4.1.17 · Maths › Calculus I — Limits & Derivatives
Intuition Badi picture (KYUN)
Sine wave sabse tezi se rise karta hai jab wo zero cross karta hai, aur apni peaks par flat ho jaata hai. Yeh "rate of climb" khud ek wave hai — aur yeh nikalta hai cosine wave (jo exactly wahan peak karta hai jahan sine upar jaate hue zero cross karta hai). Toh differentiation bas wave ko 90° shift kar deta hai. Hum ise derivative ki raw definition se prove karne waale hain, memorize nahi karna.
Definition Derivative (first principles)
Kisi function f ke liye, derivative average slope ka limit hai jab interval shrink hota hai:
f ′ ( x ) = lim h → 0 h f ( x + h ) − f ( x )
Hum yeh dikhana chahte hain:
d x d sin x === cos x == , d x d cos x === − sin x ==
(angles radians mein — yeh zaroori hai).
Sab kuch do limits par depend karta hai. Inke bina proof collapse ho jaata hai.
Worked example Poori derivation — har step justified
d x d sin x = lim h → 0 h s i n ( x + h ) − s i n x
Step 1 — addition formula se expand karo. Kyun? Hume "x " wale part ko "h jo 0 ki taraf shrink ho raha hai" waale part se alag karna hai, aur sin ( x + h ) = sin x cos h + cos x sin h exactly yahi karta hai.
= lim h → 0 h s i n x c o s h + c o s x s i n h − s i n x
Step 2 — sin x terms ko group karo. Kyun? Do jaane-maane limits build karne ke liye.
= lim h → 0 [ sin x ⋅ h c o s h − 1 + cos x ⋅ h s i n h ]
Step 3 — sin x , cos x constants hain h ke w.r.t. , toh inhe bahar nikalo:
= sin x = 0 h → 0 lim h cos h − 1 + cos x = 1 h → 0 lim h sin h
Step 4 — do ingredients substitute karo:
= sin x ⋅ 0 + cos x ⋅ 1 = cos x ✓
Worked example Poori derivation — upar wale ka mirror
d x d cos x = lim h → 0 h c o s ( x + h ) − c o s x
Step 1 — addition formula cos ( x + h ) = cos x cos h − sin x sin h . Kyun? Same reason: x ko h se alag karo.
= lim h → 0 h c o s x c o s h − s i n x s i n h − c o s x
Step 2 — cos x terms ko group karo:
= lim h → 0 [ cos x ⋅ h c o s h − 1 − sin x ⋅ h s i n h ]
Step 3 — constants bahar nikalo aur limits substitute karo (0 aur 1 ):
= cos x ⋅ 0 − sin x ⋅ 1 = − sin x ✓
Intuition Sign ka sanity check
x = 0 ke paas, cos x apni peak par hai aur decrease hona shuru karta hai → slope negative. Aur sach mein − sin x chhote x > 0 ke liye negative hai. Minus sign physically forced hai. ✔
Recall Dekhne se pehle predict karo
Q: Bina re-derive kiye, first principles structure se d x d sin ( 2 x ) kya hai? (Hint: sin ( 2 x + 2 h ) ...)
A: Wohi proof h → 2 h ke saath effectively inner rate se scale karta hai: aapko 2 cos ( 2 x ) milega. Factor 2 h s i n 2 h → 2 se aata hai. Yeh chain rule ka preview hai.
Common mistake "Degrees mein kaam karna theek hai."
Kyun sahi lagta hai: Degrees angles ki roz ki unit hain, toh kyun nahi?
Fix: Limit 1, h s i n h → 1 , sirf radians mein sach hai (sector area 2 1 h radian measure use karta hai). Degrees mein h s i n h ° → 180 π , toh aapko d x d sin x = 180 π cos x milega. Poore calculus mein radians use hote hain.
lim h c o s h − 1 = 2 1 kyunki cos, 1 − 2 h 2 jaisa curve karta hai."
