3.5.2Inorganic Qualitative Analysis

Common anions — Cl⁻, Br⁻, I⁻, SO₄²⁻, NO₃⁻, CO₃²⁻ — confirmatory tests

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1. The halides: Cl⁻, Br⁻, I⁻

HOW it works (derivation of the logic): Ag⁺ is a soft-ish cation that binds halides strongly. As we go Cl⁻ → Br⁻ → I⁻ the anion gets larger and more polarisable (softer), so the bond grows more covalent, the salt less soluble, and less soluble in NH₃ (since NH₃ can only redissolve the more ionic, higher-Ksp salts).

Anion AgX precipitate color Solubility in dil. NH₃ Ksp (≈)
Cl⁻ white fully soluble 1.8×10101.8\times10^{-10}
Br⁻ pale yellow (cream) partially soluble 5.4×10135.4\times10^{-13}
I⁻ yellow insoluble 8.5×10178.5\times10^{-17}

Ag++XAgX\text{Ag}^+ + \text{X}^- \rightarrow \text{AgX}\downarrow AgCl+2NH3[Ag(NH3)2]++Cl\text{AgCl} + 2\text{NH}_3 \rightarrow [\text{Ag(NH}_3)_2]^+ + \text{Cl}^-

1b. Confirming Br⁻ and I⁻ by oxidation (the "layer test")

Halide ease of oxidation: I>Br>Cl\text{I}^- > \text{Br}^- > \text{Cl}^- (larger ion → loses electron more easily). Add chlorine water (or Cl₂/conc. H₂SO₄ + MnO₂), then shake with CCl₄/CHCl₃:

Cl2+2Br2Cl+Br2(orange organic layer)\text{Cl}_2 + 2\text{Br}^- \rightarrow 2\text{Cl}^- + \text{Br}_2 \quad (\text{orange organic layer}) Cl2+2I2Cl+I2(violet/purple organic layer)\text{Cl}_2 + 2\text{I}^- \rightarrow 2\text{Cl}^- + \text{I}_2 \quad (\text{violet/purple organic layer})

  • Cl₂ cannot oxidise Cl⁻ → no test, distinguishes it.
  • I⁻ also turns starch blue-black (classic confirmation).

2. Sulphate, SO₄²⁻

Ba2++SO42BaSO4 (white)\text{Ba}^{2+} + \text{SO}_4^{2-} \rightarrow \text{BaSO}_4\downarrow \ (\text{white})


3. Nitrate, NO₃⁻

HOW (the chemistry): conc. H₂SO₄ generates the oxidising conditions; nitrate is reduced to NO, which complexes with Fe²⁺:

3Fe2++4H++NO33Fe3++NO+2H2O3\text{Fe}^{2+} + 4\text{H}^+ + \text{NO}_3^- \rightarrow 3\text{Fe}^{3+} + \text{NO} + 2\text{H}_2\text{O} NO+[Fe(H2O)6]2+[Fe(H2O)5NO]2++H2O\text{NO} + [\text{Fe(H}_2\text{O)}_6]^{2+} \rightarrow [\text{Fe(H}_2\text{O)}_5\text{NO}]^{2+} + \text{H}_2\text{O}

The complex [Fe(H2O)5NO]2+[\text{Fe(H}_2\text{O)}_5\text{NO}]^{2+} is brown. Why a ring? The acid is dense and sinks; reaction happens only at the boundary layer where concentrations meet → brown forms there.


4. Carbonate, CO₃²⁻

CO32+2H+H2O+CO2\text{CO}_3^{2-} + 2\text{H}^+ \rightarrow \text{H}_2\text{O} + \text{CO}_2\uparrow CO2+Ca(OH)2CaCO3+H2(milky)\text{CO}_2 + \text{Ca(OH)}_2 \rightarrow \text{CaCO}_3\downarrow + \text{H}_2\text{O} \ (\text{milky})

Figure — Common anions — Cl⁻, Br⁻, I⁻, SO₄²⁻, NO₃⁻, CO₃²⁻ — confirmatory tests

Common Mistakes (Steel-man + fix)


Recall Feynman: explain to a 12-year-old

Imagine each invisible ion is a suspect in a lineup. We can't see them, so we make them "react and show a clue." Add silver and chloride goes pale white, bromide turns cream, iodide goes yellow — like three suspects wearing different shirts. Then we ask them to dissolve in ammonia: only chloride says yes. For sulphate we add barium and it makes a white powder that won't dissolve in acid — the impostors run away in acid, the real one stays. Nitrate makes a magic brown ring with iron. Carbonate fizzes like soda and turns lime water cloudy. Each clue = one suspect caught.


