the average over a chunk. The derivative answers precisely the question: "if I zoom into the curve until it looks straight, what is its slope?" That is what the calculus limit delivers.
The orange line is the tangent — its slope is q ˙ at that instant. This slope is the ingredient the later energies feed on; it is nothing more than "slope of the position curve".
Definition Partial derivative
∂ / ∂ ( ⋅ )
A partial derivative ∂ x ∂ f asks: "if I nudge only x and hold every other input frozen, how fast does f change?" The curly ∂ (say "partial") is the flag for "one input wiggles, the rest stay still". Picture: standing on a hilly surface and stepping due east only — the partial is the slope you feel in that one direction.
q ˙ is a separate independent variable from q ."
Why it feels right: in a formula like 2 1 m q ˙ 2 − V ( q ) we treat q and q ˙ as separate slots when taking partial derivatives (nudge one, freeze the other).
The fix: for a given path , q ˙ is completely determined by q (it's the slope). They only act "independent" while taking partial derivatives of that formula — a bookkeeping trick, not physics.
Definition Kinetic energy
T
T = energy of motion . For a mass m moving with speed q ˙ ,
T = 2 1 m q ˙ 2 .
Picture: bigger when the curve is steeper (faster). Always ≥ 0 because it uses q ˙ 2 (a square is never negative). m is the mass — "how much stuff", how hard to shove.
Definition Potential energy
V
V = stored energy of position — energy you'd get back by letting the system fall/relax. Depends on where you are: V = V ( q ) .
Picture: height on a hill. High up = large V ; valley bottom = small V .
Intuition Why the topic needs BOTH separately
The action combines them as T − V (kinetic minus potential). Newton's force is hidden inside V : the force is minus the slope of the hill, F = − d q d V . Keeping T and V apart is what lets the parent recover F = ma at the end.
The green valley is V ( q ) ; the red arrow shows the force pointing downhill , i.e. toward smaller V . That single picture is why F = − d V / d q .
minus , not plus?
This is the parent's central non-obvious choice. Justification is not a guess — plugging T − V into the machinery reproduces Newton, while T + V does not. Think "kinetic credit minus potential debt": the path negotiates between the two.
∫ t 1 t 2 ( ⋯ ) d t
The tall-S symbol ∫ means "add up continuously" . ∫ t 1 t 2 L d t slices the trip into tiny time-slivers d t , multiplies each by L at that instant, and sums them all from start time t 1 to end time t 2 .
Picture: the area under the L -vs-t curve .
Intuition Why an integral and not a plain sum?
Time flows smoothly, so we need infinitely many infinitely-thin slices. The integral is exactly "a sum that has gone continuous". It answers: "what is the total accumulated L over the whole journey?"
The shaded area is the integral. Change the path q ( t ) and L ( t ) changes, so the area changes — that changing area is the action.
S [ q ]
S [ q ] = ∫ t 1 t 2 L d t .
A functional is a machine that eats an entire function q and returns one number (an area). The square brackets S [ q ] signal "I take a whole function, not just a value".
Picture: pick any blue curve → get one number (its shaded area). Different curve → different number.
Intuition Ordinary function vs functional
Function q ( t ) : number in → number out.
Functional S [ q ] : whole curve in → number out.
The parent's entire game is: among all curves, which one makes this output number stationary ?
η ( t ) and knob ε
To test "is this path special?", nudge it:
q ε ( t ) = q ( t ) + ε η ( t ) .
η ( t ) (Greek "eta") is a wiggle-shape we're free to choose. It must be continuously differentiable (C 1 : it has no jumps and no sharp corners, so its slope η ˙ exists and is itself continuous). This smoothness is what lets us differentiate and integrate it by parts later.
ε (Greek "epsilon") is a tiny volume knob for how big the wiggle is.
Endpoints stay pinned: η ( t 1 ) = η ( t 2 ) = 0 (start and finish are fixed data).
δ S = 0 — "stationary"
δ S is the first-order change in S when you turn the knob ε slightly. Saying δ S = 0 means: nudging the path a little doesn't change the action to first order .
Picture: the bottom of a valley — flat there, so a small step sideways doesn't change your height (to first order).
The blue curve is the true path; the dashed orange curves are wiggled versions q + ε η , all pinned at the two red endpoints. The right panel shows S as a function of the knob ε : at the true path (ε = 0 ) the curve is flat — that flatness is δ S = 0 .
path is a function q of t
instantaneous value q at time t
derivative q-dot the slope
Lagrangian L equals T minus V
integral adds L over the trip
vary the path with eta and epsilon
stationary delta S equals zero
Hamilton principle derivation
Related destinations once you have these tools: Hamiltonian Mechanics , Noether's Theorem , Fermat's Principle , Feynman Path Integral .
Does the function q (the path) mean a whole curve or a single value? The whole curve — the complete history over time.
Does the value q ( t ) mean a whole curve or a single number? A single number — the position at the one instant t .
What picture is the derivative q ˙ ? The slope (steepness) of the position-vs-time curve at an instant.
What does a partial derivative ∂ f / ∂ x measure? The rate of change of f when only x is nudged and all other inputs are held frozen.
Why is T = 2 1 m q ˙ 2 always ≥ 0 ? Because q ˙ 2 is a square, and squares are never negative.
In one line, what is the force in terms of V ? Minus the slope of the potential, F = − d V / d q (points downhill).
Is L equal to T + V or T − V ? T − V — the combination that reproduces Newton.
What does the integral ∫ L d t picture as? The area under the L -versus-t curve over the trip.
How is a functional different from a function? A functional eats a whole function and returns one number; a function eats a number.
What smoothness must the wiggle η have, and why? C 1 (continuous with a continuous derivative), so its slope exists and integration by parts works.
What must η satisfy at the endpoints and why? η ( t 1 ) = η ( t 2 ) = 0 , because the endpoints are fixed data and can't move.
What does δ S = 0 mean geometrically? The action is flat (stationary) under tiny path nudges — like the bottom of a valley.
Does "stationary" guarantee a minimum? No — it can be a minimum, maximum, or saddle.