1.2.16 · Physics › Newton's Laws & Dynamics
Ek body jo circle mein move kar rahi hai woh hamesha accelerate kar rahi hoti hai, chahe speed constant ho, kyunki uski direction badalti rehti hai. Acceleration ke liye ek force chahiye (Newton ka 2nd law). Toh koi physical cheez hona chahiye jo body ko center ki taraf constantly kheench rahi ho. "Centripetal force" koi naya force NAHI hai — yeh uss real force ka naam hai (tension, gravity, friction, normal force, electric…) jo center ki taraf point karta hai aur required inward pull provide karta hai.
Intuition Velocity ki direction change hoti hai → acceleration exist karta hai
Velocity ek vector hai. Chahe speed ∣ v ∣ constant ho, v ki direction rotate hoti rehti hai. Ek changing vector ka matlab hai Δ v = 0 , toh a = Δ v /Δ t = 0 . Woh acceleration center ki taraf point karta hai (yahi straight-line path ko circle mein mod deta hai).
Worked example 1. String pe stone (horizontal/vertical circle)
String mein tension haath (center) ki taraf point karta hai.
T = r m v 2
Yeh step kyun? Tension akela horizontal force hai jo inward pull karta hai, isliye woh akela m v 2 / r ke barabar hota hai.
Worked example 2. Planet/satellite orbit mein
Gravity yeh provide karta hai: r 2 GM m = r m v 2 .
Yeh step kyun? Inward gravitational force ko required centripetal force ke barabar set karo. Solve karne par orbital speed v = GM / r milti hai.
Worked example 3. Flat road par car turning
Tyres aur road ke beech static friction inward point karta hai.
f s = r m v 2 ≤ μ s m g ⇒ v m a x = μ s g r
Yeh step kyun? Friction zyada se zyada μ s m g supply kar sakta hai; usse zyada ho jaane par car outward skid karne lagti hai (curve se bahar ho jaati hai).
Worked example 4. Banked road par car (no friction)
Normal force ka horizontal component yeh provide karta hai.
Vertical: N cos θ = m g . Horizontal: N sin θ = r m v 2 .
Divide karne par: tan θ = r g v 2
Yeh step kyun? Road ko tilt karne se normal force inward tilt ho jaata hai; uska horizontal slice centripetal kaam karta hai isliye friction ki zaroorat nahi.
Worked example 5. Conical pendulum
Bob ek string par angle θ par horizontal circle mein swing karta hai.
Horizontal: T sin θ = r m v 2 . Vertical: T cos θ = m g .
tan θ = r g v 2
Yeh step kyun? Tension split ho jaata hai: vertical part weight hold karta hai, horizontal part centripetal force hai.
Worked example 6. Atom mein electron / magnetic field mein charge
Coulomb force (r 2 k q 1 q 2 ) ya magnetic force (q v B ) inward pull hai.
Magnetic field mein charge ke liye: q v B = r m v 2 ⇒ r = q B m v .
Worked example 7. Vertical circle (loop ka top)
Top par, gravity aur tension/normal dono neeche = inward point karte hain:
T + m g = r m v 2
Top par minimum speed: T ≥ 0 ⇒ v m i n = g r .
Yeh step kyun? Agar v bahut chhota ho, toh required m v 2 / r , m g se kam hoga, string slack ho jaayega aur object circle se inward gir jaayega.
Common mistake "Centripetal force ek extra force hai jo main apne free-body diagram mein add karta hoon."
Kyun sahi lagta hai: Har doosre force ka ek naam aur ek arrow hota hai, toh lagta hai centripetal force ko bhi apna arrow milna chahiye.
Fix: m v 2 / r woh result hai jo tumhe chahiye , koi input force nahi . Sirf real forces draw karo (tension, gravity, normal, friction). Phir likho ∑ F inward = m v 2 / r . Alag "centripetal arrow" add karna double-counting hai.
Common mistake "Ek outward centrifugal force hai jo body ko bahar dhakelta hai."
Kyun sahi lagta hai: Turning car mein tumhe bahar ki taraf throw hone ka feel hota hai.
Fix: Woh feeling inertia hai — tumhara body seedha jaana chahta hai jabki car turn karti hai. Ground (inertial) frame mein koi real outward force nahi hoti. Centrifugal force sirf rotating frame mein ek pseudo-force ke roop mein appear hoti hai.
Common mistake "Zyada speed mein zyada friction chahiye, toh friction bina limit ke badhta rehta hai."
Kyun sahi lagta hai: f = m v 2 / r , v ke saath badhta hai.
Fix: Static friction ki ek ceiling μ s m g hoti hai. Jab m v 2 / r isse exceed kar le, friction keep up nahi kar sakta aur car skid kar jaati hai — isliye ek maximum safe speed hoti hai.
Recall Feynman: ek 12-saal ke bachche ko explain karo
Ek ball ko string se baandho aur apne sar ke upar ghuma lo. String ball ko inward teri haath ki taraf kheenchti rehti hai — woh inward kheench hi ball ko circle mein rakhti hai straight fly off hone ki jagah. Jis second tune chhoda, ball seedhi line mein shoot kar jaati hai, kyunki koi cheez usse inward nahi kheench rahi. "Centripetal force" sirf ek fancy naam hai jo bhi inward kheechna kar raha ho uske liye: ek string, gravity, car tyres ki grip, ya ek magnet. Yeh kabhi brand-new force nahi hota — yeh ek kaam hai jo koi real force kar raha hota hai.
"Centripetal = Center-Petal: ek real force center ki taraf petal ki tarah point karta hai."
Aur providers yaad karne ke liye: "G-T-N-F-E" → G ravity (orbits), T ension (string), N ormal (banking), F riction (flat turn), E lectro/magnetic (charges).
Centripetal force physically kya hai? Koi naya force nahi — jo bhi real force (ya net inward component) center ki taraf point kare aur m v 2 / r supply kare, uska naam hai.
Centripetal acceleration ka magnitude derive karo. ∣Δ v ∣ = v Δ θ , toh a = v Δ θ /Δ t = v ω = v 2 / r = ω 2 r , center ki taraf directed.
Satellite ke liye centripetal force kya provide karta hai? Gravity: GM m / r 2 = m v 2 / r .
Flat curve par car ke liye kya provide karta hai, aur speed ko kya limit karta hai? Static friction;
v ma x = μ s g r .
Banking angle formula (frictionless) aur kaunsa force F c provide karta hai? tan θ = v 2 / ( r g ) ; normal force ka horizontal component.
Vertical loop ke top par force equation aur minimum speed likho. T + m g = m v 2 / r ;
v min = g r jab
T = 0 .
Turning car mein bahar ki taraf throw hone ka feel kyun hota hai? Inertia (body seedha-line motion chahta hai); outward "centrifugal" force ek pseudo-force hai, ground frame mein real nahi.
Magnetic field mein charge ke liye circular path ki radius? q v B = m v 2 / r ⇒ r = m v / ( q B ) .
velocity direction changes
GMm/r squared = m v squared / r
a = v squared / r = omega squared r
Required net inward force Fc = m v squared / r
Name for any real inward force