Active-Recall Flashcards

#flashcards/chemistry

Color of AgCl, AgBr, AgI respectively
White, pale yellow (cream), yellow
Why use dil. HNO₃ (not HCl) before AgNO₃ for halides
HCl adds Cl⁻ → false AgCl ppt; HNO₃ destroys CO₃²⁻/SO₃²⁻ without adding halide
Which silver halide is soluble in dilute ammonia and why
AgCl; largest Ksp so NH₃ can pull Ag⁺ into [Ag(NH₃)₂]⁺ complex
Organic-layer color: Br₂ vs I₂ after Cl₂ water
Br₂ = orange/brown, I₂ = violet/purple
Why can't Cl₂ water confirm Cl⁻
Cl₂ cannot oxidise Cl⁻ (Cl⁻ already lowest in oxidising ease)
Confirmatory test for SO₄²⁻
Acidify with dil. HCl, add BaCl₂ → white BaSO₄ insoluble in acid
Why acidify before BaCl₂ test
Removes BaCO₃/BaSO₃ impostors that are white but acid-soluble
Brown-ring test reagents
Fresh FeSO₄ + conc. H₂SO₄ (added down the side)
Formula of the brown-ring complex
[Fe(H₂O)₅NO]²⁺
Equation for carbonate + acid
CO₃²⁻ + 2H⁺ → H₂O + CO₂↑
What gas turns lime water milky, and milkiness disappears why
CO₂; excess forms soluble Ca(HCO₃)₂
Order of ease of oxidation of halides
I⁻ > Br⁻ > Cl⁻

Connections

  • Group Analysis of Cations — same precipitation logic, opposite ion
  • Solubility Product (Ksp) — quantitative basis for AgX selectivity
  • Redox Series and Standard Potentials — why I⁻ oxidises easiest
  • Coordination Complexes — [Ag(NH₃)₂]⁺ and [Fe(H₂O)₅NO]²⁺
  • Acid–Base Reactions of Salts — carbonate effervescence
  • Polarisation and Fajans' Rules — covalent character down Cl→I explains color/insolubility

Concept Map

3 handles

3 handles

3 handles

AgNO3 test

white

cream

yellow

NH3 solubility

Cl fully sol, I insoluble

Cl2 water + CCl4 layer

orange

violet + starch blue

BaCl2 after HCl

confirms

dil HCl gives gas

Unknown anion

Solubility

Redox behaviour

Acid decomposition

Silver halide ppt

Cl- confirmed

Br- suspected

I- suspected

Lower Ksp = softer ion

Organic layer color

White BaSO4 insoluble in acid

SO4 2- confirmed

CO3 2- confirmed

Hinglish (regional understanding)

Intuition Hinglish mein samjho

Dekho, qualitative analysis ka funda simple hai: hum ion ko dekh nahi sakte, isliye usse aisi reaction karwate hain jisse koi clue mile — rang, precipitate, ya gas. Halides ke liye pehle dilute HNO₃ daalo (carbonate-sulphite ko hatane ke liye), phir AgNO₃. Chloride → white, Bromide → cream, Iodide → yellow. Aur ammonia mein test: chloride poora ghul jaata hai, iodide bilkul nahi — kyunki Cl⁻ se I⁻ tak ion bada aur polarisable hota jaata hai, bond covalent hoti jaati hai, Ksp chhota hota jaata hai.

Bromide aur Iodide confirm karne ke liye Cl₂ water + CCl₄ shake karo: Br₂ se layer orange, I₂ se violet. Yaad rakho — oxidation ki ease I⁻ > Br⁻ > Cl⁻, isliye Cl₂ inko nikaal deta hai par khud Cl⁻ ko nahi.

Sulphate ke liye HCl se acidify karke BaCl₂ daalo — white BaSO₄ jo acid mein nahi ghulta (yahi asli pehchaan, kyunki BaCO₃/BaSO₃ ghul jaate). Nitrate ka famous brown ring test: FeSO₄ daalo, phir conc. H₂SO₄ deewar se dheere se, brown ring banta hai jo [Fe(H₂O)₅NO]²⁺ complex hai. Carbonate sabse easy — dil. HCl daalo, fizz nikle, CO₂ lime water ko milky kar de.

Sabse important exam-trap: halide test mein HCl mat use karo, warna khud chloride aa jaayega aur galat white ppt milega. Aur BaCl₂ test se pehle acidify zaroor karo. Yeh do galtiyan har student karta hai — inhe pakka kar lo.

Go deeper — visual, from zero

Test yourself — Inorganic Qualitative Analysis

Connections