Ek n-channel MOSFET lo (source & drain n+ regions hain p-type body mein).
Field kaise kaam karta hai:
Gate, p-type body ke upar oxide par baith ta hai.
Ek positiveVGS apply karo. Gate positively charged ho jaata hai.
Yeh field holes ko (p-body mein majority carriers) surface se repel karta hai aur electrons ko surface ki taraf attract karta hai.
Jab kaafi electrons ikatte hote hain, ek patli n-type inversion layer source ko drain se connect karti hai — ek conducting channel banta hai.
Asli fark:
Enhancement n-MOS
Depletion n-MOS
VGS=0 par channel
koi nahi
pre-doped, exist karta hai
Vth ka sign (n-type)
positive
negative
ON karne ke liye
VGS>Vth
already ON hai
OFF karne ke liye
VGS≤Vth
VGS<Vth (negative)
Default state
OFF
ON
P-channel versions ke liye, har sign ulta kar do: enhancement p-MOS ka Vth<0 hota hai (negative gate se ON hota hai), depletion p-MOS ka Vth>0 hota hai.
Dono modes saturation mein same drain current equation follow karte hain; sirf Vth shift hota hai.
Squared kyun?(VGS−Vth) ka ek factor kitne carriers hain (charge) se aata hai, doosra kitni tezi se push ho rahe hain (field) se. Dono effects linearly scale karte hain → product quadratic hota hai.
Is curve par modes ko distinguish karne wali sirf ek cheez yeh hai ki Vth kahan land karta hai:
E-mode n-MOS: curve ek positiveVth par start hoti hai.
D-mode n-MOS: curve left shift hoti hai, VGS=0 par nonzero ID cross karti hai (iska Vth negative hai).
Kya ek enhancement MOSFET normally ON hota hai ya OFF?
Depletion n-MOS ke liye Vth ka sign kya hota hai?
ID ek square law kyun hai, linear kyun nahi?
Depletion n-MOS ko OFF kaise karte hain?
Enhancement MOSFET ka default state (bina gate voltage ke)
OFF — koi channel exist nahi karta jab tak VGS, Vth se exceed na kare.
Depletion MOSFET ka default state (bina gate voltage ke)
ON — ek pre-doped channel VGS=0 par conduct karta hai.
Depletion-mode n-channel MOSFET ke liye Vth ka sign
Negative.
Enhancement-mode n-channel MOSFET ke liye Vth ka sign
Positive.
"Enhancement" physically kya matlab hai?
Aap gate se carriers add/attract karte ho ek channel build karne ke liye.
"Depletion" physically kya matlab hai?
Aap gate se carriers remove/repel karte ho existing channel ko khaali karne ke liye.
Saturation drain-current equation
ID=21k(VGS−Vth)2 for VGS>Vth, warna 0.
Drain current overdrive mein quadratic kyun hota hai?
Ek factor channel charge se (carriers ki sankhya), ek field-driven velocity se — dono (VGS−Vth) mein linear hain.
Kya mode (E/D) aur channel type (n/p) related hain?
Nahi — independent hain; chaaron combinations exist karte hain.
Depletion device ka IDSS matlab hai
VGS=0 par drain current (iska "on" current gate ground hone par).
Recall Feynman: ek 12-saal ke bachche ko samjhao
Socho ek paani ki pipe mein ek squeeze-clamp hai. Enhancement MOSFET mein pipe default se squeeze karke band hai — aapko gate button dabana padta hai isko kholne ke liye aur paani bahane ke liye. Depletion MOSFET mein pipe default se khuli hai — paani pehle se beh raha hai, aur aap gate button dabate ho isko band karne ke liye. Same pipe, same paani ka rule; bas fark yeh hai ki yeh khuli shuru hoti hai ya band.