1.3.1Chemical Reactions & Stoichiometry

Writing and balancing chemical equations

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WHY do we balance at all?

WHY this matters: If Hydrogen and Oxygen combine to make water, the 2 H atoms and 1 O atom you started with must still exist afterward — just bonded differently. An unbalanced equation would claim atoms vanished or appeared from nothing, which is physically false.


WHAT are the parts of an equation?

2H2+O2reactants2H2Oproducts\underbrace{2H_2 + O_2}_{\text{reactants}} \longrightarrow \underbrace{2H_2O}_{\text{products}}

  • Coefficient (big number in front, e.g. the 2) — you MAY change this to balance.
  • Subscript (small number, e.g. H₂) — you may NEVER change this; it defines the substance.
  • State symbols: (s)(s) solid, (l)(l) liquid, (g)(g) gas, (aq)(aq) dissolved in water.
  • Arrow \rightarrow "yields". A double arrow \rightleftharpoons means reversible.
Figure — Writing and balancing chemical equations

HOW to balance — the reliable recipe

WHY save O and H for last? They usually appear in the most compounds (water, oxides, acids), so fixing everything else first leaves them as the final "adjustable slack."


Example 1 — Combustion of methane

Skeleton: CH4+O2CO2+H2OCH_4 + O_2 \rightarrow CO_2 + H_2O

Step Action Why this step?
C 1 C left, 1 C right ✓ Balance the rarest element first
H 4 H left → need 4 H right → 2H2O2H_2O 2×2=42\times2=4 H
O Right now: 2(from CO2)+2(from 2H2O)=42(\text{from }CO_2)+2(\text{from }2H_2O)=4 O → put 2O22O_2 O last: sum the O on product side

Balanced: CH4+2O2CO2+2H2OCH_4 + 2O_2 \rightarrow CO_2 + 2H_2O Check: C 1=1, H 4=4, O 4=4 ✓


Example 2 — Rusting-style with fractions

Skeleton: Fe+O2Fe2O3Fe + O_2 \rightarrow Fe_2O_3

Step Action Why?
Fe 2 Fe on right → 2Fe2Fe left metals first
O 3 O on right, 2 per O2O_2 → need 32O2\tfrac{3}{2}O_2 fractions allowed temporarily
Clear ×2 everything integer coefficients required in final form

4Fe+3O22Fe2O34Fe + 3O_2 \rightarrow 2Fe_2O_3 Check: Fe 4=4, O 6=6 ✓ — Why ×2? 32O2\tfrac32 O_2 means "1.5 molecules," impossible physically, so scale up.


Example 3 — Polyatomic ion as a unit

Skeleton: Al+H2SO4Al2(SO4)3+H2Al + H_2SO_4 \rightarrow Al_2(SO_4)_3 + H_2

Step Action Why?
SO4SO_4 3 sulfate on right → 3H2SO43H_2SO_4 treat SO4SO_4 as one block, don't split
Al 2 Al on right → 2Al2Al metal
H left 3×2=63\times2=6 H → need 3H23H_2 H last

2Al+3H2SO4Al2(SO4)3+3H22Al + 3H_2SO_4 \rightarrow Al_2(SO_4)_3 + 3H_2 Check: Al 2=2, S 3=3, O 12=12, H 6=6 ✓


Forecast-then-Verify drill


Recall Feynman: explain to a 12-year-old

Imagine you have LEGO blocks and you build a car. Then you smash it and build a boat. You can't lose or magically get new blocks — you must use the exact same pieces. A chemical equation is a promise that we counted every LEGO block before and after, and the counts match. We only decide how many cars and boats (coefficients), never break the individual blocks (subscripts).


Flashcards

Why must a chemical equation be balanced?
Because of the Law of Conservation of Mass — atoms are neither created nor destroyed, so atom counts must be equal on both sides.
What may you change to balance an equation, and what may you NEVER change?
You may change coefficients; you may NEVER change subscripts (that changes the substance's identity).
In balancing order, which elements are done first and which last?
Metals first, then non-metals, then hydrogen, then oxygen last.
Balance: CH4+O2CO2+H2OCH_4 + O_2 \rightarrow CO_2 + H_2O
CH4+2O2CO2+2H2OCH_4 + 2O_2 \rightarrow CO_2 + 2H_2O
Balance: Fe+O2Fe2O3Fe + O_2 \rightarrow Fe_2O_3
4Fe+3O22Fe2O34Fe + 3O_2 \rightarrow 2Fe_2O_3
Balance: C3H8+O2CO2+H2OC_3H_8 + O_2 \rightarrow CO_2 + H_2O
C3H8+5O23CO2+4H2OC_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O
How do you handle a polyatomic ion like SO42SO_4^{2-} that stays intact?
Treat it as a single unit and balance it as one token.
What do (s),(l),(g),(aq)(s), (l), (g), (aq) mean?
Solid, liquid, gas, aqueous (dissolved in water).
Why do we sometimes use fractional coefficients, and what do we do afterward?
To balance an odd atom count (e.g. O); afterward multiply all coefficients by the smallest integer to clear fractions.
The general balance condition for element E is?
reactants(coeff×subscript)=products(coeff×subscript)\sum_{reactants}(\text{coeff}\times\text{subscript}) = \sum_{products}(\text{coeff}\times\text{subscript}).

Connections

Concept Map

because

requires

achieved by

adjusts only

never touches

defines

changes chemical identity

follows

balance in order

treat groups as

ends with

confirms

Law of Conservation of Mass

Atoms rearrange not created or destroyed

Balanced chemical equation

Balancing

Coefficients - big numbers

Subscripts - small numbers

Balancing recipe

Metals then nonmetals then H then O

Polyatomic ions as single units

Verify tally each element

Wrong: change subscript

Hinglish (regional understanding)

Intuition Hinglish mein samjho

Dekho, chemical equation basically ek "hisaab-kitaab" hai atoms ka. Law of Conservation of Mass kehta hai ki atoms na paida hote hain na gayab hote hain — reaction me sirf unka rearrangement hota hai. Isliye jitne H aur O atoms reactant side pe hain, utne hi product side pe hone chahiye. Agar nahi hain, to equation "unbalanced" hai aur physically galat hai.

Balance karne ka sabse bada rule: sirf coefficient (aage wala bada number) change karo, subscript (chhota number) kabhi mat chhedo. Kyun? Kyunki subscript badalne se cheez hi badal jaati hai — H2OH_2O paani hai lekin H2O2H_2O_2 bleach hai! Bilkul alag substance.

Order yaad rakho: pehle Metal, phir Non-metal, phir Hydrogen, aur Oxygen last. Iska mnemonic hai "Metals Never Have Oxygen last". Oxygen last isliye kyunki wo sabse zyada compounds me aata hai, to use adjust karna aasan rehta hai baaki sab set karne ke baad. Agar odd number aa jaaye (jaise Fe2O3Fe_2O_3 me 3 oxygen), to temporarily fraction (32O2\frac32 O_2) use karo, phir sabko multiply karke integer bana lo.

Ye topic foundation hai — mole concept, stoichiometry, limiting reagent sab isi pe khade hain. Ek baar balancing ki practice pakki ho gayi to numericals easy lagenge, kyunki coefficients hi mole ratios dete hain.

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Connections