2.2.4 · Chemistry › Periodic Trends
Ek atom mein nucleus electrons ko kheench raha hai, aur baaki electrons shield aur repel kar rahe hain. Ionization energy (IE) basically yeh pooch rahi hai: "Ek electron churaana kitna mushkil hai?" Iska jawaab nuclear attraction aur electron shielding/repulsion ke beech ki tug-of-war par depend karta hai. Har trend aur har "ajeeb" anomaly bas yahi tug-of-war hai jo play out ho rahi hai.
Definition Ionization energy
First ionization energy (I E 1 ) woh minimum energy hai jo gaseous atoms ke ek mole se, unke ground state mein, sabse loosely held electron ko remove karne ke liye chahiye.
X ( g ) → X + ( g ) + e − Δ H = I E 1 > 0
Second ionization energy (I E 2 ) resulting cation se ek electron aur remove karta hai:
X + ( g ) → X 2 + ( g ) + e − Δ H = I E 2
Hamesha positive (endothermic) hoti hai — electron bahar nikaalte waqt nucleus se ladna padta hai.
Gaseous atoms ke liye measure ki jaati hai taaki koi bonding/lattice energy interfere na kare.
Units: usually kJ mol − 1 (ya eV/atom, jahan 1 eV = 96.49 kJ mol − 1 ).
Intuition Coulomb hi poori kahani hai
Ek rough hydrogen-like model shell n mein electron ki energy deta hai:
E n = − n 2 Z eff 2 × 13.6 eV
Ionize karne ke liye hum + ∣ E n ∣ supply karte hain:
I E ≈ 13.6 eV × n 2 Z eff 2
Isse machine ki tarah padho:
Z eff ↑⇒ I E ↑ (zyada pull).
n ↑ (bada shell, electron door) ⇒ I E ↓ .
Effective nuclear charge: Z eff = Z − S , jahan S = inner/other electrons ki shielding (Slater's rules se S estimate hoti hai).
Yeh akela formula dono periodic trends explain karta hai 👇
Yeh period ke across smooth increase ko "todti" hain. Do causes hain.
Mnemonic Do "dips" yaad rakho
"Be Bored, N O!"
Be > B : full s , akele shielded p se zyada behtaar.
N > O : half-filled p 3 , paired p 4 se zyada behtaar.
Dono dips isliye hain kyunki element pehle waala unusually stable hai, na ki anomalous element unstable hai.
Worked example IE jumps se electron configuration padhna
Mg ke successive IEs (kJ/mol): 738 , 1451 , 7733 , 10540 , …
I E 2 se I E 3 tak ek bada jump hai.
KYUN? Mg hai [ Ne ] 3 s 2 . 2 electrons remove karne ke baad tum noble-gas core [ Ne ] tak pahunch jaate ho. Stable inner shell se teesra electron kheenchna bahut zyada energy maangta hai.
Rule: g electrons remove karne ke baad sudden large jump batata hai ki atom ke g valence electrons hain ⇒ group number. Mg: jump 2 ke baad ⇒ Group 2 .
Common mistake Common errors ko steel-man karna
Galti A: "Zyada protons hamesha higher IE dete hain, koi exception nahi."
Kyun sahi lagta hai: Z eff genuinely period ke across badhta hai, isliye "zyada pull" default hai.
Fix: IE yeh bhi depend karta hai ki electron kis orbital se nikala ja raha hai aur pairing repulsion kaisi hai. Jab woh effects extra proton par bhaari pad jaate hain (B<Be, O<N), trend dip karta hai. Orbital compare karo, sirf Z nahi.
Galti B: "Na ka I E 2 sirf I E 1 se thoda zyada hai."
Kyun sahi lagta hai: successive IEs hamesha gradually badhte hain... yeh assumption hai.
Fix: Na hai [ Ne ] 3 s 1 . I E 2 noble-gas core mein todta hai → ek enormous jump (~9× bada). Core-breaking jumps dhyaan se dekho.
Galti C: "IE aur electron affinity same magnitude/sign ke hain."
Fix: IE woh energy hai jo electron remove karne mein absorb hoti hai (endothermic, +). Yeh EA (ek add karna) se alag process hai. Inhein mix mat karo.
