3.3.8 · Hinglishd-Block (Transition Metals) & f-Block

Lanthanides — electronic configuration, lanthanide contraction, oxidation states (mostly +3)

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3.3.8 · Chemistry › d-Block (Transition Metals) & f-Block


1. Lanthanides kaun hain?

14 KYO? f subshell mein hai, isliye → 7 orbitals → electrons aate hain. Un 14 spots ko fill karna = 14 elements.


2. Electronic configuration

YEH ORDER KYO? rule se:

  • :
  • : (same sum, isliye compare karo: 4f pehle fill hoti hai 5d se... zyaadatar)
  • : → pehle fill hoti hai

Isliye pehle fill hoti hai, phir 4f aur 5d compete karte hain. 4f aur 5d ki energies bahut close hain, isliye do anomalies aate hain:

Element Z Configuration Anomalous kyun hai
La 57 (4f empty — 5d mein jaana aasaan)
Ce 58
Eu 63 half-filled 4f stability
Gd 64 stable 4f rakho, extra e⁻ → 5d
Yb 70 fully-filled 4f
Lu 71 4f full → extra e⁻ → 5d

3. +3 oxidation state (default)

Doosre states sirf tabhi aate hain jab koi extra-stable 4f config milti ho:

Ion f-config Stable kyun Behaves as
empty f (= La³⁺ jaisa) powerful oxidiser
half-filled f powerful reducer
full f reducer
half-filled f oxidiser

4. Lanthanide contraction

            poor shielding of 4f
   Z↑ each step  ──────────────►   Z_eff (on outer e⁻) ↑   ──►  radius ↓

KITNA BADA? Har step mein thoda (~1 pm ionic radius mein) lekin 14 elements ke baad yeh accumulated shrinkage kaafi zyaada ho jaati hai:

Figure — Lanthanides — electronic configuration, lanthanide contraction, oxidation states (mostly +3)

Consequences (woh 20% jo 80% marks laata hai)


5. Quick worked reasoning


6. Flashcards

#flashcards/chemistry

How many lanthanides are there and which 4f range?
14 elements (Ce→Lu); 4f¹ to 4f¹⁴
General ground-state config of a lanthanide atom
[Xe] 4f¹⁻¹⁴ 5d⁰⁻¹ 6s²
Which lanthanides have a 5d¹ electron in the ground state?
La, Ce, Gd, Lu (empty/half/full 4f stability)
Configuration of Ln³⁺ in general
[Xe] 4f^n (loses 6s² and one 5d/4f electron)
Why is +3 the most common oxidation state?
Do 6s + ek (5d/4f) loose hote hain; baaki 4f buried/shielded hain → remove karna mushkil
Why is Ce⁴⁺ stable?
Empty 4f⁰ configuration deta hai; strong oxidiser ki tarah kaam karta hai
Why is Eu²⁺ relatively stable?
Half-filled 4f⁷ deta hai; reducer ki tarah kaam karta hai
Define lanthanide contraction
La se Lu tak atomic/ionic radii mein steady decrease jab Z 4f series mein badhta hai
Root cause of lanthanide contraction
4f electrons ki poor shielding → outer electrons par Z_eff har added proton ke saath badhti hai
Main consequence on Zr vs Hf
Nearly equal radii (Zr≈Hf), isliye dono chemically bahut similar / hard to separate hain
Trend in basicity of Ln(OH)₃ across the series
Decrease hoti hai La(OH)₃ → Lu(OH)₃ (chhhota ion, stronger M–OH bond)
Eu³⁺ electronic configuration
[Xe] 4f⁶

Recall Feynman: 12-saal ke bacche ko explain karo

Socho ek class mein 14 almost-identical twins hain (lanthanides). Har naya twin secretly ek extra coin (ek 4f electron) apni deep pocket mein chhupaata hai, jahan koi dekh nahi sakta. Toh sab ek jaese lagte hain aur ek jaesa behave karte hain — inme se almost sab maangne par exactly 3 cheezein dete hain (+3 ion). Lekin har twin ke pet mein ek extra magnet (ek proton) bhi aa jaata hai jo unke kapde aur tight khenchta hai. Hidden coin push back nahi kar sakta, isliye har twin apne pehle waale se thoda chhhota hota hai. 14th twin tak, yeh kaafi chhhote ho chuke hote hain — wahi shrinkage "lanthanide contraction" hai, aur yahi unke baad aane waale kid (Hafnium) ko surprisingly chhhota aur heavy banaata hai.

Connections

Concept Map

fill

7 orbitals x2

general config

(n+l) rule

f/5d energies close

empty half full shell

buried, poor shielding

size shrinks across row

4f deeply shielded

gives

forms

other states rare

Lanthanides 14 elements

4f subshell

holds 14 electrons

[Xe] 4f 5d 6s2

6s fills first

Anomalies La Ce Gd Lu

keep 5d1

Lanthanide contraction

5d elements small dense

loses 6s2 plus one e

+3 default state

Ln3+ = [Xe] 4f n

extra stability only