3.4.15 · D4Coordination Chemistry

Exercises — Applications — biological (haemoglobin, chlorophyll, vit B₁₂), medicinal (cisplatin), industrial (catalysts)

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Before we start, one picture we will reuse. A macrocycle is a big ring ligand that grabs a metal from four sides at once, leaving the top and bottom (the axial sites) free. Look at it once:

Figure — Applications — biological (haemoglobin, chlorophyll, vit B₁₂), medicinal (cisplatin), industrial (catalysts)
  • The four cyan bonds in the flat plane = the equatorial nitrogen donors (from porphyrin/corrin).
  • The two amber arrows sticking up and down = the axial sites, where the interesting chemistry happens (O₂, histidine, –CN, etc.).

Level 1 — Recognition

(Can you name the piece?)

Q1.1 Name the metal, its oxidation state, and the ring type in haemoglobin, chlorophyll, and vitamin B₁₂.

Recall Solution
System Metal Oxidation state Ring
Haemoglobin Fe (Fe(II)) porphyrin
Chlorophyll Mg (Mg(II)) porphyrin
Vitamin B₁₂ Co (Co(III)) corrin

Why these facts matter: Fe(II) is the only state that binds O₂ reversibly; Mg(II) is redox-inert (holds the ring rigid); Co(III) sits in the smaller corrin ring and forms a rare metal–carbon bond. See Oxidation states of transition metals.

Q1.2 Write the formula and the geometry of cisplatin.

Recall Solution

Formula: . Geometry: square planar, Pt is Pt(II), a ion. Square planar geometry is why the two chlorides can sit either apart (cis) or apart (trans). See Square planar complexes.

Q1.3 Name the industrial catalyst for (a) hydrogenation of alkenes and (b) polymerisation of ethene.

Recall Solution

(a) Wilkinson's catalyst, — adds across a double bond. (b) Ziegler–Natta catalyst, — links ethene molecules into polythene.


Level 2 — Application

(Use a rule on a fresh case.)

Q2.1 A patient inhales carbon monoxide. Given that CO binds the O₂ site of haemoglobin about more strongly than O₂, and the reaction is explain which direction the equilibrium shifts and how giving pure O₂ helps.

Recall Solution

Step 1 — WHAT is happening: CO and O₂ fight for the same 6th axial site on Fe(II). CO wins because it binds tighter, so the forward reaction (making HbCO) is favoured. Step 2 — WHY pure O₂ helps: Le Chatelier — flood the system with O₂ on the right side. A large pushes the equilibrium backwards, reforming and releasing CO. Step 3 — WHAT it means: CO never destroyed anything. It was pure coordination competition. Raise and you out-vote the CO.

Q2.2 Estimate: if oxygen occupies a fraction of sites at some partial pressures, and CO is present at the pressure of O₂, what fraction of sites does CO grab? (Assume relative binding = binding strength × pressure.)

Recall Solution

"Relative pull" of each gas (binding strength) (pressure).

  • O₂ pull .
  • CO pull .

They are equal! So CO takes of sites even though its pressure is smaller. Fraction on CO . That is why tiny traces of CO are lethal — its strength exactly cancels a dilution.


Level 3 — Analysis

(Take it apart; say why each part is needed.)

Q3.1 Cisplatin works but transplatin does not. Both are . Using the geometry, explain the difference. A picture will help.

Recall Solution

Step 1 — geometry: Pt(II) is square planar (four ligands at the corners of a square, between neighbours, across the diagonal). See Crystal Field Theory for why gives square planar. Step 2 — the leaving groups: Inside the cell the two hydrolyse off, leaving two open bonds where DNA nitrogen atoms will attach. Step 3 — the bite distance:

  • cis: the two Cl are apart → the two new bonds point at neighbouring corners → Pt can grab two adjacent guanine bases, kinking the DNA. Replication stops → cancer cell dies.
  • trans: the two Cl are apart → the bonds point in opposite directions → Pt cannot reach two neighbouring bases → no crosslink → inactive.
Figure — Applications — biological (haemoglobin, chlorophyll, vit B₁₂), medicinal (cisplatin), industrial (catalysts)

This is geometric isomerism (Isomerism in coordination compounds) deciding biological life and death. Same formula, different arrangement, different job.

Q3.2 Why must the metal in chlorophyll be redox-inert Mg(II), while haemoglobin needs a redox-active Fe(II)? Analyse the job each metal does.

Recall Solution

Haemoglobin's job = grab and release O₂. Reversible binding of a small molecule needs a metal whose -orbitals can accept and back-donate electrons — Fe(II) does exactly this. It must not be permanently oxidised (Fe(III) = methaemoglobin can't carry O₂), but it must be able to interact electronically. Chlorophyll's job = hold a light-catching antenna rigid. Here you don't want the metal changing oxidation state — a redox event would drain the captured light energy into the wrong place. Mg(II) has no easy oxidation-state change, so it simply clamps the conjugated ring flat, keeping the absorption band sharp and channelling the excited electron cleanly. Conclusion: the required function selects the metal. Reactivity → Fe. Rigidity → Mg.


