3.3.8 · Chemistry › d-Block (Transition Metals) & f-Block
Lanthanides woh 14 elements hain jisme electrons deep, buried 4f subshell mein thuse ja rahe hain. Kyunki 4f electrons atom ke andar rehte hain (poor shielding karte hain), ek element se doosre element tak chemistry practically badlti nahi — isliye saare 14 almost identical lagte hain, zyaadatar +3 ions banate hain, aur row ke across steadily chhhote hote jaate hain. Yahi shrinkage famous lanthanide contraction hai, aur yeh secretly explain karta hai kyun 5d elements (Hf, Ta, W...) surprisingly chhhote aur dense hain.
14 elements ==Cerium (Ce, Z=58) se Lutetium (Lu, Z=71) tak, jinmein differentiating electron 4f== subshell mein jaata hai. La ke saath milkar yeh "lanthanoids" banate hain.
Yeh Period 6 mein hain, main table ke neeche rakhe gaye hain taaki table compact rahe.
14 KYO? f subshell mein ℓ = 3 hai, isliye m ℓ = − 3 , − 2 , − 1 , 0 , + 1 , + 2 , + 3 → 7 orbitals → 7 × 2 = 14 electrons aate hain. Un 14 spots ko fill karna = 14 elements.
YEH ORDER KYO? ( n + ℓ ) rule se:
4 f : n + ℓ = 4 + 3 = 7
5 d : n + ℓ = 5 + 2 = 7 (same sum, isliye n compare karo: 4f pehle fill hoti hai 5d se... zyaadatar)
6 s : n + ℓ = 6 + 0 = 6 → pehle fill hoti hai
Isliye pehle 6 s fill hoti hai, phir 4f aur 5d compete karte hain. 4f aur 5d ki energies bahut close hain, isliye do anomalies aate hain:
Element
Z
Configuration
Anomalous kyun hai
La
57
[ Xe ] 5 d 1 6 s 2
(4f empty — 5d mein jaana aasaan)
Ce
58
[ Xe ] 4 f 1 5 d 1 6 s 2
Eu
63
[ Xe ] 4 f 7 6 s 2
half-filled 4f7 stability
Gd
64
[ Xe ] 4 f 7 5 d 1 6 s 2
stable 4f7 rakho, extra e⁻ → 5d
Yb
70
[ Xe ] 4 f 14 6 s 2
fully-filled 4f14
Lu
71
[ Xe ] 4 f 14 5 d 1 6 s 2
4f full → extra e⁻ → 5d
Common mistake "Saare lanthanides mein ek 5d¹ electron hota hai"
Yeh sahi kyun lagta hai: La 5 d 1 se start karta hai, toh tumhe lagta hai pattern continue hoga. Fix: La ke baad, electron usually 4f mein gir jaata hai (kyunki Z badhne ke saath 4f ki energy neeche aa jaati hai). Sirf La, Ce, Gd, Lu hi 5 d 1 rakhte hain (yeh "exceptions" empty/half/full f-shell stability ki wajah se hain). Zyaadatar lanthanides ka 5 d 0 hota hai.
Intuition +3 kyun dominate karta hai
Ek lanthanide atom roughly [ Xe ] 4 f n 6 s 2 hota hai (5d¹ ko borrowable maano). Jab yeh ionise hota hai, toh dono loosely-held 6s electrons aur ek (5d ya 4f) electron lost hote hain — teeno sabse bahar ke, weakly-bound electrons. Baaki bache 4f electrons kaafi andar bury hote hain aur 5s,5p se shield hote hain, isliye inhe remove karna mushkil hai. Result: poori series mein +3 energetically natural aur bahut stable hai .
Doosre states sirf tabhi aate hain jab koi extra-stable 4f config milti ho:
Ion
f-config
Stable kyun
Behaves as
Ce 4 +
4 f 0
empty f (= La³⁺ jaisa)
powerful oxidiser
Eu 2 +
4 f 7
half-filled f
powerful reducer
Yb 2 +
4 f 14
full f
reducer
Tb 4 +
4 f 7
half-filled f
oxidiser
Common mistake "Ce⁴⁺ stable hai toh +4 common hoga"
Yeh sahi kyun lagta hai: Ce⁴⁺ (cerium ammonium nitrate) ek famous lab oxidiser hai, isliye +4 normal lagta hai. Fix: +4 ek exception hai, yahaan stable sirf isliye hai kyunki Ce⁴⁺ empty 4 f 0 configuration tak pahunch jaata hai. Phir bhi yeh ek powerful oxidiser hai (ek e⁻ grab karke wapas cosy +3 par jaana chahta hai).
Definition Lanthanide contraction
La se Lu tak atomic aur ionic (Ln³⁺) radii mein steady decrease jab 4f series mein atomic number badhti hai.
Intuition YEH KYUN HOTA HAI?
Har ek step daayein: nucleus mein +1 proton (pull ↑) aur +1 electron 4f mein . Lekin 4f orbitals diffuse aur aisi shape ke hain ki yeh bahut poorly shield karte hain — ek added 4f electron doosre electrons ke liye added nuclear charge ko effectively cancel nahi karta. Isliye outer 5s5p6s electrons par mehsoos hone wali effective nuclear charge (Z eff ) baar baar badhti rehti hai , poore electron cloud ko andar khenchti hai. Radius thodi thodi karke, 14 baar, chhhoti hoti jaati hai.
poor shielding of 4f
Z↑ each step ──────────────► Z_eff (on outer e⁻) ↑ ──► radius ↓
KITNA BADA? Har step mein thoda (~1 pm ionic radius mein) lekin 14 elements ke baad yeh accumulated shrinkage kaafi zyaada ho jaati hai:
r ( La 3 + ) ≈ 103 pm ⟶ r ( Lu 3 + ) ≈ 86 pm
Worked example Consequence 2 — gradual property changes aur separation
Yeh step kyun? Kyunki radii itni smoothly change hoti hain, Ln³⁺ ions mein sirf thoda sa size ka farq hota hai → similar basicity → alag karna mushkil (ion-exchange / solvent extraction ki zaroorat padti hai).
