3.6.15 · D5Spacecraft Structures & Systems Engineering
Question bank — Composite materials — fiber-matrix, ply properties, laminate theory
Before the traps, a short glossary so every symbol below is earned before use.
Recall The two directions every answer refers to
What do the material axes "1" and "2" mean? ::: Axis 1 runs along the fibers (stiff, strong); axis 2 runs across the fibers, through the weak matrix — the whole point of a ply is that these two directions behave completely differently.
Two pictures anchor the two rules and the four matrices you'll meet below.


True or false — justify
TF1. A composite with GPa is "as good as" a 140 GPa isotropic metal.
False — that 140 GPa only exists along the fibers; across them may be ~10 GPa, so the material is roughly 14× softer transversely and cannot be treated like isotropic aluminium.
TF2. The longitudinal Rule of Mixtures assumes fiber and matrix feel the same stress.
False — it assumes the same strain (they are bonded and stretch together in parallel, like parallel springs); each phase then carries stress proportional to its own stiffness.
TF3. The transverse modulus is close to the average of and .
False — uses the inverse (series) rule and is dominated by the weakest link (the matrix), so sits near , not near the average.
TF4. Because , the minor Poisson ratio is smaller than the major .
True — since , the factor , so ; both describe the same physical coupling, just referenced to different loading directions.
TF5. is exactly equal to .
False — is slightly larger than because Poisson coupling stiffens the constrained response, though the difference is usually under 1%.
TF6. Adding more fiber () always makes a better composite.
False — beyond ~0.65 there isn't enough matrix to wet and support the fibers, so voids form, load transfer fails, and strength actually drops.
TF7. A single unidirectional ply loaded off-axis develops shear even under pure tension.
True — once fibers sit at an angle , a tensile pull resolves into components along and across the fibers, and the transformed stiffness gains extension–shear coupling terms.
TF8. Fatigue resistance is a selling point because composites, unlike metals, tend not to propagate cracks the same way.
True — there is no single crystal-lattice crack marching through; damage spreads as distributed fiber/matrix micro-events, giving much flatter fatigue curves (relevant to launch load cycling).
Spot the error
SE1. "In the series (transverse) model I set because both phases stretch the same."
Wrong — series loading means equal stress, not equal strain; the softer matrix strains more (), and the total strain is the volume-weighted sum of the two.
SE2. ", so with the fiber dominates ."
Wrong — in an inverse sum the largest denominator contributes the smallest term, so the tiny term (small ) dominates ; the matrix, not the fiber, controls transverse stiffness.
SE3. "The stiffness matrix has a nonzero term coupling normal stress to shear."
Wrong — in the material axes the ply is orthotropic, so ; those coupling terms only appear in the transformed after rotating to an angled layup.
SE4. "To go from compliance to stiffness I just take reciprocals of each entry."
Wrong — is a full matrix inverse, not entry-by-entry; that is exactly why the shared determinant appears in every term.
SE5. " and are independent material constants I must measure separately."
Wrong — they are linked by the symmetry relation , so only one is independent; measuring both is a redundancy check, not two data points.
SE6. "A quasi-isotropic laminate is isotropic, so I can use isotropic hand-book formulas everywhere."
Wrong — "quasi-isotropic" means only the in-plane extensional stiffness is direction-independent; bending, interlaminar shear, and through-thickness behaviour remain strongly anisotropic.
SE7. "I used the parallel Rule of Mixtures for shear modulus ."
Wrong — in-plane shear (, resistance to sliding) passes load through the matrix like the transverse case, so it follows the inverse (series) rule, matching 's form, not 's.
Why questions
WHY1. Why does the matrix, despite being weak, matter at all?
Because it transfers load between fibers, holds their spacing/alignment, and blunts crack tips — without it a bare fiber bundle would buckle in compression and unravel under any off-axis load.
WHY2. Why do we invert compliance to get stiffness rather than working with compliance directly?
Because laminate assembly and FEA (see 5.3-finite-element-analysis) add up stiffnesses of stacked plies to build the laminate response; you cannot simply add compliances of layers that share the same strain.
WHY3. Why does low thermal expansion make composites prized for optics and antennas?
Because near-zero (even negative) fiber expansion can be tuned to hold mirror or antenna geometry stable across the orbital hot/cold swings handled in 4.2-thermal-design, where a metal would defocus.
WHY4. Why does specific stiffness (), not raw stiffness, drive material selection for spacecraft?
Because every kilogram costs launch mass (2.4-mass-budgets); a composite at 60% of aluminium's stiffness but 60% of its density still wins on stiffness-per-kilogram, which is what sets structural frequency and mass.
WHY5. Why must ply orientation be tracked, not just ply count?
Because each ply only resists load along its fibers; four 0° plies give huge axial stiffness but almost nothing transversely, whereas a balanced 0/±45/90 stack spreads capability where the loads actually point.
WHY6. Why is the term always positive and less than one for a real material?
Because thermodynamic stability requires the strain energy to be positive, which forces ; a value would imply the material releases energy when loaded — physically impossible.
WHY7. Why compare a composite to aluminium rather than to steel in trade studies?
Because aluminium is the incumbent aerospace baseline; the meaningful engineering question during material selection is "does the composite beat the metal we'd otherwise fly?"
WHY8. Why do sandwich structures pair thin composite faces with a light core?
Because separating the stiff faces (see 3.6.16-sandwich-structures) multiplies bending stiffness for almost no mass, letting a strong-but-thin laminate act like a thick beam.
Edge cases
EC1. What is in the limit (all matrix)?
The inverse rule collapses to , so — with no fibers the composite is just the matrix, exactly as it must be.
EC2. What happens to as (theoretical all-fiber)?
; the parallel rule smoothly recovers the pure-fiber modulus, confirming the formula's end behaviour even though this is unmanufacturable.
EC3. At , what does the transformation matrix reduce to?
The identity matrix, so — a ply aligned with the loading axis needs no transformation, which is the sanity check every rotation formula must pass.
EC4. At , how do the roles of and swap?
The fibers now run across the load, so the effective axial stiffness becomes (matrix-dominated) — pulling a "90° ply" is really loading it transversely.
EC5. If a laminate is loaded exactly along one fiber direction but has ±45° plies too, do those angled plies carry zero load?
No — because all plies share the same in-plane strain, the ±45° plies still stretch and carry stress (and shear), just less efficiently than the aligned plies.
EC6. What if (fiber and matrix equally stiff)?
Both rules give ; with no stiffness contrast the material becomes isotropic and the whole anisotropy story vanishes — the contrast is the composite.
EC7. Is there any orientation where an off-axis ply feels no extension–shear coupling?
Yes — only at and ; at those angles , so the coupling terms of vanish and pure tension gives pure extension.
EC8. What does approach as (imaginary infinitely soft matrix)?
; a vanishingly stiff transverse direction cannot pull the stiff direction inward, so the minor Poisson coupling disappears.