1.1.10 · Physics › Measurement, Vectors & Kinematics
Ek vector ke do kaam hote hain: batao kitna (magnitude) aur kis direction mein (direction). Ek unit vector in dono kamon ko alag kar deta hai. Yeh exactly 1 length ka vector hota hai jiska sirf ek kaam hai — point karna . Jab ek baar tumhare paas ek pure "pointer" aa gaya, tum koi bhi vector bana sakte ho us pointer ko sahi amount se stretch karke.
Socho isko ek compass needle ki tarah: needle hamesha same length ki hoti hai, woh sirf direction batati hai. "Distance" jo tum travel karte ho, woh alag se multiply hota hai.
Ek unit vector woh vector hota hai jiska magnitude == 1 == ho. Hum isko "hat" se mark karte hain: a ^ .
∣ a ^ ∣ = 1
x , y , z axes ke saath teen special unit vectors hote hain jinhe standard basis vectors kehte hain:
i ^ + x direction mein point karta hai
j ^ + y direction mein point karta hai
k ^ + z direction mein point karta hai
Yeh aapas mein perpendicular (orthogonal) hain aur har ek ki length 1 hai — milke inhe orthonormal set kehte hain (ortho = perpendicular, normal = unit length).
YEH KYUN chahiye? Kyunki yeh humein kisi bhi vector ko numbers ke simple collection ki tarah likhne dete hain:
A = A x i ^ + A y j ^ + A z k ^
Yahan A x , A y , A z components hain — vector har axis ke saath kitna reach karta hai. Hats direction carry karte hain; numbers amount carry karte hain.
Intuition Pythagoras kyun aata hai
i ^ , j ^ , k ^ perpendicular hain. Toh components A x i ^ , A y j ^ , A z k ^ ek rectangular box ke edges banate hain. Vector A box ka diagonal hai. Box diagonal ki length sirf Pythagoras do baar apply karne se milti hai.
Derivation (pehle 2D mein): x y -plane mein A x aur A y ek right triangle ki do perpendicular sides hain jiska hypotenuse A hai. Toh
∣ A ∣ 2 = A x 2 + A y 2 .
3D mein extend karo: Base plane mein diagonal ko r = A x 2 + A y 2 ek side maano, aur A z (poore base ke perpendicular) ko doosri side. Phir Pythagoras:
∣ A ∣ 2 = r 2 + A z 2 = A x 2 + A y 2 + A z 2 .
Intuition Trick sirf division hai
Agar ek vector ki length 5 hai aur mujhe length 1 chahiye, toh main usse 5 se divide kar deta hoon. Kisi vector ko uske apne magnitude se divide karne par direction wahi rehti hai lekin length exactly 1 ho jaati hai .
Derivation: Maano A ka magnitude ∣ A ∣ hai. Define karo
A ^ = ∣ A ∣ A .
Iska magnitude hai
∣ A ^ ∣ = ∣ A ∣ ∣ A ∣ = 1. ✓
Ek vector ko positive scalar 1/∣ A ∣ se multiply karne par woh rotate nahi hota , toh direction preserved rehti hai. Ho gaya.
Worked example Example 1 — 2D unit vector
A = 3 i ^ + 4 j ^ ka unit vector nikalo.
Step 1: ∣ A ∣ = 3 2 + 4 2 = 9 + 16 = 25 = 5 .
Yeh step kyun? Divide karne se pehle humein length chahiye.
Step 2: A ^ = 5 3 i ^ + 4 j ^ = 0.6 i ^ + 0.8 j ^ .
Yeh step kyun? Har component ko magnitude se divide karo — isse length rescale hokar 1 ho jaati hai.
Check: 0. 6 2 + 0. 8 2 = 0.36 + 0.64 = 1 = 1. ✓
Worked example Example 2 — 3D unit vector
B = 1 i ^ − 2 j ^ + 2 k ^ ke liye B ^ nikalo.
Step 1: ∣ B ∣ = 1 2 + ( − 2 ) 2 + 2 2 = 1 + 4 + 4 = 9 = 3 .
Kyun? Magnitude mein squares use hote hain, toh minus sign hat jaata hai — direction ki info component ke sign mein hoti hai, magnitude mein nahi.
Step 2: B ^ = 3 1 i ^ − 3 2 j ^ + 3 2 k ^ .
Kyun? Same recipe: length se divide karo.
Worked example Example 3 — direction + magnitude se vector rebuild karna
Magnitude 10 N ki ek force d = 3 i ^ + 4 j ^ ki direction mein act karti hai. Force vector nikalo.