Hydroxides ki basicity decrease hoti hai La(OH)₃ → Lu(OH)₃ (chhhota ion = stronger M–O bond = kam ionic OH⁻ release).
Common mistake "Contraction matlab electrons remove ho rahe hain"
Yeh sahi kyun lagta hai: "Contraction = chhhota hona = kuch kho dena." Fix: Electrons add ho rahe hain. Atom isliye shrunken hota hai kyunki added nuclear charge poorly-shielding 4f electron par bhaari padti hai. Yeh ek tug-of-war hai jisme nucleus jeet jaata hai.
Worked example Eu aur Eu³⁺ ki configuration predict karo
Eu ka Z=63 hai. Core [Xe]=54, baaki 9 electrons.
Kyun? Hamesha noble-gas core se shuru karo.
6 s 2 rakho, phir 4f. 9 − 2 = 7 electrons 4f mein → 4 f 7 .
Kyun? 4 f 7 half-filled hai (special stability), isliye koi 5d electron borrow nahi hota.
→ Eu = [Xe]4f⁷6s²
Eu³⁺: 2 (6s) + 1 (4f) remove karo → 4 f 6 .
Kyun? Pehle outermost/weakest hatao (6s), phir ek 4f.
→ Eu³⁺ = [Xe]4f⁶ . (Aur Eu²⁺ = 4f⁷ uski stability explain karta hai!)
Worked example Hf itna dense kyun hai?
Density ∝ mass/volume.
Kyun? Zyaada mass kam jagah mein packed.
Lanthanide contraction Hf ki volume chhhoti rakhta hai jabki uska atomic mass bada hai.
→ high density (~13.3 g/cm³). Yeh step kyun? Contraction atom ko shrink karta hai bina mass ko shrink kiye.
#flashcards/chemistry
How many lanthanides are there and which 4f range? 14 elements (Ce→Lu); 4f¹ to 4f¹⁴
General ground-state config of a lanthanide atom [Xe] 4f¹⁻¹⁴ 5d⁰⁻¹ 6s²
Which lanthanides have a 5d¹ electron in the ground state? La, Ce, Gd, Lu (empty/half/full 4f stability)
Configuration of Ln³⁺ in general [Xe] 4f^n (loses 6s² and one 5d/4f electron)
Why is +3 the most common oxidation state? Do 6s + ek (5d/4f) loose hote hain; baaki 4f buried/shielded hain → remove karna mushkil
Why is Ce⁴⁺ stable? Empty 4f⁰ configuration deta hai; strong oxidiser ki tarah kaam karta hai
Why is Eu²⁺ relatively stable? Half-filled 4f⁷ deta hai; reducer ki tarah kaam karta hai
Define lanthanide contraction La se Lu tak atomic/ionic radii mein steady decrease jab Z 4f series mein badhta hai
Root cause of lanthanide contraction 4f electrons ki poor shielding → outer electrons par Z_eff har added proton ke saath badhti hai
Main consequence on Zr vs Hf Nearly equal radii (Zr≈Hf), isliye dono chemically bahut similar / hard to separate hain
Trend in basicity of Ln(OH)₃ across the series Decrease hoti hai La(OH)₃ → Lu(OH)₃ (chhhota ion, stronger M–OH bond)
Eu³⁺ electronic configuration [Xe] 4f⁶
Recall Feynman: 12-saal ke bacche ko explain karo
Socho ek class mein 14 almost-identical twins hain (lanthanides). Har naya twin secretly ek extra coin (ek 4f electron) apni deep pocket mein chhupaata hai, jahan koi dekh nahi sakta. Toh sab ek jaese lagte hain aur ek jaesa behave karte hain — inme se almost sab maangne par exactly 3 cheezein dete hain (+3 ion). Lekin har twin ke pet mein ek extra magnet (ek proton) bhi aa jaata hai jo unke kapde aur tight khenchta hai. Hidden coin push back nahi kar sakta, isliye har twin apne pehle waale se thoda chhhota hota hai. 14th twin tak, yeh kaafi chhhote ho chuke hote hain — wahi shrinkage "lanthanide contraction" hai, aur yahi unke baad aane waale kid (Hafnium) ko surprisingly chhhota aur heavy banaata hai.
Mnemonic Exceptions aur defaults yaad karo
"La Ce Gd Lu Drive (5d¹)" — woh chaar lanthanides jo 5d¹ electron rakhte hain.
"+3 by default; +4 agar 4f⁰ (Ce) mile, +2 agar 4f⁷/4f¹⁴ (Eu/Yb) mile."
Contraction: "Zyaada protons, lazy f-shields → atom shrunken hoti hai."
Recall Active recall — note band karo aur jawab do
Gd aur Gd³⁺ ki configuration likho.
Lanthanide contraction ke do consequences batao.
+3 kyun hai, +2 ya +4 nahi, universal oxidation state?