Level 4 — Synthesis

(Combine ideas you were never handed together.)

Q4.1 Design an argument: why does life use a macrocyclic ring (porphyrin/corrin) instead of four separate small ligands to hold the metal? Bring in the Stability and chelate effect.

Recall Solution

Idea 1 — the chelate effect: A ligand that binds through several donor atoms at once (a chelate) makes a far more stable complex than the same number of separate single-donor ligands. Reason: releasing one arm doesn't release the whole ligand — it's still tethered — so the metal stays locked. Idea 2 — a macrocycle is the extreme chelate: all four N-donors are pre-organised in one rigid ring (the "macrocyclic effect"), even more stable than an open chain chelate. The metal essentially cannot fall out. Idea 3 — geometry for free: the flat ring forces four donors into the equatorial plane and leaves the two axial sites open for the actual chemistry (O₂, histidine, –CN). Synthesis: Life needs a metal that (a) stays put for the cell's whole lifetime and (b) has a clean, reserved reactive site. A macrocycle delivers both — maximum stability and a pre-shaped axial pocket. Four loose ligands would drift off and would not organise the axial sites.

Q4.2 Propose why a homogeneous metal-complex catalyst (dissolved, e.g. Wilkinson's) can be more selective than a bare metal surface, and connect it to "variable oxidation state" and "open coordination site".

Recall Solution

Building block 1 — open site: a catalytic complex has a vacant coordination position. The reactant (, alkene) docks there, in one precise orientation — not randomly like on a metal surface. Building block 2 — variable oxidation state: the metal can temporarily change its oxidation number (e.g. Rh(I) → Rh(III) as adds on, then back). This lets it hold the reactant, rearrange it, and release the product, returning to the start — a genuine catalytic cycle. See Oxidation states of transition metals. Synthesis: because every catalyst molecule is identical and dissolved, each one binds and orients the substrate the same way → high selectivity and mild conditions. It is a reusable molecular workbench: dock → transform → eject → repeat.


Level 5 — Mastery

(One clean chain of reasoning from scratch.)

Q5.1 A student claims: "We could swap the Fe(II) in haemoglobin for Mg(II) and still carry oxygen, since both are ." Demolish or defend this in a full chain of reasoning, using everything above.

Recall Solution

Claim under test: charge alone () determines O₂ carrying. Verdict: false — here is the chain.

  1. Carrying O₂ = reversibly forming and breaking an Fe–O₂ bond. That requires the metal's -orbitals to accept O₂'s electrons and back-donate — a redox-capable metal.
  2. Fe(II) is a transition metal with partly filled -orbitals → it can do this delicate electron give-and-take (and can be pushed to Fe(III), which is why oxidation to met-Hb must be avoided).
  3. Mg(II) has a noble-gas electron configuration — no accessible -electrons, redox-inert. It cannot form the reversible dative O₂ bond at all; it would just sit there or bind water.
  4. Matching charge () does not match electronic capability. Chlorophyll deliberately uses Mg(II) precisely because it won't do redox (Q3.2). Conclusion: the swap fails — same charge, wrong electronics. Function is set by the -electron chemistry, not by the ionic charge.

Q5.2 Grand synthesis. In one paragraph, state the single unifying principle behind haemoglobin, chlorophyll, B₁₂, and cisplatin.

Recall Solution

Unifying principle: A metal ion's usefulness is tuned by wrapping it in the right ligand cage with the right geometry, leaving a controlled reactive site. Fe(II) + porphyrin + one open axial site → reversible O₂ transport. Mg(II) + porphyrin (redox-inert core) → rigid light antenna. Co(III) + corrin + a metal–carbon axial bond → DNA-building enzyme. Pt(II) + square-planar geometry + two cis leaving groups → a DNA crosslinker. Change the metal, the ring, the oxidation state, or the geometry — and you change the job entirely. The cage makes the function.


Flashcards

At 1/200th the pressure of O₂ but 200× the binding strength, what fraction of Hb sites does CO grab?
About half (equal pull) — that's why traces of CO are lethal
Why does trans-platin fail as a drug?
Its two leaving groups are 180° apart and cannot reach two adjacent DNA bases to crosslink
Why can't Mg(II) replace Fe(II) in haemoglobin?
Mg(II) is redox-inert (noble-gas config, no d-electrons) so it cannot form the reversible dative O₂ bond
One-line unifying principle of all these systems?
The metal's function is set by its ligand cage + geometry + reserved reactive site — the cage makes the function
Why a macrocycle instead of four separate ligands?
Chelate/macrocyclic effect gives huge stability plus a pre-shaped ring that leaves the axial sites free

Connections

  • Isomerism in coordination compounds — cis/trans bite angle (Q3.1)
  • Square planar complexes — why Pt(II) is square planar
  • Crystal Field Theory geometry and colour
  • Stability and chelate effect — why macrocycles lock the metal in (Q4.1)
  • Oxidation states of transition metals — Fe(II)/(III), Rh(I)/(III) redox cycling