3.1.15Advanced Trigonometry

Product-to-sum formulas

1,387 words6 min readdifficulty · medium4 backlinks

WHAT are we trying to do?


HOW to DERIVE them (from scratch — never memorise blind)

Start from the angle addition formulas, which are our only assumed tools:

\cos(A+B)=\cos A\cos B-\sin A\sin B \tag{1} \cos(A-B)=\cos A\cos B+\sin A\sin B \tag{2} \sin(A+B)=\sin A\cos B+\cos A\sin B \tag{3} \sin(A-B)=\sin A\cos B-\cos A\sin B \tag{4}

Deriving cosAcosB\cos A\cos B:

  • Why? The cosAcosB\cos A\cos B term appears in both (1) and (2) with a ++ sign, while sinAsinB\sin A\sin B appears with opposite signs. So add them to cancel the sine part. (1)+(2):cos(A+B)+cos(AB)=2cosAcosB(1)+(2):\quad \cos(A+B)+\cos(A-B)=2\cos A\cos B
  • Why divide by 2? To isolate the product cleanly. cosAcosB=12[cos(AB)+cos(A+B)]\boxed{\cos A\cos B=\tfrac12[\cos(A-B)+\cos(A+B)]}

Deriving sinAsinB\sin A\sin B:

  • Why subtract? To keep sinAsinB\sin A\sin B and cancel cosAcosB\cos A\cos B, use (2)(1)(2)-(1): cos(AB)cos(A+B)=2sinAsinB\cos(A-B)-\cos(A+B)=2\sin A\sin B sinAsinB=12[cos(AB)cos(A+B)]\boxed{\sin A\sin B=\tfrac12[\cos(A-B)-\cos(A+B)]}

Deriving sinAcosB\sin A\cos B:

  • Why add (3) and (4)? Both have sinAcosB\sin A\cos B with ++; the cosAsinB\cos A\sin B parts cancel. (3)+(4):sin(A+B)+sin(AB)=2sinAcosB(3)+(4):\quad \sin(A+B)+\sin(A-B)=2\sin A\cos B sinAcosB=12[sin(A+B)+sin(AB)]\boxed{\sin A\cos B=\tfrac12[\sin(A+B)+\sin(A-B)]}

Deriving cosAsinB\cos A\sin B:

  • Why subtract? (3)(4)(3)-(4) keeps cosAsinB\cos A\sin B, cancels sinAcosB\sin A\cos B: cosAsinB=12[sin(A+B)sin(AB)]\cos A\sin B=\tfrac12[\sin(A+B)-\sin(A-B)]
Figure — Product-to-sum formulas

Worked examples


Common mistakes (Steel-manned)


Recall Feynman: explain to a 12-year-old

Imagine two friends singing steady notes at the same time. If you listen carefully, their combined sound wobbles — sometimes loud, sometimes soft. Multiplying two "wiggly" wave numbers is exactly this mixing. The product-to-sum trick says: that wobble is really just two plain notes added together — one high and one low. So instead of dealing with a confusing multiplication, we get two simple songs we can handle one at a time.


Flashcards

What does cosAcosB\cos A\cos B expand to?
12[cos(AB)+cos(A+B)]\tfrac12[\cos(A-B)+\cos(A+B)]
What does sinAsinB\sin A\sin B expand to?
12[cos(AB)cos(A+B)]\tfrac12[\cos(A-B)-\cos(A+B)]
What does sinAcosB\sin A\cos B expand to?
12[sin(A+B)+sin(AB)]\tfrac12[\sin(A+B)+\sin(A-B)]
Which two addition formulas do you ADD to derive cosAcosB\cos A\cos B?
cos(A+B)\cos(A+B) and cos(AB)\cos(A-B) — the sinAsinB\sin A\sin B terms cancel.
Why does a 12\tfrac12 appear in all product-to-sum formulas?
Because adding/subtracting two addition formulas gives 2×2\times the product, so you divide by 2.
cos·cos and sin·sin produce sums of which function?
Cosines.
sin·cos produces sums of which function?
Sines.
Compute 2sin5xcos3x2\sin5x\cos3x as a sum.
sin8x+sin2x\sin8x+\sin2x.
Evaluate sin75sin15\sin75^\circ\sin15^\circ.
14\tfrac14.
Why are these formulas useful in integration?
Products can't be integrated term-by-term, but the equivalent sum of sines/cosines can.

Connections

Concept Map

add cos eqns

subtract cos eqns

add sin eqns

subtract sin eqns

turns product into sum

explains

foundation for

Angle addition formulas

cos A cos B

sin A sin B

sin A cos B

cos A sin B

Product-to-sum identities

Integration of products

Wave interference / beats

Fourier analysis

Hinglish (regional understanding)

Intuition Hinglish mein samjho

Dekho, jab hum do trig functions ko multiply karte hain (jaise sinAcosB\sin A\cos B), toh woh dekhne me complicated lagta hai, aur especially integrate karna mushkil ho jaata hai. Product-to-sum formulas ek translator ki tarah kaam karte hain — yeh us product ko do simple cosines ya sines ke sum me todd dete hain, jinke saath kaam karna aasaan hai.

Yeh formulas kahin se aasman se nahi aate — hum inhe angle addition formulas se derive karte hain. Trick simple hai: cos(A+B)\cos(A+B) aur cos(AB)\cos(A-B) ko add karo toh sinAsinB\sin A\sin B waale terms cancel ho jaate hain aur bachta hai 2cosAcosB2\cos A\cos B. Do se divide karo — bas formula ready! Isi liye har formula me ek 12\tfrac12 aata hai; yeh division ki nishaani hai. Sabse common galti yahi hai ki students yeh 12\tfrac12 bhool jaate hain, ya cos·cos me galat sign lagaate hain (yaad rakho: cos·cos me plus, sin·sin me minus).

Yeh cheez kyun important hai? Kyunki calculus me cos4xcosxdx\int \cos4x\cos x\,dx jaise integrals directly nahi hote — par product ko sum banao (12[cos3x+cos5x]\tfrac12[\cos3x+\cos5x]) toh term-by-term easily ho jaata hai. Physics me bhi, do tuning forks ka beats phenomenon inhi formulas se samajh aata hai. Ek line yaad rakho: "Cousins Add Cosines, Sisters Subtract, Mixed make Sines" — aur aadha (half) sabme lagana mat bhoolna!

Go deeper — visual, from zero

Test yourself — Advanced Trigonometry

Connections