WHY the cycle matters: Ek baar ki expansion bahut saari heat ko work mein convert kar sakti hai, lekin phir gas "khatam" ho jaati hai (expand ho gayi, thandi ho gayi). Continuously chalane ke liye tumhe engine ko reset karna padta hai — aur resetting mein hamesha kuch heat dump karni padti hai.
Hum First Law (energy conservation) ko ek poore cycle par apply karte hain.
Step 1 — Cycle ke liye First Law likho.ΔU=Qnet−Wby gasWhy this step? First Law hamesha hold karta hai; hum bas ise ek complete loop ke liye specialise kar rahe hain.
Step 2 — Yeh use karo ki internal energy ek state function hai.
Ek closed cycle mein system apni starting point par wapas aa jaata hai, isliye
ΔUcycle=0Why this step?U sirf state par depend karta hai (jaise ideal gas ke liye T), path par nahi. Same start = same end = zero change.
Step 3 — Net heat identify karo.
Heat in hai QH, heat out hai QC (QH,QC>0 magnitudes liye hue hain):
Qnet=QH−QC
Step 4 — Combine karo.ΔU=0 ke saath:
0=(QH−QC)−W⟹W=QH−QCWhy this step? Jo bhi heat dump nahi hui woh saari work bani. Energy conserved hai.
Step 5 — Efficiency define karo "jo mila / jo diya" ke roop mein:
η≡QHW=QHQH−QC
η ka matlab words mein kya hai? → useful work out divided by heat in.
QC=0 kyun hona chahiye? → Second Law (Kelvin–Planck): heat ko cyclically poori tarah work mein convert nahi kar sakte.
ΔU=0 kyun use karte hain? → cycle start state mein wapas aata hai; U ek state function hai.
Absolute ceiling kya set karta hai? → Carnot: η=1−TC/TH, T in K.
Recall Feynman: 12-saal ke bacche ko samjhao
Ek water wheel socho. Paani ek unche tank (hot) se ek neeche tank (cold) mein girta hai, aur raaste mein wheel ghoomta hai aur work karta hai. Lekin paani gayab nahi ho sakta — usse neeche kahin utharna hi hai. Ek heat engine bilkul aisa hi hai: heat hot se cold mein "girti" hai, raaste mein tumhara engine spin karte hue, lekin kuch heat cold jagah mein jaani hi padti hai. Tum kabhi bhi wheel ko saare paani se spin nahi kar sakte aur koi bhi neeche na aaye. Jitna zyada height difference hoga (zyada hot, zyada cold), utna zyada work nikaal sakte ho.
PV diagrams and Work — cycle loop ka area = net work W.
Heat engine define karo
Ek aisa device jo cycle mein operate karta hai, hot reservoir se heat QH absorb karta hai, work W karta hai, aur cold reservoir ko heat QC reject karta hai.
Efficiency formula do tareekon se batao
η=W/QH=1−QC/QH.
W=QH−QC kyun hai?
Cycle mein ΔU=0 (state function), isliye First Law se saari net heat QH−QC work ban jaati hai.
Efficiency kabhi 1 kyun nahi ho sakti?
Iske liye QC=0 chahiye, jo Kelvin–Planck (Second Law) statement violate karta hai — heat ko cyclically poori tarah work mein convert nahi kar sakte.
TH aur TC ke beech maximum possible efficiency kya hai?
Carnot: η=1−TC/TH, temperatures kelvin mein.
QC/QH kya represent karta hai?
Input heat ki woh fraction jo waste hoti hai (dump hoti hai). Yeh 1−η ke barabar hai.
Ek engine 500 J leta hai, 350 J dump karta hai. Efficiency?
W=150 J, η=150/500=30%.
Carnot formula mein common unit mistake kya hai?
°C use karna kelvin ki jagah; temperatures absolute honi chahiye.