3.2.18 · D5Orbital Mechanics & Astrodynamics

Question bank — Orbit determination — Gauss's method, Gibbs method

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Before the traps, a one-line refresher on the words we abuse below:


True or false — justify

Coplanarity of is a necessary condition for a single Keplerian orbit to fit them.
True. A two-body orbit lives entirely in one plane (because is constant), so three points off that plane can never lie on one orbit — no velocity choice can fix it.
Gibbs's method needs the observation times .
False. Gibbs is pure geometry: three coplanar points already overdetermine the conic's shape, so velocity comes out without any clock. Times only enter later if you want the true anomaly or epoch.
Gauss's method also works with zero time information.
False. Gauss propagates with the series which depend on ; without the times the Lagrange coefficients are undefined and the whole slant-range solve collapses.
The eighth-degree polynomial in Gauss can have several positive real roots.
True. Algebra doesn't know about physics, so multiple positive roots can appear; you keep only the one giving above Earth's surface with all slant ranges .
If the three position vectors are exactly coplanar, the Gibbs velocity is unique.
True. Coplanarity plus lying on one conic pins a single tangent direction and speed at the middle point, so is uniquely determined by .
The vector in Gibbs encodes the size of the orbit.
False. points toward perigee (it's tied to the eccentricity vector ); the size/scale comes from and .
You can run Gibbs on and any midpoint you invent.
False. The three vectors must be genuine points of the same real orbit; a fabricated midpoint won't be coplanar-and-conic-consistent, so will not describe a valid orbit.
Angular momentum magnitude satisfies with .
True. This identity is exactly why the Gibbs prefactor rearranges to ; is the semi-latus rectum recovered from the helper vectors.

Spot the error

"For Gibbs I'll compute the velocity at since it's the first point."
Error: the Gibbs formula is derived at the middle point. The symmetric sums are centred so only emerges clean; using gives a wrong number.
"The coplanarity check should give exactly , so my data with a deviation is broken."
Error: real measurements carry noise, so a small nonzero value (rule of thumb under ) is acceptable. Demanding exact zero throws out perfectly usable data.
", and since is unknown I can just set it to zero to start."
Error: puts the satellite at the observer, which is nonsense. Gauss instead solves the polynomial for first, then back-substitutes to get the — it never assumes them.
"I truncated the series to two terms and got an answer, so I'm done."
Error: the truncated series is only a short-arc approximation. You must iterate with the exact Lagrange coefficients until converges, especially for wide-angle arcs.
" is a vector, so uses those vectors directly."
Error: uses the magnitudes and . Dividing the vectors component-wise is meaningless; and are actually parallel (both normal to the orbit plane).
"Gauss outputs the velocity directly from the three angles."
Error: Gauss outputs the three position vectors (via slant ranges). Getting the velocity still requires handing those positions to Gibbs (or a Lagrange-coefficient step).
"Since and are constant, any two points fix the orbit."
Error: two points and a focus leave a one-parameter family of conics; you need a third constraint (a third point in Gibbs, or times in Gauss) to pin the unique orbit.

Why questions

Why does Gibbs use cross products everywhere instead of, say, dot products?
Cross products build vectors normal to the orbit plane, which is exactly where lives; the symmetric cross-product sums let the unknown true anomalies cancel, leaving clean geometry.
Why is the middle observation () special in both methods?
It's the expansion centre. Gauss Taylor-expands about , and Gibbs's symmetric sums are balanced around point 2, so the algebra is cleanest and errors smallest there.
Why does angle-only data (Gauss) need three observations rather than two?
Each observation supplies two angles but hides one distance. Two observations give four knowns for six unknowns plus three ranges; the third observation plus coplanarity closes the count and lets the polynomial in be formed.
Why do we conserve and specifically, out of all quantities?
fixes the orbit plane and its size (); fixes the shape and orientation inside that plane. Together they carry every geometric element, so reconstructing them is reconstructing the orbit.
Why is Gibbs called "time-free" when orbits are all about Kepler's time laws?
Kepler's time law (equal areas in equal times) is separate from the orbit's shape. Three points already lock the shape; you only invoke time when you later want where on the orbit at a given instant.
Why must the eighth-degree polynomial root give ?
A negative slant range would place the target behind the observer along the line of sight — physically impossible, since you actually saw it in front. Only positive ranges correspond to a real sighting.
Why does a longer observation arc make the series worse?
The series is a Taylor truncation in ; larger means the dropped higher-order terms grow, so the approximation degrades and iteration (or exact coefficients) becomes essential.

Edge cases

What if the three position vectors are (numerically) collinear, not just coplanar?
Collinear points give a vanishing and , so blows up — the geometry is degenerate and no unique orbit can be extracted. You need genuinely spread-out points.
What happens to Gauss if the three sightings are nearly identical in direction (tiny arc)?
The coefficients become ill-conditioned: small angle differences get divided into large ranges, amplifying measurement noise wildly. Very short arcs give unreliable even though the math formally runs.
What if two of the three times coincide ()?
The relations degenerate because two observations carry the same propagated ; the linear system for the ranges loses rank and Gauss cannot separate the points. Distinct times are required.
What if the orbit is a parabola or hyperbola ()?
Gibbs still works — it uses the conic equation which covers all conics, and , stay valid. The method never assumed a bound ellipse.
What if the coplanarity test returns a large angle, say ?
Either the data is badly noisy or the three sightings aren't of the same object. Proceeding gives a meaningless "orbit"; you should reject or re-observe rather than force Gibbs through.
What if from Gauss comes out below Earth's radius?
That root is unphysical (the satellite would be underground) and must be discarded, even though it solves the polynomial. Pick the other positive real root that clears the surface.

Recall One-line self-test

Name the single output of the Gauss polynomial and the single output of Gibbs. ::: The polynomial yields (hence the slant ranges and positions); Gibbs yields (the missing velocity that completes the state vector).