Kyun sahi lagta hai: cos h ≈ 1 − 2 h 2 , toh h c o s h − 1 ≈ − 2 h .
Fix: Woh − 2 h → 0 hai! 2 1 , h 2 1 − c o s h → 2 1 ka hai, jo ek alag limit hai. Denominator mein h ki power dhyan se dekho.
h s i n h par L'Hôpital use kar sakta hoon."
Kyun sahi lagta hai: Yeh 0 0 hai, L'Hôpital iske liye hi bana hai.
Fix: L'Hôpital ko d h d sin h = cos h chahiye — jo exactly wahi cheez hai jo hum prove karne ki koshish kar rahe hain. Circular reasoning. Squeeze argument hi legitimate foundation hai.
First-principles definition of f ′ ( x ) ? h → 0 lim h f ( x + h ) − f ( x )
lim h → 0 h s i n h ki value (radians)?1
lim h → 0 h c o s h − 1 ki value?0
Kaun sa theorem h s i n h → 1 prove karta hai? Squeeze (Sandwich) Theorem, unit-circle areas ke through
Squeeze mein teen areas kaun se compare hote hain? 2 1 sin h ≤ 2 1 h ≤ 2 1 tan h
sin ke liye use hua addition formula?sin ( x + h ) = sin x cos h + cos x sin h
cos ke liye use hua addition formula?cos ( x + h ) = cos x cos h − sin x sin h
d x d sin x ?cos x
d x d cos x ?− sin x
Angles radians mein kyun hone chahiye? Kyunki h s i n h → 1 sirf radians mein hold karta hai (sector area = 2 1 h )
h c o s h − 1 evaluate karne ki trick?Conjugate c o s h + 1 c o s h + 1 se multiply karo
Yahan L'Hôpital kyun use nahi kar sakte? Yeh d x d sin x = cos x assume karta hai — circular hai
Recall Feynman: 12-saal ke bacche ko samjhao
Socho kisi swing ko dhakka de rahe ho. Jab swing bilkul neeche hoti hai toh sabse tezi se move karti hai; upar jaake ek pal ke liye ruk jaati hai. Swing ki height sin x jaisi hai, aur yeh kitni tezi se move kar rahi hai woh cos x jaisa hai. Gaur karo: jab height beech mein (zero) hoti hai, speed sabse zyada hoti hai — aur jab height top par hoti hai, speed zero hoti hai. Differentiation bas yeh pooch raha hai "abhi yeh kitni tezi se badal rahi hai?" Sine ke liye, woh jawaab hamesha cosine hota hai. Isse prove karne ke liye hum super close zoom karte hain (yahi limit hai), ek circle use karke dikhate hain ki ek chhota angle aur uska sine almost equal hote hain, aur algebra apni jagah fit ho jaati hai.
Mnemonic Signs yaad rakhne ka tarika
"Sine se Cosine free mein milta hai; Cosine se Sine ke liye fee (minus) lagti hai."
Ya cycle: sin → cos → − sin → − cos → sin — derivatives har baar wave ko 90° rotate kar dete hain.
Agar sirf ek cheez yaad rakhni ho: poora result h s i n h → 1 + addition formulas par depend karta hai. Inhe master karo aur tum dono derivatives 60 seconds mein rebuild kar sakte ho.
Squeeze Theorem — h s i n h → 1 ke peeche ka engine
Trigonometric addition formulas — algebraic splitter
Limits — definition and properties
Chain Rule — sin ( g ( x )) tak extend karta hai
Derivatives of tan, sec, csc, cot — inhi do se quotient rule ke through bante hain
Taylor series of sin and cos — usi fact ka alternative viewpoint
Radian measure — kyun constant clean aata hai
First principles derivative limit
Limit sin h over h equals 1
Limit cos h minus 1 over h equals 0
Squeeze Theorem on unit circle areas
Conjugate trick times cos h plus 1