3.2.14 · D1Orbital Mechanics & Astrodynamics

Foundations — Kepler's equation M = E − e·sin E — derivation, eccentric anomaly

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This page assumes you know nothing about the parent note's symbols. We build each one from the ground up, in an order where each idea leans only on the ones before it. By the end you should be able to read the sentence " and " and feel that every letter has already earned its place.


0. The stage: what an ellipse even is

Before any angle, we need the shape the planet travels on.

Figure — Kepler's equation M = E − e·sin E — derivation, eccentric anomaly

Why we need it: the whole topic is "planet on an ellipse", so (its size) and (its squashedness) appear in every formula.


1. The centre , the focus , and eccentricity

An ellipse has a centre (the middle, where the two axes cross). But it also has two special inner points called foci (singular: focus). For a planet, the Sun sits at one focus, which we call not at the centre.

Figure — Kepler's equation M = E − e·sin E — derivation, eccentric anomaly

Two facts about that the parent note uses constantly:

Why we need it: is the exact offset that later produces the correction term, and is the algebra key used to simplify the radius formula.

Recall Where does

come from? It is the defining relation of ellipse geometry (built from the distances to the two foci). We treat it here as a given tool; see Eccentricity and ellipse geometry (a, b, ae, b²=a²(1−e²)) for the full construction.


2. Angle in radians, and why degrees are banned

An angle measures "how much turn". You may know degrees (a full circle ). Physics here uses radians instead.

Why radians and not degrees? Every formula in this topic came from areas and arcs of circles, where the "arc = radius × angle" rule holds only in radians. A circular sector of angle has area — again only in radians. Plug degrees into and you get nonsense.


3. The trig tools: , , and the parametric circle

A point on a circle of radius , at angle measured from the rightward axis, has coordinates

Figure — Kepler's equation M = E − e·sin E — derivation, eccentric anomaly

The identity we lean on: (Pythagoras on that right triangle). It is what collapses the messy radius algebra in Derivation 2 down to .

Now apply the squash. On the auxiliary circle (radius ) the helper point is . Squash vertically by and the planet on the ellipse sits at This is where the eccentric anomaly is about to enter — as the angle feeding these cosines and sines.


4. Time symbols: , ,

These are the plainest symbols, but the topic is meaningless without them.

Perihelion itself is a place: the point of the orbit nearest the Sun (distance ). Its opposite, farthest point, is aphelion (distance ). We label the perihelion direction as the axis from which all angles are counted.

Why we need them: they turn a time question into an angle question in the very next step.


5. Mean motion and the mean anomaly

Here is the "steady imaginary clock" from the core idea.

Why we need it: it is the input we always know (we know the time), and Kepler's equation's whole job is to convert this honest clock reading into the real geometry.


6. Eccentric anomaly — the geometric helper angle

This is the star of the topic, and the last symbol we build.

Figure — Kepler's equation M = E − e·sin E — derivation, eccentric anomaly

Why we need it: is the bridge symbol. Time gives us ; geometry gives us position via ; Kepler's equation welds the two together.


7. True anomaly — the honest, real angle

For completeness (the parent uses it once): the true anomaly (Greek "nu") is the actual angle of the planet as seen from the Sun at focus , measured from perihelion. It is what you would literally point a telescope along. It relates to by See True anomaly ν and the orbit equation r = a(1−e²)/(1+e cos ν) for its own story. For now: (clock) → (centre helper) → (real angle) is the full chain.


8. One transcendental fact you must accept

has both outside () and inside a . You cannot rearrange it into " (formula in )". Equations like this are called transcendental; you solve them by repeated guessing that homes in on the answer (see Numerical root-finding — Newton–Raphson).


Prerequisite map

Ellipse a and b squashed circle

Eccentricity e and focus offset ae

Squash factor b over a

Radians arc over radius

Sector area half R squared theta

sin and cos on a circle

Position x equals a cos E y equals b sin E

Time t tp and period T

Mean motion n equals 2pi over T

Mean anomaly M equals n times t minus tp

Eccentric anomaly E from centre

Kepler equation M equals E minus e sin E

True anomaly nu real angle from Sun

Solve by Newton Raphson


Equipment checklist

Test yourself — read the prompt, answer, then reveal.

What are and on an ellipse?
The semi-major axis (half the long diameter) and semi-minor axis (half the short diameter).
What does eccentricity measure, and its range for orbits?
How stretched the ellipse is; for a bound orbit ( is a circle).
How far is the Sun (focus ) from the centre ?
A distance along the major axis.
State the link between , , and .
.
Define one radian.
The angle whose arc length equals the radius; a full circle is radians.
Why must the angles in be in radians?
The formula came from arc/area relations that only hold in radians (arc , sector area ).
Give the coordinates of a point at angle on a circle of radius .
.
Where does the planet sit in terms of ?
(circle point squashed by ).
What is the mean motion ?
The steady angular rate of a fictitious uniform body.
Define the mean anomaly .
The steady-clock angle ; a rescaled stopwatch, not the real position.
From where and how is the eccentric anomaly measured?
From the centre , on the auxiliary circle of radius , in radians.
What is the true anomaly ?
The planet's real angular position seen from the focus (Sun), measured from perihelion.
Why can't be solved algebraically?
It is transcendental — appears both outside and inside a sine, so it must be solved by iteration.