Step 1: Direction unit vector: d ^ = 5 3 i ^ + 4 j ^ = 0.6 i ^ + 0.8 j ^ .
Kyun? Hum sirf d ki direction chahte hain, toh uski length strip karo.
Step 2: F = ( 10 N ) d ^ = 6 i ^ + 8 j ^ N .
Kyun? Vector = magnitude × direction. 10 N size provide karta hai.
Check: ∣ F ∣ = 6 2 + 8 2 = 10 N . ✓
Common mistake "Isko chota karne ke liye kisi bhi number se divide karo."
Kyun sahi lagta hai: Tumhe sahi yaad hai ki unit vectors "chhote" hote hain. Toh shrinking hi goal lagta hai.
Fix: Tumhe vector ke apne magnitude se divide karna hoga, kisi arbitrary number se nahi. Sirf A /∣ A ∣ hi length exactly 1 guarantee karta hai.
∣ A ∣ = A x + A y + A z (bas components jod do)."
Kyun sahi lagta hai: Jodna natural lagta hai, aur ek hi line mein vectors ke liye yeh kaam bhi karta hai.
Fix: Components perpendicular hain, toh inhe Pythagoras se combine karo, plain addition se nahi: A x 2 + A y 2 + A z 2 . 3 i ^ + 4 j ^ ke liye galat tarika 7 deta hai; sahi tarika 5 deta hai.
Common mistake "Unit vector ke koi units nahi hote."
Kyun sahi lagta hai: "Unit" dimensionless lagta hai.
Fix: Unit vector dimensionless hota hai (pure direction). "Unit" word ka matlab hai magnitude 1 , na ki "koi unit hona". Physical units us magnitude ke saath rehti hain jisse tum multiply karte ho.
Common mistake Sign direction carry karta hai, yeh bhool jaana.
Kyun sahi lagta hai: Magnitudes positive hote hain, toh students signs drop kar dete hain.
Fix: B ^ = 3 1 i ^ − 3 2 j ^ + 3 2 k ^ mein minus zaroori hai — yeh kehta hai "− y mein point karo". Component signs rakho; sirf magnitude forced positive hota hai.
Recall Feynman: 12-saal ke bache ko samjhao
Socho ek aisa arrow jo hamesha exactly 1 cm lamba hota hai. Yeh ek chhota sa "pointing stick" hai — yeh kitna door nahi bata sakta, sirf kis taraf bata sakta hai. Yahi unit vector hai. Ab agar tumhe ek aisa real arrow chahiye jo 5 cm lamba ho aur usi taraf point kare, toh simply 1 cm wale pointer ko 5 baar stretch karo. Kisi bade arrow se pointer banane ke liye, arrow ki length mapo aur poore arrow ko usi length se chhhota karo — ab yeh exactly 1 lamba hai lekin abhi bhi same direction mein aim kar raha hai!
Mnemonic Recipe yaad karo
"Hat = vector uski length se divided." A ^ = A /∣ A ∣ .
Aur axes ke liye: "i daayein jaata hai, j upar jaata hai, k tumhari taraf aata hai" (x right, y up, z page se bahar).
Unit vector ki defining property kya hai? Iska magnitude exactly 1 hota hai (yeh sirf direction carry karta hai).
A se unit vector kaise construct karte hain?A ^ = A /∣ A ∣ — vector ko uske apne magnitude se divide karo.
A = A x i ^ + A y j ^ + A z k ^ ka magnitude likho.Magnitude ke liye Pythagoras kyun use karte hain (addition nahi)? Kyunki i ^ , j ^ , k ^ aapas mein perpendicular hain, toh components right-angled box ki sides hain.
i ^ , j ^ , k ^ ke liye "orthonormal" ka kya matlab hai?Aapas mein perpendicular (ortho) AUR har ek unit length ka (normal).
3 i ^ + 4 j ^ ka unit vector?0.6 i ^ + 0.8 j ^ (kyunki magnitude 5 hai).
Magnitude aur direction se vector kaise rebuild karte hain? A = ∣ A ∣ A ^ (magnitude × unit vector).
Kya unit vector ke physical units hote hain? Nahi — yeh dimensionless hota hai; units us magnitude mein rehti hain jisse tum multiply karte ho.
3 i ^ + 4 j ^ ke saath 10 N force: F kya hai?F = 10 ( 0.6 i ^ + 0.8 j ^ ) = 6 i ^ + 8 j ^ N.
magnitude times direction
Magnitude sqrt sum of squares
A hat equals A over mag A
Rebuild A equals mag times A hat