Do opposite waves KAISE banti hain? Aam taur par ek wave kisi boundary se takraati hai (string ka fixed end, closed pipe ka end) aur wapas apne aap par reflect ho jaati hai.
Standing wave banane ke liye kya do conditions chahiye? → Equal amplitude/frequency, opposite directions.
x ka function ke roop mein amplitude? → 2Asin(kx).
Node spacing? → λ/2.
Node-to-antinode? → λ/4.
Kya yeh energy transport karta hai? → Nahi (net zero).
Recall Feynman: ek 12-saal ke bachche ko samjhao
Socho do bachche ek lambi rope ko ek doosre ki taraf exactly same rhythm mein hila rahe hain. Wiggles ek doosre se takraati hain. Kuch jagahon par rope bilkul still baithti hai — jaise ek gaanth jo kabhi nahi uchhalti (ek node). Unke beech mein rope pagalon ki tarah upar-neeche fadfadaati hai (ek antinode). Pattern kabhi rope ke saath slide nahi karta; woh bas unhi jagahon par fadfadaata rehta hai. Yahi ek standing wave hai — yeh khadi hai kyunki still-spots wahan ki wahan rehte hain.
Standing wave kya hai?
Do identical waves jo opposite directions mein move karti hain unhe superpose karne se bana wave pattern; uski shape space mein fixed hoti hai jabki amplitude time mein oscillate karti hai, koi net energy transport nahi hota.
Asin(kx−ωt)+Asin(kx+ωt) se standing wave equation?
y=2Asin(kx)cos(ωt).
Standing wave ki position-dependent amplitude?
R(x)=2Asin(kx).
Node ki condition?
sin(kx)=0⇒x=nλ/2 (displacement hamesha zero).
Antinode ki condition?
∣sin(kx)∣=1⇒x=(2n+1)λ/4 (amplitude 2A).
Adjacent nodes ke beech distance?
λ/2.
Node se nearest antinode tak ki distance?
λ/4.
Kya standing wave net energy transport karta hai?
Nahi — equal energy dono taraf flow karti hai, net zero; energy trapped rehti hai KE↔PE swap karti hui.
x aur t ke parts alag kyun hote hain?
Sum-to-product ek factor mein ωt cancel karta hai aur doosre mein kx, jo f(x)g(t) deta hai.
Node par mechanically kya khaas hai?
Maximum slope/strain aur maximum restoring force, jabki displacement zero hoti hai.