Worked example Coulomb model se Li ka
I E 1 estimate karo
Li = 1 s 2 2 s 1 . 2 s electron: n = 2 , aur Z = 3 , do 1 s electrons se shielded.
Step: S ≈ 2 × 0.85 = 1.70 estimate karo (Slater: inner shell electrons ≈0.85 each shield karte hain). KYUN? Inner electrons nuclear charge ka zyaadatar hissa block karte hain.
Z eff = 3 − 1.70 = 1.30 .
I E ≈ 13.6 × 2 2 1.3 0 2 = 13.6 × 4 1.69 ≈ 5.75 eV .
Check karo: experimental I E 1 ( Li ) = 5.39 eV — same ballpark! Model physics capture karta hai. Chhoti error kyun? Slater's rules approximate hain aur real orbital perfectly hydrogen-like nahi hai.
Recall Quick self-test (answers chupaao)
I E 2 > I E 1 hamesha kyun? → same Z , kam electrons ⇒ higher Z eff /less repulsion.
Group mein neeche IE kyun girta hai? → naya shell, bada n , zyada shielding.
I E ( B ) < I E ( Be ) kyun? → B ka electron ek shielded higher-energy 2 p mein hai.
I E ( O ) < I E ( N ) kyun? → paired 2 p 4 repulsion vs stable half-filled p 3 .
3 electrons remove karne ke baad jump ka matlab? → 3 valence electrons ⇒ Group 13.
Recall Feynman: ek 12-saal ke bachche ko samjhao
Socho har electron ek bachcha hai jo ek magnet (nucleus) se haath mila ke khada hai. Ionization energy yeh hai ki us bachche ko tod ke alag karne ke liye kitni mehnat lagti hai. Agar magnet zyada strong hai (zyada protons), toh todna mushkil hai. Agar bachcha door outer ring mein khada hai, ya baaki bachche magnet ko block kar rahe hain, toh todna aasaan hai. Kabhi kabhi ek bachcha ek bheed wali jagah khada hota hai jahan do bachche ek doosre ko dhakka de rahe hain — woh pehle se ek doosre ko hata rahe hain, toh ek ko kheenchna kam mehnat maangta hai. Isliye oxygen nitrogen se zyada aasaani se electron chodta hai!
First ionization energy ki definition Ek mole gaseous ground-state atoms se sabse loosely held electron remove karne ki minimum energy: X ( g ) → X + ( g ) + e − .
IE hamesha positive (endothermic) kyun hoti hai Nuclear attraction overcome karke negative electron kheenchne ke liye energy supply karni padti hai.
Same element ke liye I E 2 > I E 1 kyun Kam electrons lekin same nuclear charge → higher Z e f f aur baaki electrons par kam repulsion.
Period ke across trend aur kyun IE badhti hai; Z badhta hai lekin electrons same shell mein jaate hain toh shielding kam hai → Z e f f ↑ , radius ↓ .
Group mein neeche trend aur kyun IE ghatti hai; naye shells n aur shielding badhate hain, valence electron nucleus se door ho jaata hai.
I E 1 ( B ) < I E 1 ( B e ) kyunB ka outer electron higher-energy 2 p orbital mein hai jo 2 s 2 se shielded hai, Be ke stable 2 s 2 se aasaan remove hota hai.
I E 1 ( O ) < I E 1 ( N ) kyunN ka stable half-filled 2 p 3 hai; O ke paired 2 p 4 mein electron–electron repulsion hai, isliye ek electron zyada aasaani se nikalta hai.
Hydrogen-like IE formula I E ≈ 13.6 eV × Z e f f 2 / n 2 , jahan Z e f f = Z − S .
Successive IEs mein sudden large jump kya indicate karta hai Atom noble-gas core tak pahunch gaya; aasaani se remove hone wale electrons ki sankhya = valence electrons = group.
Z e f f ka matlabActual nuclear charge Z mein se shielding S ghatane ke baad electron ko feel hone wali net positive charge.
Gaseous ground-state atoms
Effective nuclear charge Zeff
Shielding and repulsion S
Across period IE increases